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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#470363 | #5504. Flower Garden | 11d10xy | WA | 0ms | 39356kb | C++14 | 2.3kb | 2024-07-10 12:12:35 | 2024-07-10 12:12:35 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
int n,m,N,M,dfn[400010],low[400010],bl[400010],stk[400010],vis[400010],tot,tp,idin[100010<<2],idout[100010<<2];
vector<int>G[400010],D[400010],node[400010],ans,tmp;
void upd(){
if(ans.empty()&&n<=tmp.size()&&tmp.size()<=n*2){
ans.resize(n*3+1);
for(int x:tmp)ans[x]=1;
}
}
void build(int u,int l,int r){
if(l==r)return idin[u]=idout[u]=l,void();
int mid=l+r>>1;
build(u<<1,l,mid),build(u<<1|1,mid+1,r);
idin[u]=++N,idout[u]=++N;
G[idin[u]].push_back(idin[u<<1]);
G[idin[u]].push_back(idin[u<<1|1]);
G[idout[u<<1]].push_back(idout[u]);
G[idout[u<<1|1]].push_back(idout[u]);
}
void addin(int u,int l,int r,int L,int R,int x){
if(L<=l&&r<=R)return G[x].push_back(idin[u]),void();
int mid=l+r>>1;
if(L<=mid)addin(u<<1,l,mid,L,R,x);
if(R>mid)addin(u<<1|1,mid+1,r,L,R,x);
}
void addout(int u,int l,int r,int L,int R,int x){
if(L<=l&&r<=R)return G[idout[u]].push_back(x),void();
int mid=l+r>>1;
if(L<=mid)addout(u<<1,l,mid,L,R,x);
if(R>mid)addout(u<<1|1,mid+1,r,L,R,x);
}
void tarjan(int u){
dfn[u]=low[u]=++tot,stk[++tp]=u,vis[u]=1;
for(int v:G[u])if(!dfn[v])tarjan(v),low[u]=min(low[u],low[v]);
else if(vis[v])low[u]=min(low[u],dfn[v]);
if(dfn[u]==low[u]){
int x,U=++M;
do{
x=stk[tp--],vis[x]=0,bl[x]=U;
if(x<=3*n)node[U].push_back(x),tmp.push_back(x);
for(int v:G[x])if(bl[v]!=U)D[U].push_back(bl[v]);
}while(x!=u);
upd();
}
}
void dfs(int u){
tmp.insert(end(tmp),begin(node[u]),end(node[u]));
vis[u]=1;
for(int v:D[u])if(!vis[v])dfs(v);
}
void solve(){
cin>>n>>m,N=n*3;
build(1,1,n*3);
for(int a,b,c,d;m--;){
scanf("%d%d%d%d",&a,&b,&c,&d);
N++;
addout(1,1,n*3,a,b,N);
addin(1,1,n*3,c,d,N);
}
tmp={};
for(int i=1;i<=N;i++)if(!dfn[i])tarjan(i);
for(int i=1;ans.empty()&&i<=M;i++)if(node[i].size()>=n){
tmp={},dfs(i),upd();fill_n(vis+1,M,0);
}
if(!ans.empty()){
puts("TAK");
for(int i=1;i<=n*3;i++)putchar(ans[i]==0?'F':'R');
puts("");
}else puts("NIE");
for(int i=1;i<=N;i++)G[i]=D[i]=node[i]={},dfn[i]=low[i]=vis[i]=bl[i]=0;
ans={},M=tot=tp=0;
}
int main(){
int T;for(cin>>T;T--;)solve();
return 0;
}
Details
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Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 39356kb
input:
2 1 3 1 1 2 2 1 2 3 3 1 1 3 3 1 3 1 1 2 2 2 2 3 3 3 3 1 1
output:
TAK FFR NIE
result:
wrong answer odpowiedz nie spelnia wymogow!