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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#468135#1163. Another Tree Queries Problemzhao_daodaoTL 0ms0kbC++142.5kb2024-07-08 19:29:252024-07-08 19:29:26

Judging History

你现在查看的是最新测评结果

  • [2024-07-08 19:29:26]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:0kb
  • [2024-07-08 19:29:25]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
namespace Read{
    #define getchar() (p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<21,stdin),p1==p2)?EOF:*p1++)
    char buf[1<<21],*p1=buf,*p2=buf;
    const int OUT=20;
    static char outp[OUT];
    int out;
    template<typename T>inline void read(T& t){
        int c=getchar(),f=1;t=0;
        while(!isdigit(c)){if(c=='-')f=-1;c=getchar();}
        while(isdigit(c))t=t*10+c-48,c=getchar();t*=f;
    }
    template<typename T,typename ...Args>inline void read(T& t,Args&... args){
        read(t),read(args...);
    }
    inline void write(short x){out=0; x<0&&(x=-x,putchar('-'));if(!x){ putchar(48); return; }while(x) outp[++out]=x%10+48,x/=10;while(out) putchar(outp[out--]);}
    inline void write(signed x){out=0; x<0&&(x=-x,putchar('-'));if(!x){ putchar(48); return; }while(x) outp[++out]=x%10+48,x/=10;while(out) putchar(outp[out--]);}
    inline void write(long long x){out=0; x<0&&(x=-x,putchar('-'));if(!x){ putchar(48); return; }while(x) outp[++out]=x%10+48,x/=10;while(out) putchar(outp[out--]);}
    inline void write(char x){putchar(x);}
    inline void write(const char* x){while(*x)putchar(*x++);}
    template<typename T,typename ...Args>inline void write(T t,Args ...args){
        write(t);write(args...);
    }
}
using namespace Read;
const int MAXN=1e6+5;
int n,m,a[MAXN],b[MAXN];
int La[MAXN],Ra[MAXN],suma[MAXN];
int Lb[MAXN],Rb[MAXN],sumb[MAXN];
int cnta1,cnta3,cntb1,cntb3;
inline int Sa(int l,int r){return suma[r]-suma[l-1];}
inline int Sb(int l,int r){return sumb[r]-sumb[l-1];}
int ans;
inline void solve(){
    cnta1=cnta3=cntb1=cntb3=ans=0;
    read(n,m);
    for(int i=1;i<=n;i++)read(a[i]);
    for(int i=1;i<=m;i++)read(b[i]);
    La[0]=0;for(int i=1;i<=n;i++)if(a[i]==1)La[++cnta1]=i;
    Ra[0]=n+1;for(int i=n;i>=1;i--)if(a[i]==3)Ra[++cnta3]=i;
    Lb[0]=0;for(int i=1;i<=m;i++)if(b[i]==1)Lb[++cntb1]=i;
    Rb[0]=m+1;for(int i=m;i>=1;i--)if(b[i]==3)Rb[++cntb3]=i;
    for(int i=1;i<=n;i++)suma[i]=suma[i-1]+(a[i]==2);
    for(int i=1;i<=m;i++)sumb[i]=sumb[i-1]+(b[i]==2);
    for(int i=0;i<=cnta1&&i<=cntb1;i++)
        for(int j=0;j<=cnta3&&j<=cntb3;j++){
            if(La[i]<Ra[j]&&Lb[i]<Rb[j]){
                int now=i+j+min(Sa(La[i]+1,Ra[j]-1),Sb(Lb[i]+1,Rb[j]-1));
                ans=max(ans,now);
            }else break;
        }
    write(ans,'\n');
}
signed main(){
    cin.tie(0);
    cout.tie(0);
    ios::sync_with_stdio(false);
    int T;read(T);while(T--)solve();
}

詳細信息

Test #1:

score: 0
Time Limit Exceeded

input:

5
4 2
2 5
1 5
1 3
5
2 2 4
3 4
2 1 5
2 5 5
3 2

output:


result: