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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#467911 | #1163. Another Tree Queries Problem | BINYU | WA | 135ms | 27436kb | C++14 | 5.4kb | 2024-07-08 18:17:27 | 2024-07-08 18:17:27 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
const int N = 2e5;
#define ll long long
ll calc(ll st,ll len,ll k)
{
return (2 * st + len * k - k) * len / 2;
}
struct Segment_Tree
{
#define ls id << 1
#define rs id << 1 | 1
struct node
{
ll len,sum,siz,dep,ad1,ad2,ad3;
}a[4 * N + 5];
void pushdown(int id)
{
int ad1 = a[id].ad1,ad2 = a[id].ad2,ad3 = a[id].ad3;
if(ad1)
{
a[ls].ad1 += ad1;
a[ls].sum += ad1 * a[ls].len;
a[rs].ad1 += ad1;
a[rs].sum += ad1 * a[rs].len;
a[id].ad1 = 0;
}
if(ad2)
{
a[ls].ad2 += ad2;
a[ls].sum += calc(ad2,a[ls].len,ad2);
a[rs].ad2 += ad2;
a[rs].ad1 += a[ls].len * ad2;
a[rs].sum += a[ls].len * ad2 * a[rs].len;
a[rs].sum += calc(ad2 + a[ls].len * ad2,a[rs].len,ad2);
a[id].ad2 = 0;
}
if(ad3)
{
a[ls].ad3 += ad3;
a[ls].sum += ad3 * a[ls].siz;
a[rs].ad3 += ad3;
a[rs].sum += ad3 * a[rs].siz;
a[id].ad3 = 0;
}
}
void build(int id,int l,int r)
{
a[id].len = r - l + 1;
if(l == r)return;
int mid = l + r >> 1;
build(ls,l,mid);build(rs,mid + 1,r);
}
void update(int id,int l,int r,int x,ll siz,ll dep)
{
if(l == r)
{
a[id].siz = siz;
a[id].dep = dep;
return;
}
int mid = l + r >> 1;
if(x <= mid)update(ls,l,mid,x,siz,dep);
else update(rs,mid + 1,r,x,siz,dep);
a[id].siz = a[ls].siz + a[rs].siz;
a[id].dep = a[ls].dep + a[rs].dep;
}
void add1(int id,int l,int r,int st,int en,ll v)
{
if(l >= st&&r <= en)
{
a[id].ad1 += v;
a[id].sum += v * (r - l + 1);
return;
}
int mid = l + r >> 1;pushdown(id);
if(st <= mid)add1(ls,l,mid,st,en,v);
if(en > mid)add1(rs,mid + 1,r,st,en,v);
a[id].sum = a[ls].sum + a[rs].sum;
}
int add2(int id,int l,int r,int st,int en,ll v)
{
if(l >= st&&r <= en)
{
a[id].ad1 += v;
a[id].ad2++;
a[id].sum += calc(v,r - l + 1,1);
return v + r - l + 1;
}
int mid = l + r >> 1;pushdown(id);
if(en > mid)v = add2(rs,mid + 1,r,st,en,v);
if(st <= mid)v = add2(ls,l,mid,st,en,v);
a[id].sum = a[ls].sum + a[rs].sum;
return v;
}
void add3(int id,int l,int r,int st,int en,ll v)
{
if(l >= st&&r <= en)
{
a[id].ad3 += v;
a[id].sum += v * a[id].siz;
return;
}
int mid = l + r >> 1;pushdown(id);
if(st <= mid)add3(ls,l,mid,st,en,v);
if(en > mid)add3(rs,mid + 1,r,st,en,v);
a[id].sum = a[ls].sum + a[rs].sum;
}
ll query(int id,int l,int r,int st,int en)
{
if(l >= st&&r <= en)return a[id].sum;
int mid = l + r >> 1;pushdown(id);
ll res = 0;
if(st <= mid)res += query(ls,l,mid,st,en);
if(en > mid)res += query(rs,mid + 1,r,st,en);
return res;
}
int query_dep(int id,int l,int r,int st,int en)
{
if(l >= st&&r <= en)return a[id].dep;
int mid = l + r >> 1;pushdown(id);
ll res = 0;
if(st <= mid)res += query_dep(ls,l,mid,st,en);
if(en > mid)res += query_dep(rs,mid + 1,r,st,en);
return res;
}
#undef ls
#undef rs
}st;
int n,q,u,v,op;
int siz[N + 5],son[N + 5],dep[N + 5],f[20][N + 5];
int dfn[N + 5],cntdfn,top[N + 5];
vector <int> e[N + 5];
ll sum1,sum2;
void dfs1(int u,int fa)
{
siz[u] = 1;
f[0][u] = fa;
dep[u] = dep[fa] + 1;
for(auto v : e[u])
{
if(v == fa)continue;
dfs1(v,u);siz[u] += siz[v];
if(siz[v] > siz[son[u]])
son[u] = v;
}
}
void dfs2(int u,int t)
{
top[u] = t;
dfn[u] = ++cntdfn;
if(son[u])dfs2(son[u],t);
for(auto v : e[u])
if(!dfn[v])dfs2(v,v);
}
int lca(int u,int v)
{
if(dep[u] < dep[v])swap(u,v);
for(int i = 18;~i;i--)
if(dep[f[i][u]] >= dep[v])
u = f[i][u];
if(u == v)return u;
for(int i = 18;~i;i--)
if(f[i][u] != f[i][v])
u = f[i][u],v = f[i][v];
return f[0][u];
}
int jmp(int u,int d)
{
for(int i = 18;~i;i--)
{
if(dep[f[i][u]] > d)
u = f[i][u];
}
return u;
}
ll query(int u)
{
ll res = 0;
while(u)
res += st.query(1,1,n,dfn[top[u]],dfn[u]),
u = f[0][top[u]];
return res;
}
void add1(int u,ll v)
{
while(u)
st.add1(1,1,n,dfn[top[u]],dfn[u],v),
u = f[0][top[u]];
}
void add2(int u,int F)
{
sum1 += dep[u] - dep[F] + 1;
int now = 1;
while(top[u] != top[F])
sum2 += st.query_dep(1,1,n,dfn[top[u]],dfn[u]),
now = st.add2(1,1,n,dfn[top[u]],dfn[u],now),
u = f[0][top[u]];
sum2 += st.query_dep(1,1,n,dfn[F],dfn[u]);
st.add2(1,1,n,dfn[F],dfn[u],now);
}
void add3(int u,ll v)
{
sum1 += v * siz[u];
sum2 += v * st.query_dep(1,1,n,dfn[u],dfn[u] + siz[u] - 1);
st.add3(1,1,n,dfn[u],dfn[u] + siz[u] - 1,v);
add1(f[0][u],v * siz[u]);
}
int main()
{
scanf("%d",&n);
for(int i = 1;i < n;i++)
scanf("%d %d",&u,&v),
e[u].push_back(v),e[v].push_back(u);
dfs1(1,0);dfs2(1,1);
for(int i = 0;i < 18;i++)
for(int j = 1;j <= n;j++)
f[i + 1][j] = f[i][f[i][j]];
st.build(1,1,n);
for(int i = 1;i <= n;i++)
st.update(1,1,n,dfn[i],siz[i],dep[i]);
scanf("%d",&q);
while(q--)
{
scanf("%d",&op);
if(op == 1)
{
scanf("%d %d",&u,&v);
if(u == v)add3(1,1);
else if(lca(u,v) == v)
add3(1,1),add3(jmp(u,dep[v]),-1);
else add3(v,1);
}
else if(op == 2)
{
scanf("%d %d",&u,&v);
int F = lca(u,v);
sum2 += dep[F];sum1++;
if(F != u)add2(u,jmp(u,dep[F]));
if(F != v)add2(v,jmp(v,dep[F]));
int cnt = dep[u] + dep[v] - 2 * dep[F] + 1;
add1(F,cnt);
}
else
{
scanf("%d",&u);
ll sum3 = query(u);
cout<<sum1 * dep[u] + sum2 - 2 * sum3<<"\n";
}
}
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 27384kb
input:
5 4 2 2 5 1 5 1 3 5 2 2 4 3 4 2 1 5 2 5 5 3 2
output:
1 5
result:
ok 2 number(s): "1 5"
Test #2:
score: -100
Wrong Answer
time: 135ms
memory: 27436kb
input:
200 171 114 50 183 28 68 67 152 139 125 67 55 50 98 106 71 46 42 157 165 42 49 113 12 81 145 105 13 38 96 34 156 24 17 21 191 135 54 174 116 177 157 123 71 95 130 135 193 150 129 25 190 96 93 188 173 90 160 86 187 20 132 199 75 59 195 189 24 40 68 163 83 25 13 73 33 59 50 154 19 146 21 151 67 89 69 ...
output:
826 908 815 1787 2288 1320 3038 2403 4773 3883 3991 3791 5717 4501 6410 7485 4562 7741 7395 9773 7467 6024 10934 6730 12943 14817 9349 9051 8437 10737 18180 21566 16055 17522 10705 14353 12045 18492 12368 16713 23046 20542 24732 19929 13934 21554 12991 19128 12941 24738 19322 29938 19874 33276 17511...
result:
wrong answer 3rd numbers differ - expected: '813', found: '815'