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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#469764#7563. Fun on TreeduckindogWA 803ms37124kbC++232.2kb2024-07-09 23:38:512024-07-09 23:38:51

Judging History

你现在查看的是最新测评结果

  • [2024-07-09 23:38:51]
  • 评测
  • 测评结果:WA
  • 用时:803ms
  • 内存:37124kb
  • [2024-07-09 23:38:51]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

#define int long long

const int N = 200'000 + 10;
int n, q;
int a[N];
int par[N];
vector<pair<int, int>> ad[N];

int d[N], st[N], rvs[N], ed[N], it;
void dfs0(int u) { 
  st[u] = ++it; rvs[it] = u;
  for (const auto& [v, w] : ad[u]) { 
    d[v] = d[u] + w;
    par[v] = u;
    dfs0(v);
  }
  ed[u] = it;
}

pair<int, int> f[N << 2];
int lazy[N << 2];
void build(int s, int l, int r) { 
  if (l == r) {  
    f[s].first = d[rvs[l]] - a[rvs[l]];
    f[s].second = -rvs[l];
    return;
  }
  int mid = l + r >> 1;
  build(s << 1, l, mid); build(s << 1 | 1, mid + 1, r);
  f[s] = max(f[s << 1], f[s << 1 | 1]);
}
void push(int s) { 
  f[s << 1].first += lazy[s];   f[s << 1 | 1].first += lazy[s];
  lazy[s << 1] += lazy[s];      lazy[s << 1 | 1] += lazy[s];
  lazy[s] = 0;
}
void update(int s, int l, int r, int u, int v, int x) { 
  if (v < l || u > r) return;
  if (u <= l && r <= v) { 
    f[s].first += x;
    lazy[s] += x;
    return;
  }
  push(s);
  int mid = l + r >> 1;
  update(s << 1, l, mid, u, v, x); update(s << 1 | 1, mid + 1, r, u, v, x);
  f[s] = max(f[s << 1], f[s << 1 | 1]);
}
pair<int, int> query(int s, int l, int r, int u, int v) { 
  if (v < l || u > r) return {-1'000'000'000'000'000, 0};
  if (u <= l && r <= v) return f[s];
  push(s);
  int mid = l + r >> 1;

  return max(query(s << 1, l, mid, u, v), query(s << 1 | 1, mid + 1, r, u, v));
}

int32_t main() { 
  cin.tie(0)->sync_with_stdio(0);

  cin >> n >> q;
  for (int i = 1; i <= n; ++i) cin >> a[i];
  for (int v = 2; v <= n; ++v) { 
    int u, w; cin >> u >> w;
    ad[u].push_back({v, w});
  }

  dfs0(par[1] = 1);
  build(1, 1, n);

  while (q--) { 
    int x, y, v; cin >> x >> y >> v;
    int start = x;
    update(1, 1, n, st[y], ed[y], -v);

    pair<int, int> answer = query(1, 1, n, st[x], ed[x]);
    answer.first -= d[x];
    while (true) { 
      int u = par[x];
      if (x == 1) break;
      
      auto ret = max(query(1, 1, n, st[u], st[x] - 1), query(1, 1, n, ed[x] + 1, ed[u]));
      ret.first += d[start] - d[u];
      answer = max(answer, ret);  
      
      x = u;
    }

    cout << -answer.second << " " << answer.first << "\n";
  }
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 11864kb

input:

6 6
1 1 4 5 1 4
1 5
2 0
3 2
4 1
5 6
3 2 -100000
1 2 100000
1 1 0
2 2 66
3 1 5
4 4 -3

output:

6 100005
6 10
6 10
1 4
1 -1
1 1

result:

ok 6 lines

Test #2:

score: 0
Accepted
time: 2ms
memory: 13904kb

input:

5 6
-10 0 2 -4 8
1 7
1 1
2 2
2 -2
1 1 100
2 1 -100
1 1 0
4 3 10
2 5 3
5 2 2

output:

4 -87
1 17
4 13
1 19
1 17
1 15

result:

ok 6 lines

Test #3:

score: 0
Accepted
time: 1ms
memory: 9824kb

input:

6 3
0 0 0 0 0 0
1 10
1 10
1 -100
4 10
4 11
1 1 0
4 1 0
1 4 1000

output:

2 10
6 11
2 10

result:

ok 3 lines

Test #4:

score: 0
Accepted
time: 0ms
memory: 13960kb

input:

2 0
1 1
1 3

output:


result:

ok 0 lines

Test #5:

score: -100
Wrong Answer
time: 803ms
memory: 37124kb

input:

200000 200000
1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 ...

output:

119017 15000000000
120167 17000000000
119017 15000000000
119017 15000000000
120167 17000000000
120167 15000000000
120167 16000000000
119017 17000000000
119017 16000000000
119017 12000000000
119017 17000000000
120167 16000000000
120167 14000000000
120167 17000000000
120167 18000000000
120167 16000000...

result:

wrong answer 18664th lines differ - expected: '186683 18000000000', found: '120167 18000000000'