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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#479965#8005. Crossing the BordertarjenWA 87ms12416kbC++202.9kb2024-07-15 23:42:332024-07-15 23:42:33

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你现在查看的是最新测评结果

  • [2024-07-15 23:42:33]
  • 评测
  • 测评结果:WA
  • 用时:87ms
  • 内存:12416kb
  • [2024-07-15 23:42:33]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
const int N=11;
const int mod=998244353;
void add(int &x,int y){
    if((x+=y)>=mod)x-=mod;
}
struct info{
    int x,t;
    string str(){
        return "("+to_string(x)+","+to_string(t)+")";
    }
};
info& operator+=(info &x,const info y){
    if(y.x<x.x)x=y;
    else if(y.x==x.x)add(x.t,y.t);
    return x;
}
info operator+(info x,const int y){
    x.x+=y;
    return x;
}
info dp[1<<N][1<<N];
int a1[N],b1[N];
int a2[N],b2[N];
int suma1[1<<N],suma2[1<<N];
int sumb1[1<<N],sumb2[1<<N];
vector<int> ve1[1<<N],ve2[1<<N];
int main()
{
    int n,w;cin>>n>>w;
    vector<pair<int,int>> p(n);
    for(int i=0;i<n;i++)cin>>p[i].second>>p[i].first;
    sort(p.begin(),p.end());
    reverse(p.begin(),p.end());
    if(n==1){
        cout<<p[0].first<<" "<<1<<"\n";
        return 0;
    }
    int m=n/2;
    n-=m;
    for(int i=0;i<n;i++)a1[i]=p[i].second,b1[i]=p[i].first;
    for(int i=0;i<m;i++)a2[i]=p[i+n].second,b2[i]=p[i+n].first;
    for(int i=0;i<(1<<n);i++)
        for(int j=0;j<(1<<m);j++)dp[i][j]={(int)2e9,0};
    for(int i=1;i<(1<<n);i++)suma1[i]=suma1[i^(1<<__builtin_ctz(i))]+a1[__builtin_ctz(i)],sumb1[i]=b1[__builtin_ctz(i)];
    for(int i=1;i<(1<<m);i++)suma2[i]=suma2[i^(1<<__builtin_ctz(i))]+a2[__builtin_ctz(i)],sumb2[i]=b2[__builtin_ctz(i)];
    dp[0][0]={0,1};
    for(int i=1;i<(1<<m);i++){
        for(int j=i;j;j=(j-1)&i)if(suma2[j]<=w){
            dp[0][i]+=(dp[0][i^j]+sumb2[j]);
        }
    }
    for(int i=0;i<(1<<n);i++){
        ve1[i].push_back(0);
        for(int j=(i-1)&i;j;j=(j-1)&i)if(suma1[j^i]<=w){
            ve1[i].push_back(j);
        }
        sort(ve1[i].begin(),ve1[i].end(),[&](int x,int y){
            return suma1[x^i]<suma1[y^i];
        });
        
    }
    for(int i=0;i<(1<<m);i++){
        int p=((1<<m)-1)^i;
        ve2[i].push_back(i);
        for(int j=p;j;j=(j-1)&p)if(suma2[j]<=w){
            ve2[i].push_back(j^i);
        }
        sort(ve2[i].begin(),ve2[i].end(),[&](int x,int y){
            return suma2[x^i]>suma2[y^i];
        });
    }  
    for(int i=1;i<(1<<n);i++){
        for(int j=0;j<(1<<m);j++){
            info mi={(int)2e9,1};
            auto it1=ve1[i].begin();
            auto it2=ve2[j].begin();
            while(it2!=ve2[j].end()&&suma1[(*it1)^i]+suma2[(*it2)^j]>w)it2++;
            for(;it2!=ve2[j].end();it2++){
                while(it1!=ve1[i].end()&&suma1[(*it1)^i]+suma2[(*it2)^j]<=w){
                    // cout<<dp[*it1][j].x<<" "<<sumb1[(*it1)^i]<<endl;
                    mi+=(dp[*it1][j]+sumb1[(*it1)^i]);
                    it1++;
                }
                if(*it2!=j)dp[i][*it2]+=mi;
                // cout<<"i="<<i<<" j="<<j<<" it1="<<*it1<<" *it2="<<*it2<<" mi="<<mi.str()<<endl;
            }
            // cout<<"i="<<i<<" j="<<j<<" ("<<dp[i][j].x<<","<<dp[i][j].t<<")"<<endl;
        }
    }
    cout<<dp[(1<<n)-1][(1<<m)-1].x<<" ";
    cout<<dp[(1<<n)-1][(1<<m)-1].t<<"\n";
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3660kb

input:

5 5
3 5
1 4
2 3
2 2
2 1

output:

9 4

result:

ok 2 number(s): "9 4"

Test #2:

score: -100
Wrong Answer
time: 87ms
memory: 12416kb

input:

18 10000000
956231 904623
1692946 1796774
1081323 1170319
3218792 2542661
3183376 3037270
1869132 1442561
35436 35018
1564635 1939950
1847344 2006043
755870 899310
1671882 2057413
1369264 1338951
3132483 3504034
2056224 1825640
1840949 1562071
1514040 1405352
2300821 2421801
2466540 3004920

output:

9391997 186

result:

wrong answer 2nd numbers differ - expected: '70', found: '186'