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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#488025 | #7733. Cool, It’s Yesterday Four Times More | Gaze | TL | 56ms | 200996kb | C++14 | 2.2kb | 2024-07-23 15:15:03 | 2024-07-23 15:15:04 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
struct Node {
int n, m;
}str[5010];
int T, n, m, opt;
char ch;
int e[5010][5010], vis[5010][5010], win[5010];
void DFS(int x, int y, int num) {
if(vis[x][y] != 0 || e[x][y] == 0) return;
vis[x][y] = num;
DFS(x + 1, y, num);
DFS(x, y + 1, num);
DFS(x - 1, y, num);
DFS(x, y - 1, num);
}
bool v[5010][5010];
void clear(int x, int y) {
if(v[x][y] == 0) return;
v[x][y] = 0;
clear(x + 1, y);
clear(x - 1, y);
clear(x, y + 1);
clear(x, y - 1);
}
void cmp(int x, int y, int xa, int yb) {
if(opt == 0 || v[x][y] == 1) return;
if(e[x][y] == 0) return;
if(e[xa][yb] == 0) {
opt = 0;
return;
}
v[x][y] = 1;
cmp(x + 1, y, xa + 1, yb);
cmp(x - 1, y, xa - 1, yb);
cmp(x, y + 1, xa, yb + 1);
cmp(x, y - 1, xa, yb - 1);
return;
}
void Solve() {
int num = 0;
for(int i = 1; i <= n; ++i) {
for(int j = 1; j <= m; ++j) {
if(e[i][j] == 1 && vis[i][j] == 0) {
num += 1;
DFS(i, j, num);
}
}
}
// for(int i = 1; i <= n; ++i) {
// for(int j = 1; j <= m; ++j) {
// cout << vis[i][j];
// }
// cout << endl;
// }
for(int i = 1; i <= n; ++i) {
for(int j = 1; j <= m; ++j) {
int nm = vis[i][j];
if(nm == 0) continue;
if(str[nm].n == 0) {
str[nm].n = i;
str[nm].m = j;
}
}
}
for(int i = 1; i <= num; ++i) {
int op = 0;
for(int j = 1; j <= n; ++j) {
for(int k = 1; k <= m; ++k) {
if(vis[j][k] != i && e[j][k] == 1) {
clear(str[i].n, str[i].m);
opt = 1;
cmp(str[i].n, str[i].m, j, k);
op = max(opt, op);
}
}
}
if(op == 0) {
win[i] = 1;
}
}
int ans = 0;
for(int i = 1; i <= n; ++i) {
for(int j = 1; j <= m; ++j) {
if(win[vis[i][j]] == 1) ans += 1;
}
}
cout << ans << endl;
}
int main() {
//freopen("1.in", "r", stdin);
cin >> T;
for(int i = 1; i <= T; ++i) {
memset(e, 0, sizeof(e));
memset(vis, 0, sizeof(vis));
memset(win, 0, sizeof(win));
memset(str, 0, sizeof(str));
cin >> n >> m;
for(int i = 1; i <= n; ++i) {
for(int j = 1; j <= m; ++j) {
cin >> ch;
if(ch == '.') e[i][j] = 1;
}
}
Solve();
}
}
详细
Test #1:
score: 100
Accepted
time: 56ms
memory: 200996kb
input:
4 2 5 .OO.. O..O. 1 3 O.O 1 3 .O. 2 3 OOO OOO
output:
3 1 0 0
result:
ok 4 lines
Test #2:
score: -100
Time Limit Exceeded
input:
200 2 4 OOO. OO.. 2 3 OOO .O. 3 3 O.O OOO OO. 4 1 . . O O 1 2 .O 1 1 . 2 5 .OO.. .O.O. 2 1 O O 1 1 O 1 3 .OO 5 1 O O . O . 5 2 O. .. O. .O .. 5 3 ... ... .OO ..O OOO 3 5 ..O.O .O.O. .OO.O 5 2 .O OO O. O. .. 2 1 O O 3 5 .O.OO O...O ..OO. 1 5 ..... 5 1 O . O . . 5 3 OOO OO. .OO OO. O.O 2 1 O . 5 2 O. ...
output:
3 0 0 2 1 1 3 0 0 1 0 4 9 4 4 0 0 5 2 0 1 0 4 5 2 0 0 5 3 3 1 4 1 0 4 5 2 3 7 3 0 6 0 2 2 0 4 6 6 3 3 2 0 5 0 1 0 3 3 4 4 0 2 0 7 6 4 8 5 3