#include <bits/stdc++.h>
#define ent '\n'
#define f first
#define s second

typedef long long ll;
typedef long double ld;
using namespace std;
const int maxn = 1e6+12;

pair<ld, int> dp[maxn];
vector<int> g[maxn];
bool was[maxn];
vector<int> t;
int L[maxn];
int R[maxn];
int n, m;

struct line{
    ld k, b;
    int c;
};

bool check(line nw, line last, line prl){
    if((nw.b - prl.b) * (prl.k - last.k) <= (last.b - prl.b) * (prl.k - nw.k))return 1;
    return 0;
}

int ptr = 0;
vector<line> l;

void add(line x){
    while(l.size() && l.back().k == x.k && l.back().b > x.b){
        l.pop_back();
    }
    if(l.size() && l.back().k == x.k && l.back().b <= x.b){
        return;
    }
    while(l.size()>1 && check(x, l.back(), l[l.size()-2])){
        l.pop_back();
    }
    l.push_back(x);
}

pair<ld, int> get(ll x){
    if(!l.size()){
        return {1e18, 1e9};
    }
    if(ptr >= l.size()){
        ptr = l.size()-1;
    }
    while(ptr + 1 < l.size() && l[ptr].k * x + l[ptr].b > l[ptr+1].k * x + l[ptr+1].b){
        ptr++;
    }
    return {l[ptr].k * x + l[ptr].b, l[ptr].c + 1};
}

int check(ll k){
    add({0, 0, 0});
    for(int &i:t){
        dp[i] = get(i);
        dp[i].f += i * 1ll * i + k;
        for(int &j:g[i]){
            ll b = j * 1ll * j + dp[R[j]].f, c = dp[R[j]].s;
            if(R[j] > j) b -= (R[j] - j) * 1ll * (R[j] - j);
            add(line(-2 * j, b, c));
        }
    }
    l.clear();
    ptr = 0;
    return dp[m].s;
}

long long solve(int k){
    ll val = 0;
    for(ll l = -2e12, r = 2e12; l <= r;){
        ll mid = l + r >> 1;
        if(check(mid) <= k){
            val = mid;
            r = mid - 1;
        }
        else l = mid + 1;
    }
    check(val);
    return dp[m].f - dp[m].s * val;
}

long long take_photos(int N, int M, int k, vector<int> rr, vector<int> c){
    n = N, m = M;
    for(int i=1;i<=m;i++){
        L[i] = 1e9;
    }
    m = 0;
    for(int i=0;i<n;i++){
        if(rr[i] < c[i]){
            swap(rr[i], c[i]);
        }
        rr[i]++, c[i]++;
        L[rr[i]] = min(L[rr[i]], c[i]);
        R[c[i]] = max(R[c[i]], rr[i]);
        for(int x=-1;x<=0;x++){
            was[rr[i]+x] = was[c[i]+x] = 1;
        }
        m = max(m, rr[i]);
    }
    was[1] = 1;
    for(int i=1;i<=m;i++){
        R[i] = max(R[i], R[i-1]);
        if(!was[i]) continue;
        t.push_back(i);
        g[max(R[i], i)].push_back(i);
    }
    ll ans = 1e18;
    int l = 1, r = k;
    for(; r - l >= 10;){
        int m1 = l + (r - l) / 3, m2 = r - (r - l) / 3;
        ans = min({ans, solve(m1), solve(m2)});
        if(solve(m1) <= solve(m2)){
            r = m2;
        }
        else l = m1;
    }
    for(int i=l;i<=r;i++){
        ans = min(ans, solve(i));
    }
    return ans;
}