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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#460638 | #7103. Red Black Tree | Shayan86 | WA | 871ms | 37496kb | C++23 | 5.7kb | 2024-07-01 23:25:42 | 2024-07-01 23:25:43 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
// Ofast, O0, O1, O2, O3, unroll-loops, fast-math, trapv
typedef long long ll;
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;
#define Mp make_pair
#define sep ' '
#define endl '\n'
#define F first
#define S second
#define pb push_back
#define SZ(x) (int)x.size()
#define all(x) (x).begin(),(x).end()
#define kill(res) cout << res << '\n', exit(0);
#define set_dec(x) cout << fixed << setprecision(x);
#define fast_io ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define file_io freopen("input.txt", "r", stdin) ; freopen("output.txt", "w", stdout);
#define lid (id*2)
#define rid (id*2+1)
#define mid ((l+r)/2)
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const ll L = 20;
const ll N = 1e5 + 50;
const ll inf = 1e18;
ll n, m, q, red[N], h[N], dist[N], st[N], ft[N], timer, anc[N], par[N][L];
vector<pii> adj[N];
void dfs(int v, int p = 0){
if(red[v]) anc[v] = v;
else anc[v] = anc[p];
par[v][0] = p;
for(int i = 1; i < L; i++){
if(!par[v][i-1]) break;
par[v][i] = par[par[v][i-1]][i-1];
}
st[v] = timer++;
for(auto [u, w]: adj[v]){
if(u == p) continue;
h[u] = h[v] + w;
dist[u] = dist[v] + 1;
dfs(u, v);
}
ft[v] = timer;
}
int getPar(int v, int k){
for(int i = 0; i < L; i++) if(k >> i & 1) v = par[v][i];
return v;
}
int lca(int u, int v){
if(dist[u] > dist[v]) swap(u, v);
v = getPar(v, dist[v] - dist[u]);
if(u == v) return v;
for(int i = L-1; i >= 0; i--){
if(par[v][i] != par[u][i]){
v = par[v][i]; u = par[u][i];
}
}
return par[v][0];
}
/*
vector<pll> g[N];
vector<int> child[N];
ll seg[3][N*4], res;
void upd(int i, int x, ll y, int l = 0, int r = n, int id = 1){
if(l+1 == r){
seg[i][id] = y; return;
}
if(x < mid) upd(i, x, y, l, mid, lid);
else upd(i, x, y, mid, r, rid);
seg[i][id] = max(seg[i][lid], seg[i][rid]);
}
ll get(int i, int ql, int qr, int l = 0, int r = n, int id = 1){
if(ql <= l && r <= qr) return seg[i][id];
if(qr <= l || r <= ql) return -inf;
return max(get(i, ql, qr, l, mid, lid), get(i, ql, qr, mid, r, rid));
}
void calc(int v){
for(int u: child[v]){
upd(1, st[u], h[u]);
upd(2, st[u], -inf);
}
ll th = max(max(get(2, st[v], ft[v]), get(1, st[v], ft[v]) - h[v]), max(get(0, 0, st[v]), get(0, ft[v], n)));
res = min(res, th);
for(auto [u, w]: g[v]) calc(u);
for(int u: child[v]){
upd(1, st[u], -inf);
upd(2, st[u], h[u] - h[anc[u]]);
}
}
*/
/*
void Main(){
cin >> n >> m >> q;
for(int i = 1; i <= m; i++){
int x; cin >> x; red[x] = 1;
}
for(int i = 1; i < n; i++){
int u, v, w;
cin >> u >> v >> w;
adj[u].pb({v, w});
adj[v].pb({u, w});
}
timer = 0; dfs(1);
