#include<iostream>
#include<algorithm>
#incllude<math.h>
using namespace std;
#define int long long
const int N = 2e5 + 5, p = 1e9 + 7;
pair<int, int> nums[N], heap[N];
int ans, arr[N]; long double Logarr[N];
bool smaller(pair<int, int> a, pair<int, int> b)
{
double x = log2(nums[a.first].first) + nums[a.first].second;
double y = log2(nums[b.first].first) + nums[b.first].second;
if (x < y) return true; else return false;
}
void heapInsert(int idx)
{
while (idx != 0 && smaller(heap[idx], heap[idx / 2]))
{
pair<int, int> tmp = heap[idx]; heap[idx] = heap[idx / 2];
heap[idx / 2] = tmp; idx = idx / 2;
}
}
void heapify(int idx, int size)
{
int l = 2 * idx;
while (l <= size)
{
int mini = l + 1 <= size && smaller
(heap[l + 1], heap[l]) ? l + 1 : l;
if (smaller(heap[idx], heap[mini])) break;
pair<int, int> tmp = heap[mini]; heap[mini] = heap[idx];
heap[idx] = tmp; idx = mini; l = 2 * idx;
}
}
int power(int a, int b)
{
int tmp = 2, ans = 1;
while (b > 0)
{
if (b % 2) ans = (ans * tmp) % p;
tmp = (tmp * tmp) % p; b /= 2;
}
return (a * ans) % p;
}
//小根堆维护最小值
//signed main()
//{
// int n, k; cin >> n >> k;
// for (int i = 1; i <= n; i++)
// {
// cin >> nums[i].first;
// nums[i].second = 0;
// heap[i] = { i, nums[i].first };
// heapInsert(i);
// }
//
// for (int i = 0; i < k; i++)
// {
// //时间复杂度O(k*logn),k比较大时无法在时限内得到结果
// heap[1].second = (heap[1].second * 2) % p;
// nums[heap[1].first].second++; heapify(1, n);
// }
//
// for (int i = 1; i <= n; i++)
// {
// ans += heap[i].second; ans %= p;
// }
// cout << ans;
//
// return 0;
//}
signed main()
{
int n, k; cin >> n >> k;
for (int i = 1; i <= n; i++)
{
cin >> arr[i];
}
sort(arr + 1, arr + n + 1);
for (int i = 1; i <= n; i++)
{
Logarr[i] = log2l(arr[i]);
}
int stop = n, times = 0;
int left = 1, right = n;
while (left <= right)
{
int sum = 0;
int mid = (left + right) / 2;
for (int i = 1; i < mid; i++)
{
sum += floor(Logarr[mid] - Logarr[i]);
}
if (sum <= k)
{
left = mid + 1; stop = mid; times = k - sum;
}
else
{
right = mid - 1;
}
}
for (int i = 1; i < stop; i++)
{
arr[i] = power(arr[i], floor(Logarr[stop] - Logarr[i]));
}
sort(arr + 1, arr + stop + 1);
int t = times / stop, s = times - t * stop;
for (int i = 1; i <= stop; i++)
{
if (i <= s) arr[i] = power(arr[i], t + 1);
else arr[i] = power(arr[i], t);
}
for (int i = 1; i <= n; i++)
{
ans += arr[i]; ans %= p;
}
cout << ans;
return 0;
}