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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#473168 | #6414. Classical Maximization Problem | UESTC_Snow_Halation | WA | 200ms | 25804kb | C++17 | 2.4kb | 2024-07-11 22:41:56 | 2024-07-11 22:41:57 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
constexpr int max_n = 4e5+7;
double eps = 1e-8;
vector<int> edge[max_n];
map<int, int> x2n, y2n;
map<pair<int,int>,int> idx;
vector<pair<int, bool>> n2xy;
bool vis[max_n];
vector<pair<int, int>> ans;
struct Pair{
int a;
bool add(int x, int y) {
int b;
if (n2xy[x - 1].second) {
b = idx[{n2xy[y - 1].first, n2xy[x - 1].first}];
} else {
b = idx[{n2xy[x - 1].first, n2xy[y - 1].first}];
}
if (a > 0) {
ans.emplace_back(a, b);
a = -1;
return true;
} else {
a = b;
return false;
}
}
};
void clear(int n) {
n <<= 1;
ans.clear();
x2n.clear();
y2n.clear();
n2xy.clear();
for (int i = 0; i <= n; ++i) {
edge[i].clear();
}
memset(vis, 0, n + 5);
}
bool dfs(int u, int fa) {
vis[u] = true;
Pair p{-1};
for (int v: edge[u]) {
if (vis[v]) {
if (v != fa && v > u) {
p.add(u, v);
}
continue;
}
if (dfs(v, u)) {
p.add(u, v);
}
}
return fa && !p.add(u, fa);
}
void solve() {
int n;
cin >> n;
n <<= 1;
int x, y;
for (int i = 1; i <= n; ++i) {
cin >> x >> y;
idx[{x,y}] = i;
if (!x2n.count(x)) {
n2xy.emplace_back(x, false);
x2n[x] = n2xy.size();
}
if (!y2n.count(y)) {
n2xy.emplace_back(y, true);
y2n[y] = n2xy.size();
}
edge[x2n[x]].push_back(y2n[y]);
edge[y2n[y]].push_back(x2n[x]);
}
int m = n2xy.size();
for (int i = 1; i <= m; ++i) {
if (!vis[i]) dfs(i, 0);
}
// for (int i = 1; i <= n; ++i) {
// cout << i << ": ";
// for (int it: edge[i]) {
// cout << it << ", ";
// }
// cout << '\n';
// }
memset(vis, 0, n + 5);
m = ans.size();
cout << m << '\n';
for (auto [x, y]: ans) {
cout << x << ' ' << y << '\n';
vis[x] = true;
vis[y] = true;
}
int a = 0;
for (int i = 1; i <= n; ++i) {
if (!vis[i] && a) {
cout << a << ' ' << i << '\n';
a = 0;
} else {
a = i;
}
}
clear(n);
}
int main() {
// freopen("code.out", "w", stdout);
ios::sync_with_stdio(false);
cin.tie(nullptr);
int T = 1;
cin >> T;
// scanf("%d", &T);
for (int i = 1; i <= T; ++i) {
// cout << "Case " << i << ": ";
solve();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 3ms
memory: 13392kb
input:
3 2 0 0 0 1 1 0 1 1 2 0 0 0 1 0 2 0 3 2 0 0 1 1 2 2 3 3
output:
2 4 3 1 2 2 1 2 3 4 0 1 2 3 4
result:
ok ok (3 test cases)
Test #2:
score: 0
Accepted
time: 198ms
memory: 25748kb
input:
10000 2 -107276936 -310501829 419434212 585811870 -65754386 -491212232 381152038 897148193 3 -474045168 493506332 299114415 540203303 165808153 983551 -506936261 -694189769 766718170 -725540031 975267148 -593051087 1 -818952276 -762387923 584023914 -612401389 6 -77701228 -266484128 659434465 6322062...
output:
0 1 2 3 4 0 1 2 3 4 5 6 0 1 2 0 1 2 3 4 5 6 7 8 9 10 11 12 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 0 1 2 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 0 1 2 3 4...
result:
ok ok (10000 test cases)
Test #3:
score: -100
Wrong Answer
time: 200ms
memory: 25804kb
input:
10000 1 999855386 999580905 999342928 999615227 21 999601032 999015398 999155628 999176944 999309856 999524434 999121011 999509537 999323572 999685730 999272272 999769606 999450559 999390758 999632027 999178534 999024993 999463838 999784856 999374197 999980525 999366771 999241260 999516879 999599548...
output:
0 1 2 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 0 1 2 3 4 5 6 7...
result:
wrong answer point 3 used twice (test case 2517)