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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#465731#8780. Training, Round 2GeothermalWA 59ms199140kbC++202.3kb2024-07-07 06:53:292024-07-07 06:53:30

Judging History

你现在查看的是最新测评结果

  • [2024-07-07 06:53:30]
  • 评测
  • 测评结果:WA
  • 用时:59ms
  • 内存:199140kb
  • [2024-07-07 06:53:29]
  • 提交

answer

#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> pi;
typedef pair<ll, ll> pl;
typedef pair<ld, ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;

#define FOR(i, a, b) for (int i = a; i < (b); i++)
#define F0R(i, a) for (int i = 0; i < (a); i++)
#define FORd(i, a, b) for (int i = (b) - 1; i >= (a); i--)
#define F0Rd(i, a) for (int i = (a) - 1; i >= 0; i--)
#define trav(a, x) for (auto &a : x)
#define sz(x) (int)(x).size()
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
#define ins insert

const char nl = '\n';

int bst1[5002][5002], bst2[5002][5002];
void solve() {
    int N, B1, B2; cin >> N >> B1 >> B2;
    int X1[N], X2[N], Y1[N], Y2[N];
    F0R(i, N) cin >> X1[i] >> X2[i] >> Y1[i] >> Y2[i];
    F0R(i, N) {
        X1[i] -= B1; X2[i] -= B1;
        Y1[i] -= B1; Y2[i] -= B2;
    }
    bst1[0][0] = 0;
    bst2[0][0] = 0;
    FOR(i, 1, N+1) bst1[0][i] = -1000000007;
    FOR(i, 1, N+1) bst2[0][i] = -1000000007;
    F0R(i, N) {
        F0R(j, N+1) {
            bst1[i+1][j] = bst1[i][j];
            bst2[i+1][j] = bst2[i][j];
        }
        F0R(j, N+1) {
            if (j >= X1[i] && j <= X2[i] && bst1[i][j] >= Y1[i] && bst1[i][j] <= Y2[i]) {
                bst1[i+1][j] = max(bst1[i+1][j],bst1[i][j]+1);
                bst1[i+1][j+1] = max(bst1[i+1][j+1], bst1[i][j]);
                bst2[i+1][bst1[i][j]] = max(bst2[i+1][bst1[i][j]], j+1);
                bst2[i+1][bst1[i][j]+1] = max(bst2[i+1][bst1[i][j]+1], j);
            }
            if (j >= Y1[i] && j <= Y2[i] && bst2[i][j] >= X1[i] && bst2[i][j] <= X2[i]) {
                bst2[i+1][j] = max(bst2[i+1][j],bst2[i][j]+1);
                bst2[i+1][j+1] = max(bst2[i+1][j+1], bst2[i][j]);
                bst1[i+1][bst2[i][j]] = max(bst1[i+1][bst2[i][j]], j+1);
                bst1[i+1][bst2[i][j]+1] = max(bst1[i+1][bst2[i][j]+1], j);
            }
        }
    }

    int ans = 0;
    F0R(i, N+1) {
        ans = max(ans, bst1[N][i] + i);
        ans = max(ans, bst2[N][i] + i);
    }
    cout << ans << nl;
}

int main() {
	ios_base::sync_with_stdio(0); cin.tie(0);
	solve();
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 5572kb

input:

3 0 0
0 1 0 1
1 1 0 1
1 1 1 1

output:

3

result:

ok single line: '3'

Test #2:

score: -100
Wrong Answer
time: 59ms
memory: 199140kb

input:

5000 801577551 932138594
801577551 801577551 932138594 932138594
801577552 801577552 932138594 932138594
801577552 801577552 932138595 932138595
801577552 801577552 932138596 932138596
801577553 801577553 932138596 932138596
801577553 801577553 932138597 932138597
801577553 801577553 932138598 93213...

output:

0

result:

wrong answer 1st lines differ - expected: '5000', found: '0'