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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#506101 | #6422. Evil Coordinate | Abcl | WA | 14ms | 3760kb | C++14 | 2.6kb | 2024-08-05 15:17:22 | 2024-08-05 15:17:23 |
Judging History
answer
#include <bits/stdc++.h>
#define int long long
using namespace std;
void solve() {
int mx,my;
cin>>mx>>my;
string str;
cin>>str;
if(mx==0&&my==0) {
cout<<"Impossible"<<endl;
return;
}
unordered_map<char,int> mp;
for(int i=0; i<str.length(); i++) {
mp[str[i]]++;//统计各个方向移动的指令数目
}
int end_x=mp['R']-mp['L'];//不要取绝对值就是算最后的坐标
int end_y=mp['U']-mp['D'];
if(mx==end_x&&my==end_y){
cout<<"Impossible"<<endl;
return;
}
if(end_x!=mx&&end_y!=my) { //如果两个最终的结果都不跟坐标相同
int nowx=0,nowy=0;
while(mp['L']+mp['R']+mp['U']+mp['D']){
if(nowx+1!=mx&&nowy!=my&&mp['R']){
mp['R']--;nowx++;
cout<<'R';
}
else if(nowx-1!=mx&&nowy!=my&&mp['L']){
mp['L']--;nowx--;
cout<<'L';
}
else if(nowx!=mx&&nowy+1!=my&&mp['U']){
mp['U']--;nowy++;
cout<<'U';
}
else if(nowx!=mx&&nowy-1!=my&&mp['D']){
mp['D']--;nowy--;
cout<<'D';
}
else break;
}
for(int i=0; i<mp['L']; i++) {
cout<<'L';
}
for(int i=0; i<mp['R']; i++) {
cout<<'R';
}
for(int i=0; i<mp['U']; i++) {
cout<<'U';
}
for(int i=0; i<mp['D']; i++) {
cout<<'D';
}
cout<<endl;
return;
}
else if(end_x!=mx&&end_y==my) {//若x不相同,但是y的坐标相同的话
if(mx>0&&end_x>mx){
cout<<"Impossible"<<endl;
return;
}
else if(mx<0&&end_x<mx){
cout<<"Impossible"<<endl;
return;
}
for(int i=1;i<=min(mp['L'],mp['R']); i++) {
cout<<'L'<<'R';
}
for(int i=min(mp['L'],mp['R'])+1; i<=max(mp['L'],mp['R']); i++) {
if(mp['L']>mp['R'])
cout<<'L';
else cout<<'R';
}
for(int i=0; i<mp['U']; i++) {
cout<<'U';
}
for(int i=0; i<mp['D']; i++) {
cout<<'D';
}
cout<<endl;
return;
}
else if(end_y!=my&&end_x==mx) { //如果y最后不相同但是x相同,
if(my>0&&end_y>my){
cout<<"Impossible"<<endl;
return;
}
else if(my<0&&end_y<my){
cout<<"Impossible"<<endl;
return;
}
for(int i=1; i<=min(mp['U'],mp['D']); i++) {
cout<<'U'<<'D';
}
for(int i=min(mp['U'],mp['D'])+1;i<=max(mp['U'],mp['D']); i++){
if(mp['U']>mp['D'])
cout<<'U';
else cout<<'D';
}
for(int i=0; i<mp['L']; i++) {
cout<<'L';
}
for(int i=0; i<mp['R']; i++) {
cout<<'R';
}
cout<<endl;
return;
}
}
signed main() {
ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
int t;
cin>>t;
while(t--) {
solve();
}
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3492kb
input:
5 1 1 RURULLD 0 5 UUU 0 3 UUU 0 2 UUU 0 0 UUU
output:
LRLRUUD UUU Impossible Impossible Impossible
result:
ok 5 cases
Test #2:
score: -100
Wrong Answer
time: 14ms
memory: 3760kb
input:
11109 6 0 RUDUDR 2 0 URU 0 0 UDRU 0 0 R -1 1 LDUUDDRUUL -1 5 RRUUUDUUU -8 4 RRDRLDR 2 0 UD 0 0 UUDD 3 -2 LDDLLLRR 3 -2 LDRURLDD 1 0 RRL -1 0 DUDDLLRDU -4 0 LL -1 -1 DLRLDLUDUR 1 4 URDULUR 0 0 DDUUDUDDDD 0 2 UU 1 0 RRULD 0 -2 LDLRLLDRRL 0 1 RLRLLRLUR -3 0 RL 0 0 D 0 0 L 0 0 DDLRRUDRUD 0 0 DULU 2 0 RR...
output:
RRUUDD URU Impossible Impossible Impossible RRUUUUUUD RRRRLDD UD Impossible LRLRLLDD LRLRUDDD Impossible UDUDDDLLR LL Impossible UDUULRR Impossible Impossible Impossible LRLRLRLLDD Impossible LR Impossible Impossible Impossible Impossible Impossible LRLRLRRRUU LLLUD Impossible LUUUDDD UDUDRR Impossi...
result:
wrong answer case 165, participant's output goes through forbidden coordinate