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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#487960#6642. (1, 2) Nimucup-team052#TL 0ms0kbC++232.6kb2024-07-23 14:13:522024-07-23 14:13:52

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  • [2024-07-23 14:13:52]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:0kb
  • [2024-07-23 14:13:52]
  • 提交

answer

#include<bits/stdc++.h>
#ifdef xay5421
#define D(...) fprintf(stderr,__VA_ARGS__)
#define DD(...) D(#__VA_ARGS__ "="),debug_helper::debug(__VA_ARGS__),D("\n")
#include"/home/xay5421/debug.hpp"
#else
#define D(...) ((void)0)
#define DD(...) ((void)0)
#endif
#define pb push_back
#define eb emplace_back
#define SZ(x) ((int)(x).size())
#define each(x,v) for(auto&x:v)
#define rep(i,a,b) for(int i=(a);i<=(b);++i)
#define per(i,a,b) for(int i=(a);i>=(b);--i)
template<class T>void rd(T&x){int f=0,c;while(!isdigit(c=getchar()))f^=!(c^45);x=(c&15);while(isdigit(c=getchar()))x=x*10+(c&15);if(f)x=-x;}
template<class T>void pt(T x,int c=-1){if(x<0)putchar('-'),x=-x;if(x>9)pt(x/10);putchar(x%10+48);if(c!=-1)putchar(c);}
using namespace std;
using LL=long long;
using ULL=unsigned long long;
const int P=1e9+7;
int ad(int k1,int k2){return k1+k2>=P?k1+k2-P:k1+k2;}
int su(int k1,int k2){return k1-k2<0?k1-k2+P:k1-k2;}
int mu(int k1,int k2){return 1ULL*k1*k2%P;}
void uad(int&k1,int k2){(k1+=k2)>=P&&(k1-=P);}
void usu(int&k1,int k2){(k1-=k2)<0&&(k1+=P);}
template<class... T>int ad(int k1,T... k2){return ad(k1,ad(k2...));}
template<class... T>int su(int k1,T... k2){return su(k1,ad(k2...));}
template<class... T>int mu(int k1,T... k2){return mu(k1,mu(k2...));}
template<class... T>void uad(int&k1,T... k2){return uad(k1,ad(k2...));}
template<class... T>void usu(int&k1,T... k2){return usu(k1,ad(k2...));}
int po(int k1,int k2){
	int k3=1;
	for(;k2;k2>>=1,k1=mu(k1,k1))if(k2&1)k3=mu(k3,k1);
	return k3;
}
const int N=1000005;
int T,n,m,K,a[N],dp[N],val[N],suf[N];
bool check(int mid){
	rep(i,1,n){
		if(mid==0){
			val[i]=dp[a[i]+1];
		}else{
			val[i]=dp[(a[i]+mid-1)/mid];
		}
	}
	nth_element(val+1,val+(n+1)/2,val+n+1);
	LL cur=0;
	rep(i,1,(n+1)/2){
		cur+=val[i];
		if(cur>K)return 0;
	}
	return 1;
}
int main(){
#ifdef xay5421
	freopen("a.in","r",stdin);
#endif
	rd(T);
	while(T--){
		rd(n),rd(m),rd(K);
		rep(i,1,n)rd(a[i]);
		rep(i,1,m)rd(dp[i]);
		dp[m+1]=2e9;
		per(i,m,1){
			dp[i]=min(dp[i],dp[i+1]);
		}
		rep(i,1,m+1){
			rep(j,1,(m+1)/i){
				dp[i*j]=min(dp[i*j],dp[i]+dp[j]);
			}
		}
		suf[m+1]=dp[m+1];
		per(i,m+1,1){
			suf[i]=min(suf[i+1],dp[i]);
		}
		int w=2e9;
		rep(i,1,m+1){
			w=min(w,dp[i]+dp[(m+i)/i]);
		}
		per(i,m+1,1){
			dp[i]=min(dp[i],w);
		}
		per(i,m,1){
			dp[i]=min(dp[i],dp[i+1]);
		}
		rep(i,1,m+1)D("%d ",dp[i]);
		D("\n");
		int l=0,r=m,ans=m;
		while(l<=r){
			int mid=(l+r)>>1;
			if(check(mid)){
				r=mid-1;
				ans=mid;
			}else{
				l=mid+1;
			}
		}
		printf("%d\n",ans);
		
	}
	return 0;
}

/*
2 2 4 4 6 6 
5
2 2 4 4 6 6 
5
2 2 4 4 6 6 
1



*/

Details

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Test #1:

score: 0
Time Limit Exceeded

input:

3
2
1 2
1
5
4
1 7 2 9

output:


result: