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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#504683 | #9108. Zayin and Obstacles | IllusionaryDominance# | AC ✓ | 96ms | 13228kb | C++20 | 2.4kb | 2024-08-04 14:45:48 | 2024-08-04 14:45:49 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
const int MAX_N = 100 + 5;
const int INF32 = 0x3f3f3f3f;
const int dx[] = {1, -1, 0, 0, 0, 0}, dy[] = {0, 0, 1, -1, 0, 0}, dz[] = {0, 0, 0, 0, 1, -1};
int N, M, sum[MAX_N][MAX_N][MAX_N], dis[MAX_N][MAX_N][MAX_N];
struct Node{
int x, y, z;
Node (int a = 0, int b = 0, int c = 0) : x(a), y(b), z(c) {}
};
void solve() {
memset(sum, 0, sizeof sum);
memset(dis, 0x3f, sizeof dis);
scanf("%d%d", &N, &M);
for (int i = 1; i <= M; i ++) {
int a, b, c, d, e, f;
scanf("%d%d%d%d%d%d", &a, &b, &c, &d, &e, &f);
d ++; e ++; f ++;
sum[a][b][c] ++;
sum[d][b][c] --;
sum[a][e][c] --;
sum[a][b][f] --;
sum[a][e][f] ++;
sum[d][b][f] ++;
sum[d][e][c] ++;
sum[d][e][f] --;
}
for (int i = 1; i <= N; i ++) {
for (int j = 1; j <= N; j ++) {
for (int k = 1; k <= N; k ++) {
sum[i][j][k] += sum[i][j][k - 1];
}
}
}
for (int i = 1; i <= N; i ++) {
for (int k = 1; k <= N; k ++) {
for (int j = 1; j <= N; j ++) {
sum[i][j][k] += sum[i][j - 1][k];
}
}
}
for (int j = 1; j <= N; j ++) {
for (int k = 1; k <= N; k ++) {
for (int i = 1; i <= N; i ++) {
sum[i][j][k] += sum[i - 1][j][k];
}
}
}
int xs, ys, zs, xt, yt, zt;
scanf("%d%d%d%d%d%d", &xs, &ys, &zs, &xt, &yt, &zt);
if (sum[xs][ys][zs] || sum[xt][yt][zt]) {
puts("-1"); return ;
}
queue <Node> q;
q.push(Node(xs, ys, zs));
dis[xs][ys][zs] = 0;
while (!q.empty()) {
auto [x, y, z] = q.front();
q.pop();
if (x == xt && y == yt && z == zt) break;
int nd = dis[x][y][z] + 1;
for (int k = 0; k < 6; k ++) {
int nx = x + dx[k], ny = y + dy[k], nz = z + dz[k];
if (nx > 0 && nx <= N && ny > 0 && ny <= N && nz > 0 && nz <= N && !sum[nx][ny][nz] && dis[nx][ny][nz] > nd) {
dis[nx][ny][nz] = nd; q.push(Node(nx, ny, nz));
}
}
}
if (dis[xt][yt][zt] < INF32) printf("%d\n", dis[xt][yt][zt]);
else puts("-1");
}
int main() {
int T;
scanf("%d", &T);
while (T --) solve();
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 12896kb
input:
3 3 0 1 1 1 3 3 3 3 1 2 1 1 2 3 3 1 1 1 3 3 3 3 3 2 1 1 2 2 3 1 1 2 2 3 2 1 2 2 3 3 2 1 1 1 1 1 3
output:
6 -1 14
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 19ms
memory: 12896kb
input:
5 19 27 2 1 1 2 18 19 4 2 1 4 19 19 6 1 1 6 18 19 8 2 1 8 19 19 10 1 1 10 18 19 12 2 1 12 19 19 14 1 1 14 18 19 16 2 1 16 19 19 18 1 1 18 18 19 1 1 2 18 19 2 2 1 4 19 19 4 1 1 6 18 19 6 2 1 8 19 19 8 1 1 10 18 19 10 2 1 12 19 19 12 1 1 14 18 19 14 2 1 16 19 19 16 1 1 18 18 19 18 1 2 2 19 19 2 1 2 4 ...
output:
1998 15998 53998 127998 249998
result:
ok 5 lines
Test #3:
score: 0
Accepted
time: 34ms
memory: 12812kb
input:
5 99 147 2 1 1 2 98 99 4 2 1 4 99 99 6 1 1 6 98 99 8 2 1 8 99 99 10 1 1 10 98 99 12 2 1 12 99 99 14 1 1 14 98 99 16 2 1 16 99 99 18 1 1 18 98 99 20 2 1 20 99 99 22 1 1 22 98 99 24 2 1 24 99 99 26 1 1 26 98 99 28 2 1 28 99 99 30 1 1 30 98 99 32 2 1 32 99 99 34 1 1 34 98 99 36 2 1 36 99 99 38 1 1 38 9...
output:
132878 2596 227782 37198 90672
result:
ok 5 lines
Test #4:
score: 0
Accepted
time: 18ms
memory: 13108kb
input:
5 99 1000 2 1 1 2 98 99 4 2 1 4 99 99 6 1 1 6 98 99 8 2 1 8 99 99 10 1 1 10 98 99 12 2 1 12 99 99 14 1 1 14 98 99 16 2 1 16 99 99 18 1 1 18 98 99 20 2 1 20 99 99 22 1 1 22 98 99 24 2 1 24 99 99 26 1 1 26 98 99 28 2 1 28 99 99 30 1 1 30 98 99 32 2 1 32 99 99 34 1 1 34 98 99 36 2 1 36 99 99 38 1 1 38 ...
output:
4998 4998 4998 4998 4998
result:
ok 5 lines
Test #5:
score: 0
Accepted
time: 27ms
memory: 12832kb
input:
5 19 1000 2 1 1 2 18 19 4 2 1 4 19 19 6 1 1 6 18 19 8 2 1 8 19 19 10 1 1 10 18 19 12 2 1 12 19 19 14 1 1 14 18 19 16 2 1 16 19 19 18 1 1 18 18 19 4 13 10 4 19 12 6 5 5 6 6 18 6 16 4 6 18 11 8 6 10 8 17 19 14 10 7 14 17 12 2 4 4 2 5 15 4 5 10 4 7 17 12 1 2 12 2 9 12 8 10 12 18 15 16 19 2 16 19 8 8 1 ...
output:
-1 798 1906 3198 4998
result:
ok 5 lines
Test #6:
score: 0
Accepted
time: 96ms
memory: 13228kb
input:
5 100 0 92 81 37 11 85 14 100 0 16 48 91 61 65 58 100 0 87 25 52 83 7 45 100 0 80 95 16 62 5 80 100 0 33 33 50 48 82 3
output:
108 95 29 172 111
result:
ok 5 lines