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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#492927#4912. WereYouLastlifan100 ✓5512ms4992kbC++14936b2024-07-26 17:15:382024-07-26 17:15:42

Judging History

你现在查看的是最新测评结果

  • [2024-07-26 17:15:42]
  • 评测
  • 测评结果:100
  • 用时:5512ms
  • 内存:4992kb
  • [2024-07-26 17:15:38]
  • 提交

answer

// 
#include<bits/stdc++.h>
using namespace std;
bool query(int);
void modify(int,bool);
bool WereYouLast(int n,int m){
	/*
	其实就是用5个bit位存储当前的位置(2^k)
	然后再对于每个位置维护这个位置出现过奇数/偶数次
	如果是偶数次停留,否则回到0继续走
	感觉这个数学分析之后好神奇
	*/
	//特判n=10;
	if(n==1024||m==10){
		int now=0;
		for(int i=1;i<=10;i++)now<<=1,now|=query(i);
		if(now==n-1)return 1;
		++now;
		for(int i=10;i;--i)modify(i,now&1),now>>=1;
		return 0;
	}
	int pw=-1,tmp=n;
	while(tmp)pw++,tmp>>=1;
	int now=0;
	for(int i=1;i<=5;i++)now<<=1,now|=query(i);
	if(now==pw)return 1;
	if(now==pw-1){//临门一脚
		for(int i=5;i;--i)modify(i,pw&1),pw>>=1;
		return 0;
	}
	int op=query(now+50);
	if(op){
		modify(50+now,0);
		++now;
	}
	else modify(50+now,1),now=0;
	for(int i=5;i;--i)modify(i,now&1),now>>=1;
	return 0;
}

詳細信息

Subtask #1:

score: 10
Accepted

Test #1:

score: 10
Accepted
time: 1ms
memory: 3904kb

input:

1024 10

output:

12345876 10 10

result:

ok Correct Answer.
C1 = 10.
C2 = 10.

Subtask #2:

score: 20
Accepted

Test #2:

score: 20
Accepted
time: 6ms
memory: 4992kb

input:

65536 100000

output:

12345876 6 6

result:

ok Correct Answer.
C1 = 6.
C2 = 6.

Subtask #3:

score: 30
Accepted

Test #3:

score: 30
Accepted
time: 83ms
memory: 4976kb

input:

1048576 100000

output:

12345876 6 6

result:

ok Correct Answer.
C1 = 6.
C2 = 6.

Subtask #4:

score: 40
Accepted

Test #4:

score: 40
Accepted
time: 5512ms
memory: 4988kb

input:

67108864 100000

output:

12345876 6 6

result:

ok Correct Answer.
C1 = 6.
C2 = 6.