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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#487990 | #6633. Exam Requirements | ucup-team052# | ML | 15ms | 14060kb | C++23 | 2.9kb | 2024-07-23 14:34:51 | 2024-07-23 14:34:53 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 5, M = 2e7;
vector <int> adj[M];
int l[N], r[N], b[N];
int T, n, m, tot, len;
inline void adde(int u, int v) {
if (u && v) {
adj[u].push_back(v);
// fprintf(stderr, "u = %d, v = %d\n", u, v);
}
}
int p1[N << 2], p2[N << 2];
int ID;
void query(int u, int L, int R, int l, int r) {
// fprintf(stderr, "u = %d, L = %d, R = %d, l = %d, r = %d\n", u, L, R, l, r);
if (l <= L && R <= r) {
adde(ID * 2, p1[u]); adde(p2[u], ID * 2 - 1);
++tot;
adde(tot * 2 - 1, p1[u]);
if (L != R) {
adde(tot * 2 - 1, p1[u << 1]);
adde(tot * 2 - 1, p1[u << 1 | 1]);
}
p1[u] = tot * 2 - 1;
adde(p2[u], tot * 2);
if (L != R) {
adde(p2[u << 1], tot * 2);
adde(p2[u << 1 | 1], tot * 2);
}
p2[u] = tot * 2;
adde(p1[u], ID * 2 - 1);
adde(ID * 2, p2[u]);
return;
}
int mid = (L + R) >> 1;
if (mid >= l) query(u << 1, L, mid, l, r);
if (mid + 1 <= r) query(u << 1 | 1, mid + 1, R, l, r);
++tot;
adde(tot * 2 - 1, p1[u]);
adde(tot * 2 - 1, p1[u << 1]);
adde(tot * 2 - 1, p1[u << 1 | 1]);
p1[u] = tot * 2 - 1;
adde(p2[u], tot * 2);
adde(p2[u << 1], tot * 2);
adde(p2[u << 1 | 1], tot * 2);
p2[u] = tot * 2;
}
int low[M], dfn[M], st[M], col[N * 2];
bool inst[M];
int dfnt, top, cnt;
void tarjan(int u) {
low[u] = dfn[u] = ++dfnt; st[++top] = u; inst[u] = 1;
for (auto v : adj[u]) {
if (!dfn[v]) {
tarjan(v);
low[u] = min(low[u], low[v]);
} else if (inst[v]) {
low[u] = min(low[u], dfn[v]);
}
}
if (low[u] == dfn[u]) {
++cnt;
int tmp = 0;
while (tmp != u) {
tmp = st[top--];
inst[tmp] = 0;
if (tmp <= 2 * n) col[tmp] = cnt;
}
}
}
int main() {
scanf("%d", &T);
while (T--) {
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; i++) {
scanf("%d%d", &l[i], &r[i]);
b[i] = l[i];
}
for (int i = 1; i <= m; i++) {
int a, b;
scanf("%d%d", &a, &b);
adde(a * 2 - 1, b * 2);
adde(b * 2 - 1, a * 2);
}
sort(b + 1, b + n + 1);
len = unique(b + 1, b + n + 1) - b - 1;
for (int i = 1; i <= n; i++) {
l[i] = lower_bound(b + 1, b + len + 1, l[i]) - b;
r[i] = upper_bound(b + 1, b + len + 1, r[i]) - b - 1;
}
tot = n;
for (int i = 1; i <= len * 4; i++) p1[i] = p2[i] = 0;
for (int i = 1; i <= n; i++) {
ID = i;
query(1, 1, len, l[i], r[i]);
// add(1, 1, len, l[i], r[i]);
}
for (int i = 1; i <= len * 4; i++) p1[i] = p2[i] = 0;
for (int i = n; i >= 1; i--) {
ID = i;
query(1, 1, len, l[i], r[i]);
// add(1, 1, len, l[i], r[i]);
}
dfnt = cnt = 0;
for (int i = 1; i <= n * 2; i++) {
if (!dfn[i]) {
tarjan(i);
}
}
int ans = 1;
for (int i = 1; i <= n; i++) {
if (col[i * 2 - 1] == col[i * 2]) {
ans = 0;
break;
}
}
printf("%s\n", ans ? "YES" : "NO");
for (int i = 1; i <= tot * 2; i++) adj[i].clear(), dfn[i] = 0;
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 15ms
memory: 14060kb
input:
2 3 1 1 5 2 7 10 11 2 1 3 3 1 5 2 7 5 7 1 2 2 3 3 1
output:
YES NO
result:
ok 2 lines
Test #2:
score: -100
Memory Limit Exceeded
input:
1 100000 100000 15084647 15220430 217541056 217598054 222963701 223110976 71224450 71340221 320463268 320631387 334861459 334924668 328950591 329083669 178996498 178996584 428529461 428605033 405428435 405504132 197936687 197947412 9058562 9190197 169407597 169474101 297518153 297590927 31471874 316...
output:
NO