QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#484286 | #9108. Zayin and Obstacles | PetroTarnavskyi# | AC ✓ | 165ms | 12648kb | C++20 | 2.1kb | 2024-07-19 17:14:43 | 2024-07-19 17:14:45 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)
#define SZ(a) int(a.size())
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair
#define F first
#define S second
typedef long long LL;
typedef vector<int> VI;
typedef pair<int, int> PII;
typedef double db;
const int N = 104;
int a[N][N][N];
int d[N][N][N];
int dx[6] = {-1, 1, 0, 0, 0, 0};
int dy[6] = {0, 0, -1, 1, 0, 0};
int dz[6] = {0, 0, 0, 0, -1, 1};
int n;
bool ok(int x, int y, int z)
{
return 1 <= x && x <= n && 1 <= y && y <= n && 1 <= z && z <= n;
}
void solve()
{
FOR (i, 0, N) FOR (j, 0, N) FOR (k, 0, N)
{
a[i][j][k] = 0;
d[i][j][k] = -1;
}
int m;
cin >> n >> m;
FOR (it, 0, m)
{
int x1, y1, z1, x2, y2, z2;
cin >> x1 >> y1 >> z1 >> x2 >> y2 >> z2;
if (x2 < x1)
swap(x1, x2);
if (y2 < y1)
swap(y1, y2);
if (z2 < z1)
swap(z1, z2);
x2++;
y2++;
z2++;
FOR (mask, 0, 8)
{
int x = (mask & 1) ? x1 : x2;
int y = (mask & 2) ? y1 : y2;
int z = (mask & 4) ? z1 : z2;
a[x][y][z] += (__builtin_popcount(mask) & 1) ? -1 : 1;
}
}
FOR (x, 1, N)
FOR (y, 0, N)
FOR (z, 0, N)
a[x][y][z] += a[x - 1][y][z];
FOR (y, 1, N)
FOR (x, 0, N)
FOR (z, 0, N)
a[x][y][z] += a[x][y - 1][z];
FOR (z, 1, N)
FOR (y, 0, N)
FOR (x, 0, N)
a[x][y][z] += a[x][y][z - 1];
int x1, y1, z1;
cin >> x1 >> y1 >> z1;
d[x1][y1][z1] = 0;
queue<tuple<int, int, int>> q;
q.push({x1, y1, z1});
while (!q.empty())
{
auto [x, y, z] = q.front();
q.pop();
FOR (i, 0, 6)
{
int nx = x + dx[i];
int ny = y + dy[i];
int nz = z + dz[i];
if (ok(nx, ny, nz) && a[nx][ny][nz] == 0 && d[nx][ny][nz] == -1)
{
d[nx][ny][nz] = d[x][y][z] + 1;
q.push({nx, ny, nz});
}
}
}
int x2, y2, z2;
cin >> x2 >> y2 >> z2;
cout << d[x2][y2][z2] << '\n';
}
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
int t;
cin >> t;
while (t--)
{
solve();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 10ms
memory: 12492kb
input:
3 3 0 1 1 1 3 3 3 3 1 2 1 1 2 3 3 1 1 1 3 3 3 3 3 2 1 1 2 2 3 1 1 2 2 3 2 1 2 2 3 3 2 1 1 1 1 1 3
output:
6 -1 14
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 29ms
memory: 12492kb
input:
5 19 27 2 1 1 2 18 19 4 2 1 4 19 19 6 1 1 6 18 19 8 2 1 8 19 19 10 1 1 10 18 19 12 2 1 12 19 19 14 1 1 14 18 19 16 2 1 16 19 19 18 1 1 18 18 19 1 1 2 18 19 2 2 1 4 19 19 4 1 1 6 18 19 6 2 1 8 19 19 8 1 1 10 18 19 10 2 1 12 19 19 12 1 1 14 18 19 14 2 1 16 19 19 16 1 1 18 18 19 18 1 2 2 19 19 2 1 2 4 ...
output:
1998 15998 53998 127998 249998
result:
ok 5 lines
Test #3:
score: 0
Accepted
time: 49ms
memory: 12496kb
input:
5 99 147 2 1 1 2 98 99 4 2 1 4 99 99 6 1 1 6 98 99 8 2 1 8 99 99 10 1 1 10 98 99 12 2 1 12 99 99 14 1 1 14 98 99 16 2 1 16 99 99 18 1 1 18 98 99 20 2 1 20 99 99 22 1 1 22 98 99 24 2 1 24 99 99 26 1 1 26 98 99 28 2 1 28 99 99 30 1 1 30 98 99 32 2 1 32 99 99 34 1 1 34 98 99 36 2 1 36 99 99 38 1 1 38 9...
output:
132878 2596 227782 37198 90672
result:
ok 5 lines
Test #4:
score: 0
Accepted
time: 18ms
memory: 12316kb
input:
5 99 1000 2 1 1 2 98 99 4 2 1 4 99 99 6 1 1 6 98 99 8 2 1 8 99 99 10 1 1 10 98 99 12 2 1 12 99 99 14 1 1 14 98 99 16 2 1 16 99 99 18 1 1 18 98 99 20 2 1 20 99 99 22 1 1 22 98 99 24 2 1 24 99 99 26 1 1 26 98 99 28 2 1 28 99 99 30 1 1 30 98 99 32 2 1 32 99 99 34 1 1 34 98 99 36 2 1 36 99 99 38 1 1 38 ...
output:
4998 4998 4998 4998 4998
result:
ok 5 lines
Test #5:
score: 0
Accepted
time: 37ms
memory: 12564kb
input:
5 19 1000 2 1 1 2 18 19 4 2 1 4 19 19 6 1 1 6 18 19 8 2 1 8 19 19 10 1 1 10 18 19 12 2 1 12 19 19 14 1 1 14 18 19 16 2 1 16 19 19 18 1 1 18 18 19 4 13 10 4 19 12 6 5 5 6 6 18 6 16 4 6 18 11 8 6 10 8 17 19 14 10 7 14 17 12 2 4 4 2 5 15 4 5 10 4 7 17 12 1 2 12 2 9 12 8 10 12 18 15 16 19 2 16 19 8 8 1 ...
output:
-1 798 1906 3198 4998
result:
ok 5 lines
Test #6:
score: 0
Accepted
time: 165ms
memory: 12648kb
input:
5 100 0 92 81 37 11 85 14 100 0 16 48 91 61 65 58 100 0 87 25 52 83 7 45 100 0 80 95 16 62 5 80 100 0 33 33 50 48 82 3
output:
108 95 29 172 111
result:
ok 5 lines