QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#458356 | #8831. Chemistry Class | ucup-team956# | TL | 0ms | 3528kb | C++20 | 2.9kb | 2024-06-29 16:49:01 | 2024-06-29 16:49:05 |
Judging History
answer
#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
using namespace std;
#define SZ(x) ((int)((x).size()))
#define lb(x) ((x) & (-(x)))
#define bp(x) __builtin_popcount(x)
#define bpll(x) __builtin_popcountll(x)
#define mkp make_pair
#define pb push_back
#define fi first
#define se second
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> pii;
typedef pair<ll, int> pli;
typedef pair<ll, ll> pll;
typedef pair<double, int> pdi;
const int INF = 0x3f3f3f3f;
void solve() {
int n; ll A, B;
cin >> n >> A >> B;
vector a(2 * n + 1, 0ll);
for (int i = 1; i <= 2 * n; i++) {
cin >> a[i];
}
sort(a.begin() + 1, a.begin() + 2 * n + 1);
for (int i = 1; i <= 2 * n; i += 2) {
if (a[i + 1] - a[i] > A) {
cout << -1 << '\n';
return ;
}
}
vector sum(2, vector(2 * n + 1, 0));
for (int i = 2; i <= 2 * n; i++) {
sum[i & 1][i] = sum[i & 1][i - 2] + (a[i] - a[i - 1] <= B ? 1 : 0);
}
vector f(2 * n + 1, vector(2, -INF));
f[0][0] = 0;
// brute force DP
for (int i = 2; i <= 2 * n; i++) {
f[i][0] = f[i - 2][0] + (sum[i & 1][i] - sum[i & 1][i - 2]);
for (int j = 1; j < i - 1; j++) {
if (!((i ^ j) & 1)) {
continue;
}
if (a[i] - a[j] > A) {
continue;
}
f[i][1] = max(f[i][1], max(f[j - 1][0], f[j - 1][1]) + sum[j & 1][i - 1] - sum[j & 1][j]);
}
}
// auto calc = [&](int p) -> int {
// return max(f[p - 1][0], f[p - 1][1]) - sum[p & 1][p];
// };
// deque<int> q0, q1;
// q1.push_back(1);
// for (int i = 2; i <= 2 * n; i++) {
// f[i][0] = f[i - 2][0] + (sum[i & 1][i] - sum[i & 1][i - 2]);
// while (!q0.empty() && a[i] - a[q0.front()] > A) {
// q0.pop_front();
// }
// while (!q1.empty() && a[i] - a[q1.front()] > A) {
// q1.pop_front();
// }
// if ((i & 1) && q0.empty()) {
// //
// } else if (!(i & 1) && q1.empty()) {
// //
// } else {
// int j = (i & 1) ? q0.front() : q1.front();
// f[i][1] = calc(j) + sum[j & 1][i - 1];
// }
// if (i & 1) {
// while (!q1.empty() && calc(q1.back()) < calc(i)) {
// q1.pop_back();
// }
// q1.push_back(i);
// } else {
// while (!q0.empty() && calc(q0.back()) < calc(i)) {
// q0.pop_back();
// }
// q0.push_back(i);
// }
// }
int ans = max(f[2 * n][0], f[2 * n][1]);
cout << ans << '\n';
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0), cout.tie(0);
int T;
cin >> T;
while (T--) solve();
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3528kb
input:
4 1 2 1 42 69 2 3 1 1 2 3 4 2 5 1 6 1 3 4 5 19 1 1 7 8 9 10 11 12 13 14 20
output:
-1 2 1 4
result:
ok 4 number(s): "-1 2 1 4"
Test #2:
score: -100
Time Limit Exceeded
input:
1 199996 67013419502794 1 403716252634677166 895717933735068492 410002430455111886 844431179242134559 322988383133810700 133475121268220299 481706326769800263 606871141911985391 195911124687409946 959578180866483093 930547702157856949 877914383714875160 994158366044742636 890855755285236186 69498488...