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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#471066 | #7563. Fun on Tree | duckindog | WA | 1524ms | 60848kb | C++23 | 3.5kb | 2024-07-10 17:36:29 | 2024-07-10 17:36:29 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define int long long
const int N = 200'000 + 10;
int n, q;
int a[N];
vector<pair<int, int>> ad[N];
int par[N], d[N], sz[N];
void dfs0(int u) {
for (const auto& [v, w] : ad[u]) {
par[v] = u;
d[v] = d[u] + w;
dfs0(v);
sz[u] += sz[v] + 1;
}
}
int head[N], st[N], ed[N], rvs[N], it;
void dfs1(int u) {
if (!head[u]) head[u] = u;
st[u] = ++it; rvs[it] = u;
sort(ad[u].begin(), ad[u].end(), [&](const auto& a, const auto& b) {
return sz[a.first] > sz[b.first];
});
for (const auto& [v, w] : ad[u]) {
if (make_pair(v, w) == ad[u][0]) head[v] = head[u];
dfs1(v);
}
ed[u] = it;
}
struct IT {
pair<int, int> f[N << 2];
int lazy[N << 2];
void push(int s) {
f[s << 1].first += lazy[s]; f[s << 1 | 1].first += lazy[s];
lazy[s << 1] += lazy[s]; lazy[s << 1 | 1] += lazy[s];
lazy[s] = 0;
}
void update(int s, int l, int r, int u, int v, int x) {
if (v < l || u > r) return;
if (u <= l && r <= v) {
f[s].first += x;
lazy[s] += x;
return;
}
push(s);
int mid = l + r >> 1;
update(s << 1, l, mid, u, v, x); update(s << 1 | 1, mid + 1, r, u, v, x);
f[s] = max(f[s << 1], f[s << 1 | 1]);
}
void assign(int s, int l, int r, int i, pair<int, int> x) {
if (i < l || i > r) return;
if (l == r) {
f[s] = x;
return;
}
push(s);
int mid = l + r >> 1;
assign(s << 1, l, mid, i, x); assign(s << 1 | 1, mid + 1, r, i, x);
f[s] = max(f[s << 1], f[s << 1 | 1]);
}
pair<int, int> query(int s, int l, int r, int u, int v) {
if (v < l || u > r) return {-1'000'000'000'000'000, 0};
if (u <= l && r <= v) return f[s];
push(s);
int mid = l + r >> 1;
return max(query(s << 1, l, mid, u, v), query(s << 1 | 1, mid + 1, r, u, v));
}
} T, D;
int32_t main() {
cin.tie(0)->sync_with_stdio(0);
cin >> n >> q;
for (int i = 1; i <= n; ++i) cin >> a[i];
for (int v = 2; v <= n; ++v) {
int u, w; cin >> u >> w;
ad[u].push_back({v, w});
}
dfs0(1);
dfs1(1);
for (int i = 1; i <= n; ++i) T.assign(1, 1, n, st[i], {d[i] - a[i], -i});
for (int u = 1; u <= n; ++u) {
pair<int, int> ma = {-a[u], -u};
for (const auto& [v, w] : ad[u]) {
if (v == ad[u][0].first) continue;
ma = max(ma, T.query(1, 1, n, st[v], ed[v]));
}
ma.first -= 2 * d[u];
D.assign(1, 1, n, st[u], ma);
}
for (int i = 1; i <= q; ++i) {
int x, y, w; cin >> x >> y >> w;
int start = x;
T.update(1, 1, n, st[y], ed[y], -w);
D.update(1, 1, n, st[y], ed[y], -w);
while (par[head[y]]) {
int a = par[head[y]], b = ad[a][0].first;
auto ret = max(T.query(1, 1, n, st[a], st[b] - 1), T.query(1, 1, n, ed[b] + 1, ed[a]));
ret.first -= 2 * d[a];
D.assign(1, 1, n, st[a], ret);
y = par[head[y]];
}
auto answer = T.query(1, 1, n, st[x], ed[x]);
answer.first -= d[x];
while (x) {
{
int l = st[head[x]], r = st[x] - 1;
auto ret = D.query(1, 1, n, l, r);
ret.first += d[start];
answer = max(answer, ret);
}
if (par[head[x]]) {
int a = par[head[x]], b = ad[a][0].first;
auto ret = max(T.query(1, 1, n, st[a], st[b] - 1), T.query(1, 1, n, ed[b] + 1, ed[a]));
ret.first += d[start];
answer = max(answer, ret);
}
x = par[head[x]];
}
cout << -answer.second << " " << answer.first << "\n";
}
}
詳細信息
Test #1:
score: 100
Accepted
time: 4ms
memory: 39624kb
input:
6 6 1 1 4 5 1 4 1 5 2 0 3 2 4 1 5 6 3 2 -100000 1 2 100000 1 1 0 2 2 66 3 1 5 4 4 -3
output:
6 100005 6 10 6 10 1 4 1 -1 1 1
result:
ok 6 lines
Test #2:
score: 0
Accepted
time: 0ms
memory: 38516kb
input:
5 6 -10 0 2 -4 8 1 7 1 1 2 2 2 -2 1 1 100 2 1 -100 1 1 0 4 3 10 2 5 3 5 2 2
output:
4 -87 1 17 4 13 1 19 1 17 1 15
result:
ok 6 lines
Test #3:
score: 0
Accepted
time: 3ms
memory: 37736kb
input:
6 3 0 0 0 0 0 0 1 10 1 10 1 -100 4 10 4 11 1 1 0 4 1 0 1 4 1000
output:
2 10 6 11 2 10
result:
ok 3 lines
Test #4:
score: 0
Accepted
time: 3ms
memory: 39580kb
input:
2 0 1 1 1 3
output:
result:
ok 0 lines
Test #5:
score: -100
Wrong Answer
time: 1524ms
memory: 60848kb
input:
200000 200000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 ...
output:
65204 15000000000 119017 16000000000 65204 15000000000 65204 15000000000 119017 16000000000 119017 14000000000 119017 15000000000 65204 17000000000 65204 16000000000 65204 12000000000 65204 17000000000 119017 15000000000 119017 13000000000 119017 16000000000 119017 17000000000 119017 15000000000 119...
result:
wrong answer 1st lines differ - expected: '119017 15000000000', found: '65204 15000000000'