QOJ.ac
QOJ
| ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
|---|---|---|---|---|---|---|---|---|---|
| #499623 | #6723. Grid with Arrows | Railgun2334 | WA | 8ms | 3972kb | C++20 | 3.8kb | 2024-07-31 16:24:55 | 2024-07-31 16:24:56 |
Judging History
answer
#include <iostream>
#include <cstring>
#include <string>
#include <cstdio>
#include <vector>
#include <algorithm>
#include <set>
#include <map>
#include <queue>
#include <cstdio>
#include <cmath>
#include <fstream>
#define opeen freopen("in.txt", "r", stdout);
// #define int long long
using namespace std;
const int N = 1e5 + 10, M = 1e6 + 10, MOD = 1e9 + 7;
int n, m;
bool flag = 0;
void dfs(int x, int y, vector<vector<int>> a, int num, vector<vector<bool>> f, vector<vector<char>> s)
{
// cout<<x<<' '<<y<<' '<<num<<'\n';
if (num >= n * m)
{
flag = 1;
return;
}
if (s[x][y] == 'r')
{
int xx = x, yy = y + a[x][y];
if (xx >= 1 && xx <= n && yy >= 1 && yy <= m)
{
if (f[xx][yy] != 0)
return;
f[xx][yy] = 1;
dfs(xx, yy, a, num + 1, f, s);
}
}
else if (s[x][y] == 'l')
{
int xx = x, yy = y - a[x][y];
if (xx >= 1 && xx <= n && yy >= 1 && yy <= m)
{
if (f[xx][yy] != 0)
return;
f[xx][yy] = 1;
dfs(xx, yy, a, num + 1, f, s);
}
}
else if (s[x][y] == 'd')
{
int xx = x + a[x][y], yy = y;
if (xx >= 1 && xx <= n && yy >= 1 && yy <= m)
{
if (f[xx][yy] != 0)
return;
f[xx][yy] = 1;
dfs(xx, yy, a, num + 1, f, s);
}
}
else
{
int xx = x - a[x][y], yy = y;
if (xx >= 1 && xx <= n && yy >= 1 && yy <= m)
{
if (f[xx][yy] != 0)
return;
f[xx][yy] = 1;
dfs(xx, yy, a, num + 1, f, s);
}
}
}
void solove()
{
cin >> n >> m;
vector<vector<int>> a(n + 1, vector<int>(m + 1));
vector<vector<bool>> f(n + 1, vector<bool>(m + 1));
vector<vector<char>> s(n + 1, vector<char>(m + 1));
for (int i = 1; i <= n; i++)
{
for(int j=1;j<=m;j++)
{
cin>>s[i][j];
}
}
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= m; j++)
{
cin >> a[i][j];
}
}
vector<pair<int, int>> op;
vector<vector<bool>> st(n + 1, vector<bool>(m + 1));
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= m; j++)
{
int x = i, y = j;
if (s[i][j] == 'r')
{
x = i, y = j + a[i][j];
}
else if (s[i][j] == 'l')
{
x = i, y = j - a[i][j];
}
else if (s[i][j] == 'd')
{
x = i + a[i][j], y = j;
}
else
{
x = i - a[i][j], y = j;
}
if (x >= 1 && x <= n && y >= 1 && y <= m)
{
st[x][y] = 1;
}
}
}
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= m; j++)
{
if (st[i][j] == 1)
continue;
op.push_back({i, j});
if (op.size() >= 2)
{
cout << "No\n";
return;
}
}
}
if (op.size() == 0)
cout << "Yes\n";
else if (op.size() == 1)
{
flag = 0;
f[op[0].first][op[0].second] = 1;
dfs(op[0].first, op[0].second, a, 1, f, s);
if (flag == 1)
cout << "Yes\n";
else
cout << "No\n";
}
else
cout << "No\n";
}
signed main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int TT = 1;
cin >> TT;
while (TT--)
{
solove();
if(TT==500)break;
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3564kb
input:
2 2 3 rdd url 2 1 1 1 1 2 2 2 rr rr 1 1 1 1
output:
Yes No
result:
ok 2 token(s): yes count is 1, no count is 1
Test #2:
score: -100
Wrong Answer
time: 8ms
memory: 3972kb
input:
1109 5 8 rddddldl drruludl rrldrurd urrrlluu uurrulrl 4 4 1 2 4 3 1 6 1 3 5 1 1 1 3 6 2 4 1 1 2 1 1 1 2 3 4 2 4 3 3 3 4 1 1 2 2 5 1 5 7 9 rdrddrdll urrdruldl ruullrulu drrlrlddl rrrdddlll ruulururl ruurrlluu 7 1 1 1 2 1 2 3 6 1 7 3 1 3 1 2 1 8 2 2 1 2 4 3 1 2 2 2 2 4 1 1 5 3 3 1 3 4 6 1 2 1 2 7 7 6 ...
output:
Yes No No No Yes No Yes Yes Yes Yes No Yes No Yes Yes No Yes No Yes No No No Yes Yes Yes Yes Yes No Yes Yes No Yes Yes No Yes Yes Yes No No Yes Yes Yes No Yes Yes Yes No Yes Yes Yes Yes Yes Yes No Yes Yes No No Yes Yes Yes Yes Yes Yes No Yes Yes Yes Yes Yes No No Yes Yes No No Yes Yes Yes No Yes Yes...
result:
wrong answer expected NO, found YES [12th token]