QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#462626 | #8339. Rooted Tree | castc | TL | 148ms | 13116kb | C++20 | 808b | 2024-07-03 22:21:09 | 2024-07-03 22:21:10 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
#define int long long
const int N=5e7+10,M=1e9+9;
int ny[N],dp[N],zt[N],maxx,f[N];
int ksm(int a, int n, int p) {
int ans = 1;
while(n) {
if(n & 1) {
ans = ans % p * a % p;
}
a = a % p * a % p;
n >>= 1;
}
return ans;
}
signed main(){
int m,k;
cin>>m>>k;
f[0]=1;
for(int i=1;i<=k;i++){
f[i]=f[i-1]-1+m;
}
dp[0]=0;
ny[1]=1;
for(int i=1;i<=k;i++){
int zqx=ksm(f[i],M-2,M);
dp[i]=((dp[i-1]*f[i-1])%M*zqx%M-(dp[i-1]*zqx%M)+M)%M+m*dp[i-1]%M*zqx%M+m*zqx%M;
dp[i]%=M;
}
int ans1=dp[k]*f[k]%M;
for(int i=1;i<k;i++){
ans1+=dp[i];
ans1%=M;
}
cout<<ans1<<endl;
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 3488kb
input:
6 2
output:
18
result:
ok 1 number(s): "18"
Test #2:
score: 0
Accepted
time: 0ms
memory: 3532kb
input:
2 6
output:
600000038
result:
ok 1 number(s): "600000038"
Test #3:
score: 0
Accepted
time: 148ms
memory: 13116kb
input:
83 613210
output:
424200026
result:
ok 1 number(s): "424200026"
Test #4:
score: -100
Time Limit Exceeded
input:
48 6713156
output:
198541581