QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#505962 | #9110. Zayin and Tree | WendyChen | AC ✓ | 149ms | 24108kb | C++20 | 1.0kb | 2024-08-05 14:13:58 | 2024-08-05 14:13:58 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define endl '\n'
#define base 191
#define mod 1145141
#define inf 0x3f3f3f3f3f3f3f3f
const int N = 1e7 + 10;
int n;
int ans;
vector<int>edge[1000010];
int a[1000010];
int dep[N], min1[N], min2[N];
void dfs(int u, int fa) {
min1[u] = a[u] + dep[u];
min2[u] = -a[u] + dep[u];
for (auto it : edge[u]) {
if (it == fa) {
continue;
}
dep[it] = dep[u] + 1;
dfs(it, u);
min1[u] = min(min1[u], min1[it]);
min2[u] = min(min2[u], min2[it]);
}
ans = min(ans, min1[u] + min2[u] - 2 * dep[u] + 1);
}
void solve() {
cin >> n;
ans = inf;
int ma = 1;
for (int i = 1; i <= n; ++i) {
cin >> a[i];
edge[i].clear();
}
for (int i = 1; i <= n - 1; ++i) {
int u, v;
cin >> u >> v;
edge[u].push_back(v);
edge[v].push_back(u);
}
dfs(1, 0);
cout << ans << endl;
}
signed main() {
ios::sync_with_stdio(false), cin.tie(0), cout.tie(0);
int T = 1;
cin >> T;
while (T--) {
solve();
}
}
/*2
3
1 1
1 3 2
3
1 2
1 3 2*/
詳細信息
Test #1:
score: 100
Accepted
time: 149ms
memory: 24108kb
input:
3009 5 4 5 3 4 2 1 2 2 3 3 4 3 5 5 4 4 1 1 2 1 2 2 3 3 4 3 5 10 5 8 1 0 8 7 5 2 0 4 2 4 3 8 3 9 1 2 1 3 3 6 4 5 5 7 6 10 10 6 8 8 4 8 0 6 6 0 2 7 10 1 7 2 9 2 3 3 4 1 5 1 6 6 8 1 2 10 9 0 4 0 4 6 0 2 0 0 1 5 1 3 1 7 2 6 1 2 1 9 1 4 5 8 7 10 10 8 8 1 2 7 4 8 6 0 8 1 6 1 7 1 5 7 9 1 3 1 2 2 10 3 4 1 8...
output:
0 -1 -6 -6 -7 -6 -7 -4 -3 -7 -5 -6 -5 -4 -6 -3 -4 -7 -4 -4 -6 -6 -6 -5 -4 -5 -6 -6 -7 -7 -5 -7 -6 -6 -7 -6 -5 -5 -4 -6 -6 -5 -6 -6 -6 -6 -3 -6 -3 -6 -4 -6 -7 -6 -7 -6 -6 -5 -7 -6 -4 -7 -3 -5 -5 -6 -4 -5 -7 -6 -5 -5 -4 -3 -5 -3 -4 -2 -6 -5 -7 -4 -5 -5 -7 -7 -4 -6 -5 -4 -6 -5 -5 -6 -3 -6 -7 -7 -7 -6 -...
result:
ok 3009 lines