for(int i = 0; i < 3; i++) for(int j = 0; j < n; j++) upd(i, j, -inf);
for(int i = 1; i <= q; i++){
int k;
cin >> k;
vector<int> vec, imp;
for(int j = 1; j <= k; j++){
int x; cin >> x;
imp.pb(x);
vec.pb(x); vec.pb(anc[x]);
child[anc[x]].pb(x);
}
sort(all(vec), [&](int i, int j){return st[i] < st[j];});
vector<int> vc;
for(int j = 0; j < SZ(vec) - 1; j++){
vc.pb(vec[j]); vc.pb(lca(vec[j], vec[j+1]));
}
vc.pb(vec.back());
sort(all(vc), [&](int i, int j){return st[i] < st[j];});
vc.resize(unique(all(vc)) - vc.begin());
vec = vc;
vector<int> sta;
while(!vc.empty()){
int v = vc.back(); vc.pop_back();
while(!sta.empty() && ft[sta.back()] <= ft[v]){
g[v].pb({sta.back(), h[v] - h[sta.back()]});
sta.pop_back();
}
sta.pb(v);
}
int root = sta.back();
for(int j: imp){
upd(0, st[j], h[j] - h[anc[j]]);
upd(2, st[j], h[j] - h[anc[j]]);
}
res = inf; calc(root);
cout << res << endl;
for(int j: vec){
child[j].clear(); g[j].clear();
upd(0, st[j], -inf);
upd(2, st[j], -inf);
}
}
for(int i = 1; i <= n; i++){
adj[i].clear(); red[i] = 0;
}
}
*/
void Main(){
cin >> n >> m >> q;
for(int i = 1; i <= m; i++){
int x; cin >> x; red[x] = 1;
}
for(int i = 1; i < n; i++){
int u, v, w;
cin >> u >> v >> w;
adj[u].pb({v, w});
adj[v].pb({u, w});
}
timer = 0; dfs(1);
for(int id = 1; id <= q; id++){
int k; cin >> k;
vector<pll> vec;
for(int i = 1; i <= k; i++){
int x; cin >> x;
vec.pb({h[x] - h[anc[x]], x});
}
sort(all(vec));
reverse(all(vec));
vec.pb({0, 0});
ll res = vec[1].F, mx = h[vec[0].S], v = vec[0].S;
for(int i = 1; i < k; i++){
v = lca(v, vec[i].S);
mx = max(mx, h[vec[i].S]);
res = min(res, max(vec[i+1].F, mx - h[v]));
}
cout << res << endl;
}
for(int i = 1; i <= n; i++){
adj[i].clear(); red[i] = 0;
}
}
int main(){
fast_io;
int T;
cin >> T;
while(T--){
Main();
}
}
詳細信息
Test #1:
score: 100
Accepted
time: 2ms
memory: 11924kb
input:
2 12 2 4 1 9 1 2 1 2 3 4 3 4 3 3 5 2 2 6 2 6 7 1 6 8 2 2 9 5 9 10 2 9 11 3 1 12 10 3 3 7 8 4 4 5 7 8 4 7 8 10 11 3 4 5 12 3 2 3 1 2 1 2 1 1 3 1 1 1 2 1 2 3 1 2 3
output:
4 5 3 8 0 0 0
result:
ok 7 lines
Test #2:
score: -100
Wrong Answer
time: 871ms
memory: 37496kb
input:
522 26 1 3 1 1 4 276455 18 6 49344056 18 25 58172365 19 9 12014251 2 1 15079181 17 1 50011746 8 9 2413085 23 24 23767115 22 2 26151339 26 21 50183935 17 14 16892041 9 26 53389093 1 20 62299200 24 18 56114328 11 2 50160143 6 26 14430542 16 7 32574577 3 16 59227555 3 15 8795685 4 12 5801074 5 20 57457...
output:
148616264 148616264 0 319801028 319801028 255904892 317070839 1265145897 1265145897 1072765445 667742619 455103436 285643094 285643094 285643094 317919339 0 785245841 691421476 605409472 479058444 371688030 303203698 493383271 919185207 910180170 919185207 121535083 181713164 181713164 181713164 181...
result:
wrong answer 209th lines differ - expected: '346455869', found: '393616414'