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ID	题目	提交者	结果	用时	内存	语言	文件大小	提交时间	测评时间
#499669	#6723. Grid with Arrows	Dawnkk03	ML	0ms	3576kb	C++23	3.2kb	2024-07-31 16:46:41	2024-07-31 16:46:43

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[2024-07-31 16:46:43]
评测

测评结果：ML
用时：0ms
内存：3576kb

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[2024-07-31 16:46:41]
提交

answer

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

struct Node
{
    int dis;
    char arrow;
    Node* parent = nullptr;

    Node* find(Node* node)
    {
        if (node->parent == nullptr)
            return node;
        return node->parent = find(node->parent);
    }
    void merge(Node* node)
    {
        Node* a = find(this);
        Node* b = find(node);
        if (a != b)
        {
            b->parent = a;
        }
    }
};

void solve()
{
    int n,m;
    cin>>n>>m;
    vector<vector<Node>> Map(n+1, vector<Node>(m+1));
    int cnt = 0;//记录环的数量
    for(int i = 1;i <= n;i++)
    {
        for(int j = 1;j <= m;j++)
        {
            cin>>Map[i][j].arrow;
        }
    }
    for(int i = 1;i <= n;i++)
    {
        for(int j = 1;j <= m;j++)
        {
            cin>>Map[i][j].dis;
        }
    }
    for(int i = 1;i <= n;i++)
    {
        for(int j = 1;j <= m;j++)
        {
            if(Map[i][j].arrow == 'd')
            {
                if(i + 1 > n)
                {
                    Map[i][j].parent = Map[i][j].find(&Map[i][j]);
                    cnt++;
                }
                else if(Map[i+1][j].find(&Map[i+1][j]) == Map[i][j].find(&Map[i][j]))
                {
                    cnt++;
                }
                else
                {
                    Map[i+1][j].merge(&Map[i][j]);
                }
            }
            else if(Map[i][j].arrow == 'u')
            {
                if(i - 1 < 1)
                {
                    Map[i][j].parent = Map[i][j].find(&Map[i][j]);
                    cnt++;
                }
                else if(Map[i-1][j].find(&Map[i-1][j]) == Map[i][j].find(&Map[i][j]))
                {
                    cnt++;
                }
                else
                {
                    Map[i-1][j].merge(&Map[i][j]);
                }
            }
            else if(Map[i][j].arrow == 'l')
            {
                if(j - 1 < 1)
                {
                    Map[i][j].parent = Map[i][j].find(&Map[i][j]);
                    cnt++;
                }
                else if(Map[i][j-1].find(&Map[i][j-1]) == Map[i][j].find(&Map[i][j]))
                {
                    cnt++;
                }
                else
                {
                    Map[i][j-1].merge(&Map[i][j]);
                }
            }
            else if(Map[i][j].arrow == 'r')
            {
                if(j + 1 > m)
                {
                    Map[i][j].parent = Map[i][j].find(&Map[i][j]);
                    cnt++;
                }
                else if(Map[i][j+1].find(&Map[i][j+1]) == Map[i][j].find(&Map[i][j]))
                {
                    cnt++;
                }
                else
                {
                    Map[i][j+1].merge(&Map[i][j]);
                }
            }
            if(cnt >= 2)
            {
                cout<<"No"<<endl;
                return;
            }
        }
    }
    cout<<"Yes"<<endl;
}
int main()
{
    ll T = 1;
    cin>>T;
    while (T--)
    {
        solve();
    }
}

源文件, 语言: C++23

详细

Test #1:

score: 100

Accepted

time: 0ms

memory: 3576kb

input:

2
2 3
rdd
url
2 1 1
1 1 2
2 2
rr
rr
1 1
1 1

output:

Yes
No

result:

ok 2 token(s): yes count is 1, no count is 1

Test #2:

score: -100

Memory Limit Exceeded

input:

1109
5 8
rddddldl
drruludl
rrldrurd
urrrlluu
uurrulrl
4 4 1 2 4 3 1 6
1 3 5 1 1 1 3 6
2 4 1 1 2 1 1 1
2 3 4 2 4 3 3 3
4 1 1 2 2 5 1 5
7 9
rdrddrdll
urrdruldl
ruullrulu
drrlrlddl
rrrdddlll
ruulururl
ruurrlluu
7 1 1 1 2 1 2 3 6
1 7 3 1 3 1 2 1 8
2 2 1 2 4 3 1 2 2
2 2 4 1 1 5 3 3 1
3 4 6 1 2 1 2 7 7
6 ...

output:

No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
Yes
No
No
No
No
No
Yes
No
No
No
No
No
Yes
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
Yes
No
Yes
No
No
No
Yes
No
No
No
No
No
...