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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#478323#8049. Equal SumslefyML 1ms3972kbC++141.1kb2024-07-14 20:36:542024-07-14 20:36:55

Judging History

你现在查看的是最新测评结果

  • [2024-07-14 20:36:55]
  • 评测
  • 测评结果:ML
  • 用时:1ms
  • 内存:3972kb
  • [2024-07-14 20:36:54]
  • 提交

answer

#include<bits/stdc++.h>
#define ll long long
using namespace std;
const int mod=998244353,N=510,lim=500;
int lx[N],ly[N],rx[N],ry[N];
ll f[N][N][N<<1];
void add(ll &x,int y){
    x+=y;
    if(x>=mod)x-=mod;
}
void del(ll &x,int y){
    x-=y;
    if(x<0)x+=mod;
}
int main(){
    int n,m;scanf("%d%d",&n,&m);
    for(int i=1;i<=n;i++)scanf("%d%d",&lx[i],&rx[i]);
    for(int i=1;i<=m;i++)scanf("%d%d",&ly[i],&ry[i]);
    f[0][0][lim]=1;f[0][0][lim+1]=-1;
    for(int i=0;i<=n;i++)for(int j=0;j<=m;j++){
        for(int k=1;k<=lim*2;k++)add(f[i][j][k],f[i][j][k-1]);
        for(int k=0;k<=lim*2;k++){
            if(k<lim){
                if(j<m){
                    add(f[i][j+1][k+ly[j+1]],f[i][j][k]);
                    del(f[i][j+1][k+ry[j+1]+1],f[i][j][k]);
                }
            }else{
                if(i<n){
                    add(f[i+1][j][k-rx[i+1]],f[i][j][k]);
                    del(f[i+1][j][k-lx[i+1]+1],f[i][j][k]);
                }
            }
        }
        if(i&&j){
            printf("%lld ",f[i][j][lim]);
            if(j==m)printf("\n");
        }
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3972kb

input:

2 3
1 2
2 3
1 4
2 2
1 3

output:

2 0 0 
3 4 4 

result:

ok 6 numbers

Test #2:

score: -100
Memory Limit Exceeded

input:

500 500
19 458
1 480
7 485
50 461
12 476
15 461
48 466
40 453
46 467
9 458
27 478
26 472
46 459
29 490
6 500
17 487
48 484
28 472
28 459
25 480
4 491
29 481
36 460
2 491
44 499
22 473
20 458
4 483
27 471
2 496
11 461
43 450
2 478
37 466
15 459
42 482
7 451
19 455
2 453
47 475
48 450
1 474
46 471
9 4...

output:

411 79401 9145270 673005095 180581065 984223118 586589234 293043270 404363796 865361724 665487988 118838806 926189944 226338288 521479857 808644951 786041288 340769021 177100 21 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ...

result: