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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#481699 | #4686. Tours | Geothermal | WA | 0ms | 3768kb | C++20 | 3.5kb | 2024-07-17 13:22:09 | 2024-07-17 13:22:10 |
Judging History
answer
#include "bits/stdc++.h"
#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")
using namespace std;
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;
typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
template<class T> using pq = priority_queue<T>;
template<class T> using pqg = priority_queue<T, vector<T>, greater<T>>;
#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)
#define trav(a,x) for (auto& a : x)
#define uid(a, b) uniform_int_distribution<int>(a, b)(rng)
#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
#define ins insert
template<class T> bool ckmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; }
template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; }
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
void __print(int x) {cerr << x;}
void __print(long x) {cerr << x;}
void __print(long long x) {cerr << x;}
void __print(unsigned x) {cerr << x;}
void __print(unsigned long x) {cerr << x;}
void __print(unsigned long long x) {cerr << x;}
void __print(float x) {cerr << x;}
void __print(double x) {cerr << x;}
void __print(long double x) {cerr << x;}
void __print(char x) {cerr << '\'' << x << '\'';}
void __print(const char *x) {cerr << '\"' << x << '\"';}
void __print(const string &x) {cerr << '\"' << x << '\"';}
void __print(bool x) {cerr << (x ? "true" : "false");}
template<typename T, typename V>
void __print(const pair<T, V> &x) {cerr << '{'; __print(x.first); cerr << ", "; __print(x.second); cerr << '}';}
template<typename T>
void __print(const T &x) {int f = 0; cerr << '{'; for (auto &i: x) cerr << (f++ ? ", " : ""), __print(i); cerr << "}";}
void _print() {cerr << "]\n";}
template <typename T, typename... V>
void _print(T t, V... v) {__print(t); if (sizeof...(v)) cerr << ", "; _print(v...);}
#ifdef DEBUG
#define dbg(x...) cerr << "\e[91m"<<__func__<<":"<<__LINE__<<" [" << #x << "] = ["; _print(x); cerr << "\e[39m" << endl;
#else
#define dbg(x...)
#endif
const int MOD = 1000000007;
const char nl = '\n';
const int MX = 100001;
int N, M;
int dep[2001];
int ans = 0;
vector<vi> graph;
void dfs(int v, int p) {
trav(a, graph[v]) {
if (a == p) continue;
if (dep[a] != -1) {
if (dep[a] < dep[v]) {
if (ans == 0) ans = dep[v]-dep[a]+1;
ans = __gcd(ans, dep[v]-dep[a]+1);
}
} else {
dep[a]=dep[v]+1;
dfs(a, v);
}
}
}
void solve() {
cin >> N >> M;
graph = vector<vi>(N);
F0R(i, M) {
int X, Y; cin >> X >> Y; X--; Y--;
graph[X].pb(Y); graph[Y].pb(X);
}
F0R(i, N) {
//dbg(i);
F0R(j, N) dep[j] = -1;
dep[i] = 0;
dfs(i, -1);
}
FOR(i, 1, N+1) {
if (ans%i == 0) {
cout << i << " ";
}
}
cout << nl;
}
int main() {
ios_base::sync_with_stdio(0); cin.tie(0);
int T = 1;
// cin >> T;
while(T--) {
solve();
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3744kb
input:
4 5 1 2 2 3 3 4 1 4 1 3
output:
1
result:
ok 1 number(s): "1"
Test #2:
score: 0
Accepted
time: 0ms
memory: 3756kb
input:
6 6 1 2 2 3 1 3 1 4 2 5 3 6
output:
1 3
result:
ok 2 number(s): "1 3"
Test #3:
score: 0
Accepted
time: 0ms
memory: 3764kb
input:
4 5 1 2 3 4 2 3 1 4 1 3
output:
1
result:
ok 1 number(s): "1"
Test #4:
score: 0
Accepted
time: 0ms
memory: 3768kb
input:
6 6 1 2 2 3 1 4 2 5 1 3 3 6
output:
1 3
result:
ok 2 number(s): "1 3"
Test #5:
score: -100
Wrong Answer
time: 0ms
memory: 3764kb
input:
9 10 1 2 2 3 3 4 4 5 5 6 6 7 7 8 1 8 4 9 6 9
output:
1 2 4
result:
wrong answer Output contains longer sequence [length = 3], but answer contains 2 elements