QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#506171 | #6422. Evil Coordinate | Abcl | WA | 19ms | 3820kb | C++14 | 3.3kb | 2024-08-05 15:47:44 | 2024-08-05 15:47:44 |
Judging History
answer
#include <bits/stdc++.h>
#define int long long
using namespace std;
vector<char> ans;
int end_x,end_y;
unordered_map<char,int> mp;
int f=0;
int mx,my;
void solve() {
cin>>mx>>my;
string str;
cin>>str;
f=0;ans.clear();
if(mx==0&&my==0) {
cout<<"Impossible"<<endl;
return;
}
mp.clear();
for(int i=0; i<str.length(); i++) {
mp[str[i]]++;//统计各个方向移动的指令数目
}
end_x=mp['R']-mp['L'];//不要取绝对值就是算最后的坐标
end_y=mp['U']-mp['D'];
if(mx==end_x&&my==end_y){
cout<<"Impossible"<<endl;
return;
}
if(mx==0&&my>0&&end_y>my){
cout<<"Impossible"<<endl;
return;
}
else if(mx==0&&my<0&&end_y<my){
cout<<"Impossible"<<endl;
return;
}
if(my==0&&mx>0&&end_x>mx){
cout<<"Impossible"<<endl;
return;
}
else if(my==0&&mx<0&&end_x<mx){
cout<<"Impossible"<<endl;
return;
}
if(end_x!=mx&&end_y!=my) { //如果两个最终的结果都不跟坐标相同
int nowx=0,nowy=0;
while(mp['L']+mp['R']+mp['U']+mp['D']){
if((nowx+1!=mx||nowy!=my)&&mp['R']){
mp['R']--;nowx++;
cout<<'R';
}
else if((nowx-1!=mx||nowy!=my)&&mp['L']){
mp['L']--;nowx--;
cout<<'L';
}
else if((nowx!=mx||nowy+1!=my)&&mp['U']){
mp['U']--;nowy++;
cout<<'U';
}
else if((nowx!=mx||nowy-1!=my)&&mp['D']){
mp['D']--;nowy--;
cout<<'D';
}
else break;
}
for(int i=0; i<mp['L']; i++) {
cout<<'L';
}
for(int i=0; i<mp['R']; i++) {
cout<<'R';
}
for(int i=0; i<mp['U']; i++) {
cout<<'U';
}
for(int i=0; i<mp['D']; i++) {
cout<<'D';
}
cout<<endl;
return;
}
else if(end_x!=mx&&end_y==my) {//若x不相同,但是y的坐标相同的话
int nowx=0,nowy=0;
while(mp['L']+mp['R']+mp['U']+mp['D']){
if((nowx+1!=mx||nowy!=my)&&mp['R']){
mp['R']--;nowx++;
cout<<'R';
}
else if((nowx-1!=mx||nowy!=my)&&mp['L']){
mp['L']--;nowx--;
cout<<'L';
}
else if((nowx!=mx||nowy+1!=my)&&mp['U']){
mp['U']--;nowy++;
cout<<'U';
}
else if((nowx!=mx||nowy-1!=my)&&mp['D']){
mp['D']--;nowy--;
cout<<'D';
}
else break;
}for(int i=0; i<mp['L']; i++) {
cout<<'L';
}
for(int i=0; i<mp['R']; i++) {
cout<<'R';
}
for(int i=0; i<mp['U']; i++) {
cout<<'U';
}
for(int i=0; i<mp['D']; i++) {
cout<<'D';
}
cout<<endl;
return;
}
else if(end_y!=my&&end_x==mx) { //如果y最后不相同但是x相同,
int nowx=0,nowy=0;
while(mp['L']+mp['R']+mp['U']+mp['D']){
if((nowx+1!=mx||nowy!=my)&&mp['R']){
mp['R']--;nowx++;
cout<<'R';
}
else if((nowx-1!=mx||nowy!=my)&&mp['L']){
mp['L']--;nowx--;
cout<<'L';
}
else if((nowx!=mx||nowy+1!=my)&&mp['U']){
mp['U']--;nowy++;
cout<<'U';
}
else if((nowx!=mx||nowy-1!=my)&&mp['D']){
mp['D']--;nowy--;
cout<<'D';
}
else break;
}
for(int i=0; i<mp['L']; i++) {
cout<<'L';
}
for(int i=0; i<mp['R']; i++) {
cout<<'R';
}
for(int i=0; i<mp['U']; i++) {
cout<<'U';
}
for(int i=0; i<mp['D']; i++) {
cout<<'D';
}
cout<<endl;
return;
}
}
signed main() {
ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
int t;
cin>>t;
while(t--) {
solve();
}
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3608kb
input:
5 1 1 RURULLD 0 5 UUU 0 3 UUU 0 2 UUU 0 0 UUU
output:
RRLLUUD UUU Impossible Impossible Impossible
result:
ok 5 cases
Test #2:
score: -100
Wrong Answer
time: 19ms
memory: 3820kb
input:
11109 6 0 RUDUDR 2 0 URU 0 0 UDRU 0 0 R -1 1 LDUUDDRUUL -1 5 RRUUUDUUU -8 4 RRDRLDR 2 0 UD 0 0 UUDD 3 -2 LDDLLLRR 3 -2 LDRURLDD 1 0 RRL -1 0 DUDDLLRDU -4 0 LL -1 -1 DLRLDLUDUR 1 4 URDULUR 0 0 DDUUDUDDDD 0 2 UU 1 0 RRULD 0 -2 LDLRLLDRRL 0 1 RLRLLRLUR -3 0 RL 0 0 D 0 0 L 0 0 DDLRRUDRUD 0 0 DULU 2 0 RR...
output:
RRUUDD RUU Impossible Impossible Impossible RRUUUUUUD RRRRLDD UD Impossible RRLLLLDD RRLLUDDD Impossible RLULUDDDD LL Impossible RRLUUUD Impossible Impossible Impossible RRRLLLLLDD Impossible RL Impossible Impossible Impossible Impossible Impossible RRRRRLLLUU LLLUD Impossible LUUUDDD RRUUDD Impossi...
result:
wrong answer case 13, participant's output goes through forbidden coordinate