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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#464502 | #7895. Graph Partitioning 2 | Andyqian7 | TL | 0ms | 40144kb | C++14 | 2.9kb | 2024-07-06 10:29:33 | 2024-07-06 10:29:34 |
Judging History
answer
#include <bits/stdc++.h>
#define pb push_back
using namespace std;
const int MAX = 3e5 + 10, mod = 998244353;
int T, n, k, sz[MAX], cnt[MAX];
vector<int> nei[MAX], sons[MAX], dp[MAX];
map<int, int> dp2[MAX];
void getsz(int s)
{
sz[s] = 1;
for (int son : nei[s])
{
if (sz[son])
continue;
sons[s].pb(son);
getsz(son);
sz[s] += sz[son];
}
}
void dfs(int s)
{
dp[s].resize(2);
dp[s][1] = 1;
int cnt1 = 0, cnt2 = 0;
for (int son : sons[s])
{
dfs(son);
dp[s].resize(dp[s].size() + dp[son].size());
for (int i = min(k + 1, (int)dp[s].size() - 1); i > 0; i--)
{
for (int j = min(k + 1, (int)dp[son].size() - 1); j > 0; j--)
{
if (i + j <= min(k + 1, (int)dp[s].size() - 1))
{
dp[s][i + j] = (dp[s][i + j] + 1ll * dp[s][i] * dp[son][j]) % mod;
}
}
dp[s][i] = 1ll * dp[s][i] * dp[son][0] % mod;
}
}
if (k + 1 < dp[s].size())
dp[s][0] = (dp[s][k] + dp[s][k + 1]) % mod;
else if (k < dp[s].size())
{
dp[s][0] = dp[s][k];
}
}
void dfs2(int s)
{
dp2[s][1] = 1;
int cnt1 = 0, cnt2 = 0;
for (int son : sons[s])
{
dfs2(son);
for (auto i = dp2[s].rbegin(); i != dp2[s].rend(); i++)
{
for (auto j = dp2[son].rbegin(); j != dp2[son].rend(); j++)
{
if (j->first == 0)
continue;
dp2[s][i->first + j->first] = (dp2[s][i->first + j->first] + 1ll * dp2[s][i->first] * dp2[son][j->first]) % mod;
}
dp2[s][i->first] = 1ll * dp2[s][i->first] * dp2[son][0] % mod;
}
}
if (dp2[s].count(k))
dp2[s][0] = (dp2[s][0] + dp2[s][k]) % mod;
if (dp2[s].count(k + 1))
dp2[s][0] = (dp2[s][0] + dp2[s][k + 1]) % mod;
}
int main()
{
cin >> T;
while (T--)
{
cin >> n >> k;
if (k < sqrt(n))
{
for (int i = 1; i <= n; i++)
{
sz[i] = 0;
nei[i].clear(), sons[i].clear(), dp[i].clear();
}
for (int i = 0; i < n - 1; i++)
{
int u, v;
cin >> u >> v;
nei[u].pb(v), nei[v].pb(u);
}
getsz(1), dfs(1);
cout << dp[1][0] << endl;
}
else
{
for (int i = 1; i <= n; i++)
{
sz[i] = 0;
nei[i].clear(), sons[i].clear(), dp2[i].clear();
}
for (int i = 0; i < n - 1; i++)
{
int u, v;
cin >> u >> v;
nei[u].pb(v), nei[v].pb(u);
}
getsz(1), dfs2(1);
cout << dp2[1][0] << endl;
}
}
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 40144kb
input:
2 8 2 1 2 3 1 4 6 3 5 2 4 8 5 5 7 4 3 1 2 1 3 2 4
output:
2 1
result:
ok 2 lines
Test #2:
score: -100
Time Limit Exceeded
input:
5550 13 4 10 3 9 1 10 8 3 11 8 5 10 7 9 6 13 5 9 7 2 7 5 12 4 8 8 2 4 1 3 4 7 8 2 5 6 7 4 8 2 3 11 1 11 10 1 4 9 10 8 4 3 6 5 7 6 1 10 2 11 7 11 1 17 2 14 16 13 15 17 3 15 11 1 6 13 2 13 17 4 8 14 10 8 14 14 5 9 12 14 2 12 17 17 6 15 7 14 6 2 14 2 13 2 4 8 4 3 11 7 3 14 1 11 9 13 3 5 10 6 8 3 10 14 ...