QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#472547#1436. Split in SetsSunsetLakeWA 0ms3808kbC++142.0kb2024-07-11 17:06:272024-07-11 17:06:28

Judging History

你现在查看的是最新测评结果

  • [2024-07-11 17:06:28]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3808kb
  • [2024-07-11 17:06:27]
  • 提交

answer

#include<bits/stdc++.h>
#define ll long long
#define pb push_back
using namespace std;
const int N = 1e5 + 5,mod = 1e9 + 7;
int n,k;
ll fac[N],inv[N],sum,cnt;
ll qpow(ll x,ll y){
	ll res = 1;
	while(y){
		if(y & 1) res = res * x % mod;
		x = x * x % mod;
		y >>= 1;
	}
	return res;
}
ll C(ll x,ll y){
	if(x < y || x < 0 || y < 0) return 0;
	return fac[x] * inv[y] % mod * inv[x - y] % mod;
}
ll calc(ll x,ll y){//x diff balls --> y same boxes can't empty
	ll res = 0;
	for(int i = 0;i <= y;++ i)
		if(i & 1) res = (res - C(y,i) * qpow(y - i,x) % mod + mod) % mod;
		else res = (res + C(y,i) * qpow(y - i,x) % mod) % mod;
	return res;
} 
vector<int>v,tmp;
void print(){
	for(auto now : tmp) cout << now << " ";
	puts("");
}
int main(){
	cin >> n >> k;
	int ppp = k;
	for(int i = 1,a;i <= n;++ i) scanf("%d",&a),v.pb(a);
	fac[0] = inv[0] = 1;
	for(int i = 1;i <= n;++ i) fac[i] = fac[i - 1] * i % mod;
	inv[n] = qpow(fac[n],mod - 2);
	for(int i = n - 1;i >= 1;-- i) inv[i] = inv[i + 1] * (i + 1) % mod;
	while(1){
		ll mx = 0;
		for(auto now : v) mx = max(mx,1ll * now);
		if(!mx) break;
		ll bit = __lg(mx);
		mx = 1 << bit;
		int num = 0;
		for(auto now : v) num += (now >= mx);
		if(mx == 1){
			puts("gfdhdhgf");
			if(num < k) cnt = (cnt + calc(v.size() - num,k - num)) % mod;
			else cnt = (cnt + calc(num + 1,k)) % mod;
		}
		if(num < k){
			for(auto now : v) if(now >= mx) sum += now;
			k -= num;
			for(auto now : v) if(now < mx) tmp.pb(now);
		}
		else{
			if(num == v.size()){
				sum += k * mx;
				for(auto now : v) tmp.pb(now ^ mx);
//				cout << "fdsgsg\n";
//				print();
			}
			else{
				sum += (k - 1) * mx;
				int kk = (1 << 30) - 1;
				for(auto now : v) 
					if(now < mx) kk &= now;
					else tmp.pb(now ^ mx);
				tmp.pb(kk);
			}
		}
		swap(v,tmp);
		tmp.clear();
	} 
	if(!cnt) cnt = 1;
	cout << sum << " " << cnt * fac[ppp] % mod;
	return 0;
}
/*
3 2
4 7 5
100
111
101

4 1
44 47 74 77
0101100
0101111
1001010
1001101
*/

詳細信息

Test #1:

score: 0
Wrong Answer
time: 0ms
memory: 3808kb

input:

3 2
4 7 5

output:

gfdhdhgf
11 2

result:

wrong answer 1st words differ - expected: '11', found: 'gfdhdhgf'