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QOJ

ID	Problem	Submitter	Result	Time	Memory	Language	File size	Submit time	Judge time
#499658	#6723. Grid with Arrows	Umok	WA	76ms	21420kb	C++20	2.5kb	2024-07-31 16:41:15	2024-07-31 16:41:16

Judging History

你现在查看的是最新测评结果

[2024-07-31 16:41:16]
评测

测评结果：WA
用时：76ms
内存：21420kb

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[2024-07-31 16:41:15]
提交

answer

#include <bits/stdc++.h>
using namespace std;
#define endl '\n'
const int N = 1e5 + 5;
#define int long long
typedef pair<int, int> PII;
#define MAX LONG_LONG_MAX
string mp[N];
vector<int> ar[N], f;
vector<int> st[N];
int n, m, din[N];
int finds(int x)
{
    if (f[x] == x)
        return x;
    return f[x] = finds(f[x]);
}
PII find(int x, int y)
{
    int xx = x, yy = y;
    if (mp[x][y] == 'r')
        yy += ar[x][y];
    else if (mp[x][y] == 'd')
        xx += ar[x][y];
    else if (mp[x][y] == 'l')
        yy -= ar[x][y];
    else
        xx -= ar[x][y];
    if (xx < 1 || xx > n || yy < 0 || yy > m)
        return {0, 0};
    return {xx, yy};
}

void solve()
{
    cin >> n >> m;
    int ans = n * m;
    f.clear();
    for (int i = 1; i <= n; i++)
    {
        mp[i] = "";
        ar[i].clear();
        st[i].clear();
    }
    for (int i = 1; i <= n; i++)
    {
        cin >> mp[i];
        mp[i] = " " + mp[i];
    }
    for (int i = 1; i <= n; i++)
    {
        ar[i].push_back(0);
        f.push_back(0);
        st[i].push_back(0);
        for (int j = 1; j <= m; j++)
        {
            int x;
            cin >> x;
            ar[i].push_back(x);
            f.push_back(0);
            st[i].push_back(0);
        }
    }
    st[0].push_back(0);

    for (int i = 1; i <= ans; i++)
        f[i] = i;

    int num = 1;
    for (int i = 1; i <= n; i++)
        for (int j = 1; j <= m; j++)
            st[i][j] = num++;

    for (int i = 1; i <= n; i++)
        for (int j = 1; j <= m; j++)
        {
            auto a = find(i, j);
            int x = a.first, y = a.second;
            int _ = f[st[i][j]], __ = f[st[x][y]];
            if (_ == __ || _ < 1 || __ < 1)
                continue;
            din[__]++;
            f[finds(__)] = finds(_);
        }
    int x = finds(1);
    for (int i = 2; i <= ans; i++)
    {
        if (finds(i) != x)
        {
            puts("No");
            return;
        }
    }
    int in0 = 0;
    for (int i = 1; i <= n; i++)
        for (int j = 1; j <= m; j++)
        {
            if (din[st[i][j]] == 0)
                in0++;
            if (in0 > 1)
            {
                cout << "No" << endl;
                return;
            }
        }
    cout << "Yes" << endl;
}
signed main()
{
    ios::sync_with_stdio(0);
    cin.tie(0), cout.tie(0);
    int tcase;
    cin >> tcase;
    while (tcase--)
        solve();
    return 0;
}

Source code, Language: C++20

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100

Accepted

time: 2ms

memory: 6784kb

input:

2
2 3
rdd
url
2 1 1
1 1 2
2 2
rr
rr
1 1
1 1

output:

Yes
No

result:

ok 2 token(s): yes count is 1, no count is 1

Test #2:

score: -100

Wrong Answer

time: 76ms

memory: 21420kb

input:

1109
5 8
rddddldl
drruludl
rrldrurd
urrrlluu
uurrulrl
4 4 1 2 4 3 1 6
1 3 5 1 1 1 3 6
2 4 1 1 2 1 1 1
2 3 4 2 4 3 3 3
4 1 1 2 2 5 1 5
7 9
rdrddrdll
urrdruldl
ruullrulu
drrlrlddl
rrrdddlll
ruulururl
ruurrlluu
7 1 1 1 2 1 2 3 6
1 7 3 1 3 1 2 1 8
2 2 1 2 4 3 1 2 2
2 2 4 1 1 5 3 3 1
3 4 6 1 2 1 2 7 7
6 ...

output:

Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
...

result:

wrong answer expected NO, found YES [2nd token]