QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#466452#5504. Flower GardenBalintRWA 2ms16056kbC++205.8kb2024-07-07 20:32:442024-07-07 20:32:44

Judging History

你现在查看的是最新测评结果

  • [2024-07-07 20:32:44]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:16056kb
  • [2024-07-07 20:32:44]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

typedef unsigned uint;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<pii> vpii;
typedef complex<double> cpx;
template <typename T> using minPq = priority_queue<T, vector<T>, greater<T>>;
#define ms(a, x) memset(a, x, sizeof(a))
#define pb push_back
#define fs first
#define sn second
#define ALL(v) begin(v), end(v)
#define SZ(v) ((int) (v).size())
#define lbv(v, x) (lower_bound(ALL(v), x) - (v).begin())
#define ubv(v, x) (upper_bound(ALL(v), x) - (v).begin())
template <typename T> inline void UNIQUE(vector<T> &v){sort(ALL(v)); v.resize(unique(ALL(v)) - v.begin());}
const int INF = 0x3f3f3f3f;
const ll LLINF = 0x3f3f3f3f3f3f3f3f;
const double PI = acos(-1);
#define FR(i, n) for(int i = 0; i < (n); i++)
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define FORR(i, a, b) for(int i = (a); i >= (b); i--)
#define dbg(x) {cerr << #x << ' ' << x << endl;}
#define dbgArr(arr, n) {cerr << #arr; FR(_i, n) cerr << ' ' << (arr)[_i]; cerr << endl;}
template <typename T, typename U>
ostream& operator<<(ostream &os, pair<T, U> p){return os << "(" << p.fs << ", " << p.sn << ")";}

const int MQ = 1e5 + 5;
const int MN = 5e5 + 5;
int n, m, q;
pair<pii, pii> queries[MQ];
vi adjList[MN], gAdjList[MN], rgAdjList[MN], groups[MN];
int gi, *gid;
string res;

namespace Graph {
    int tsz, qOffs;

    struct Tree {
        int offs;

        int getNode(int i){
            if(i >= tsz) return i-tsz;
            else return offs+i;
        }

        vi query(int l, int r){
            vi res;
            for(l += tsz, r += tsz; l < r; l >>= 1, r >>= 1){
                if(l & 1) res.pb(getNode(l++));
                if(r & 1) res.pb(getNode(--r));
            }
            return res;
        }
    };

    Tree upTree, downTree;

    void genGraph(){
        tsz = 2 << __lg(max(1, m-1));
        upTree.offs = tsz;
        downTree.offs = tsz*2;
        qOffs = tsz*3;

        FORR(i, tsz*2-1, 2){
            adjList[upTree.getNode(i)].pb(upTree.getNode(i/2));
            adjList[downTree.getNode(i/2)].pb(downTree.getNode(i));
        }

        cin >> q;
        FR(i, q){
            int a, b, c, d;
            cin >> a >> b >> c >> d;
            a--; c--;
            queries[i] = {{a, b}, {c, d}};
            //FOR(x, c, d) FOR(y, a, b) adjList[x].pb(y);
            for(int n1 : upTree.query(c, d)) adjList[n1].pb(qOffs+i);
            for(int n1 : downTree.query(a, b)) adjList[qOffs+i].pb(n1);
        }
        //n = m;
        //return;

        n = qOffs+q;
        assert(n < MN);
    }
}

namespace SCC {
    vi stk;
    int init[MN], lo[MN], ti;

    void dfs(int n1){
        stk.pb(n1);
        init[n1] = lo[n1] = ++ti;
        for(int n2 : adjList[n1]){
            if(!init[n2]) dfs(n2);
            if(init[n2] > 0) lo[n1] = min(lo[n1], lo[n2]);
        }
        if(init[n1] == lo[n1]){
            while(true){
                int n2 = stk.back();
                stk.pop_back();
                if(n2 < m) groups[gi].pb(n2);
                init[n2] = ~gi;
                if(n2 == n1) break;
            }
            gi++;
        }
    }

    void genGroups(){
        gid = init;
        ti = 0;
        FR(i, n) init[i] = 0;
        FR(i, n) if(!init[i]) dfs(i);
        assert(stk.empty());
    }
}

namespace DAG {
    int inDeg[MN], outDeg[MN], sm;
    int qu[MN], ql, qr;

    bool solve(){
        //FR(i, gi) dbgArr(groups[i], SZ(groups[i]));

        FR(i, gi) inDeg[i] = outDeg[i] = 0;
        FR(n1, n) for(int n2 : adjList[n1]) if(gid[n1] != gid[n2]){
            int a = ~gid[n1], b = ~gid[n2];
            gAdjList[a].pb(b);
            rgAdjList[b].pb(a);
            outDeg[a]++;
            inDeg[b]++;
            //cerr << a << ' ' << b << endl;
        }
        m /= 3;

        res.assign(m*3, 'R');
        ql = qr = sm = 0;
        FR(n1, n) if(!inDeg[n1]) qu[qr++] = n1;
        while(ql < qr){
            int n1 = qu[ql++];
            if(sm + SZ(groups[n1]) > m+m) continue;
            sm += SZ(groups[n1]);
            for(int a : groups[n1]) res[a] = 'F';
            for(int n2 : gAdjList[n1]) if(!--inDeg[n2]) qu[qr++];
        }
        if(sm >= m) return true;

        res.assign(m*3, 'F');
        ql = qr = sm = 0;
        FR(n1, n) if(!outDeg[n1]) qu[qr++] = n1;
        while(ql < qr){
            int n1 = qu[ql++];
            if(sm + SZ(groups[n1]) > m+m) continue;
            sm += SZ(groups[n1]);
            for(int a : groups[n1]) res[a] = 'R';
            for(int n2 : rgAdjList[n1]) if(!--outDeg[n2]) qu[qr++];
        }
        if(sm >= m) return true;

        return false;
    }
}

void solve(){
    cin >> m;
    m *= 3;
    Graph::genGraph();
    SCC::genGroups();
    if(!DAG::solve()) res = "";
}

int main(){
    cin.sync_with_stdio(0); cin.tie(0);
    int t; cin >> t;

    while(t--){
        solve();
        if(res.empty()) cout << "NIE\n";
        else {
            cout << "TAK\n" << res << '\n';

            m *= 3;
            assert(m == SZ(res));
            vi pref(m+1);
            FR(i, m) pref[i+1] = pref[i] + res[i];

            FR(i, q){
                auto [a, b] = queries[i].fs;
                auto [c, d] = queries[i].sn;
                bool good1 = pref[b]-pref[a] == (b-a)*'R';
                bool good2 = pref[d]-pref[c] == (d-c)*'F';
                if(!good1 && !good2){
                    FR(j, q) cerr << queries[j] << '\n';
                    assert(false);
                }
            }
        }

        FR(i, n) adjList[i].clear();
        FR(i, gi) gAdjList[i].clear(), rgAdjList[i].clear(), groups[i].clear();
        gi = 0;
    }
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 0
Wrong Answer
time: 2ms
memory: 16056kb

input:

2
1 3
1 1 2 2
1 2 3 3
1 1 3 3
1 3
1 1 2 2
2 2 3 3
3 3 1 1

output:

NIE
NIE

result:

wrong answer zla odpowiedz!