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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#461690#8834. Formal Fringucup-team3678AC ✓67ms12116kbC++14798b2024-07-02 22:46:062024-07-02 22:46:08

Judging History

你现在查看的是最新测评结果

  • [2024-07-02 22:46:08]
  • 评测
  • 测评结果:AC
  • 用时:67ms
  • 内存:12116kb
  • [2024-07-02 22:46:06]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

const int N = 1e6 + 5, P = 998244353;

int f[N], g[N], h[N];

signed main() {
    int n; scanf("%d", &n);
    g[0] = 1;
    for (int i = 1; i <= n; ++i) {
        if (i & 1) g[i] = g[i - 1];
        else ((g[i] = g[i - 1] + g[i >> 1]) >= P) && (g[i] -= P);
    }
    for (int i = 1; i <= 19; ++i) {
        h[i] = g[(1 << i) - 1];
        for (int j = 1; j < i; ++j) h[i] = (h[i] + 1ll * (P - h[j]) * g[(1 << (i - j)) - 1]) % P;
    }
    for (int i = 1, k = 0; i <= n; ++i) {
        while ((1 << (k + 1)) <= i) ++k;
        for (int j = k; ~j && ((i >> j) & 1); --j) {
            f[i] = (f[i] + 1ll * g[i & ((1 << j) - 1)] * h[k - j + 1]) % P;
        }
        printf("%d%c", f[i], " \n"[i == n]);
    }
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 6028kb

input:

10

output:

1 1 2 1 1 3 6 1 1 2

result:

ok 10 numbers

Test #2:

score: 0
Accepted
time: 1ms
memory: 5980kb

input:

70

output:

1 1 2 1 1 3 6 1 1 2 2 5 5 11 26 1 1 2 2 4 4 6 6 11 11 16 16 27 27 53 166 1 1 2 2 4 4 6 6 10 10 14 14 20 20 26 26 37 37 48 48 64 64 80 80 107 107 134 134 187 187 353 1626 1 1 2 2 4 4 6

result:

ok 70 numbers

Test #3:

score: 0
Accepted
time: 67ms
memory: 12116kb

input:

1000000

output:

1 1 2 1 1 3 6 1 1 2 2 5 5 11 26 1 1 2 2 4 4 6 6 11 11 16 16 27 27 53 166 1 1 2 2 4 4 6 6 10 10 14 14 20 20 26 26 37 37 48 48 64 64 80 80 107 107 134 134 187 187 353 1626 1 1 2 2 4 4 6 6 10 10 14 14 20 20 26 26 36 36 46 46 60 60 74 74 94 94 114 114 140 140 166 166 203 203 240 240 288 288 336 336 400 ...

result:

ok 1000000 numbers

Extra Test:

score: 0
Extra Test Passed