QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#485146 | #8593. Coin | fractal | 0 | 5ms | 30632kb | C++17 | 2.6kb | 2024-07-20 13:54:10 | 2024-07-20 13:54:10 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define F first
#define S second
#define sz(x) (int)x.size()
#define all(x) x.begin(), x.end()
#define make_unique(x) sort(all(x)), x.erase(unique(all(x)), x.end())
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
mt19937_64 Rng(chrono::steady_clock::now().time_since_epoch().count());
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
const int N = 1e6 + 200;
const int M = 1e6;
const int inf = 2e9 + 3;
const ll INF = 1e18;
int n, m;
vector<int> g[N];
int can[1001][1001];
int ans[N], now[N], d[N];
int main() {
ios_base::sync_with_stdio(0), cin.tie(0);
cin >> n >> m;
for (int i = 1; i <= n; ++i)
ans[i] = -1;
if (n <= 0) {
vector<int> x(m), y(m);
for (int i = 0; i < m; ++i) {
cin >> x[i] >> y[i];
now[x[i]] += (can[x[i]][y[i]] == 0);
now[y[i]] += (can[x[i]][y[i]] == 0);
can[x[i]][y[i]] = 1;
for (int v = 1; v <= n; ++v) {
if (can[y[i]][v]) {
now[v] += can[x[i]][v] == 0;
now[x[i]] += can[x[i]][v] == 0;
can[x[i]][v] = 1;
}
if (can[v][x[i]]) {
now[v] += can[v][y[i]] == 0;
now[y[i]] += can[v][y[i]] == 0;
can[v][y[i]] = 1;
}
}
for (int v = 1; v <= n; ++v) if (now[v] == n - 1) ans[v] = i + 1, now[v] = n;
}
for (int i = 1; i <= n; ++i)
cout << ans[i] << " \n"[i == n];
return 0;
}
for (int i = 1, x, y; i <= m; ++i) {
cin >> x >> y;
g[x].push_back(y);
d[y]++;
}
priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> q;
for (int i = 1; i <= n; ++i) {
q.push({d[i], i});
}
while (q.size()) {
auto [x, v] = q.top();
q.pop();
if (x > d[v]) continue;
vector<int> kek;
for (auto u : g[v]) {
kek.push_back(u);
}
if (q.size() && q.top().F == 0) {
while (q.size() && q.top().F == 0) {
for (auto u : g[q.top().S]) kek.push_back(u);
q.pop();
}
}
else {
ans[v] = m;
}
for (auto u : kek) {
d[u]--;
q.push({d[u], u});
}
}
for (int i = 1; i <= n; ++i)
cout << ans[i] << " \n"[i == n];
}
Details
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Subtask #1:
score: 0
Wrong Answer
Test #1:
score: 3
Acceptable Answer
time: 3ms
memory: 30204kb
input:
4 4 2 4 3 1 4 1 2 3
output:
4 4 -1 -1
result:
points 0.50 -1 correct
Test #2:
score: 3
Acceptable Answer
time: 5ms
memory: 30632kb
input:
6 8 1 5 5 4 6 2 2 5 4 3 6 1 6 5 2 1
output:
8 8 8 8 8 8
result:
points 0.50 -1 correct
Test #3:
score: 6
Accepted
time: 0ms
memory: 29568kb
input:
2 1 1 2
output:
1 1
result:
ok ac
Test #4:
score: 0
Wrong Answer
time: 0ms
memory: 29520kb
input:
6 12 1 5 5 4 6 2 2 5 4 3 6 5 1 5 1 5 2 4 6 3 1 3 4 3
output:
-1 12 12 12 12 -1
result:
wrong answer wa
Subtask #2:
score: 0
Skipped
Dependency #1:
0%
Subtask #3:
score: 0
Skipped
Dependency #1:
0%
Subtask #4:
score: 0
Skipped
Dependency #1:
0%