#include<bits/stdc++.h>
using namespace std;

int main()
{
    int t;
    cin >> t;
    while (t--) {
        long double n, m, p;
        cin >> n >> m >> p;
        p /= 10000;
        long double mi = 1e9;
        for (int i = 1; i <= 10000; i++) {
            long double d = (n * i + m) / (1 - pow(1 - p, i));
            mi = min(mi, d);

        }
        printf("%.10lf\n", mi);
    }
    return 0;
}