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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#499639#6723. Grid with ArrowsziripoRE 0ms3708kbC++201.3kb2024-07-31 16:33:012024-07-31 16:33:01

Judging History

你现在查看的是最新测评结果

  • [2024-07-31 16:33:01]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:3708kb
  • [2024-07-31 16:33:01]
  • 提交

answer

#include<bits/stdc++.h>
#define ll long long
using namespace std;

vector<vector<char>> x;
vector<vector<ll>> f;

int main() {
	ll t; cin >> t;
	for (ll i = 0; i < t; i++) {
		ll n, m; scanf("%lld%lld", &n, &m);
		vector<vector<char>> x(n, vector<char>(m));
		vector<vector<ll>> s(n, vector<ll>(m));
		vector<vector<ll>> f(n, vector<ll>(m, -1));
		vector<ll> dp(n * m, 0);
		ll t = 0, xt = 0, yt = 0;
		for (ll i = 0; i < n; i++)for (ll j = 0; j < m; j++)cin >> x[i][j];
		for (ll i = 0; i < n; i++)for (ll j = 0; j < m; j++)scanf("%lld", &s[i][j]);
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < m; j++) {
				if (f[i][j] != -1)
					continue;
				ll p = i, q = j;
				int c = i * n + j;
				dp[c] = 1;
				t++;
				while (p >= 0 && p < n && q >= 0 && q < m) {
					f[p][q] = c;
					if (x[p][q] == 'u')
						p -= s[p][q];
					else if (x[p][q] == 'd')
						p += s[p][q];
					else if (x[p][q] == 'r')
						q += s[p][q];
					else if (x[p][q] == 'l')
						q -= s[p][q];
					if (!(p >= 0 && p < n && q >= 0 && q < m))
						break;
					if (f[p][q]!=-1) {
						if (dp[f[p][q]]==1) {
							t--;
							dp[f[p][q]] = 0;
						}
						break;
					}
				}
			}
		}
		if (t <= 1)
			printf("Yes\n");
		else
			printf("No\n");
	}
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3708kb

input:

2
2 3
rdd
url
2 1 1
1 1 2
2 2
rr
rr
1 1
1 1

output:

Yes
No

result:

ok 2 token(s): yes count is 1, no count is 1

Test #2:

score: -100
Runtime Error

input:

1109
5 8
rddddldl
drruludl
rrldrurd
urrrlluu
uurrulrl
4 4 1 2 4 3 1 6
1 3 5 1 1 1 3 6
2 4 1 1 2 1 1 1
2 3 4 2 4 3 3 3
4 1 1 2 2 5 1 5
7 9
rdrddrdll
urrdruldl
ruullrulu
drrlrlddl
rrrdddlll
ruulururl
ruurrlluu
7 1 1 1 2 1 2 3 6
1 7 3 1 3 1 2 1 8
2 2 1 2 4 3 1 2 2
2 2 4 1 1 5 3 3 1
3 4 6 1 2 1 2 7 7
6 ...

output:

Yes
Yes
No
No
Yes
No

result: