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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#457301 | #8834. Formal Fring | ucup-team3510# | AC ✓ | 86ms | 7724kb | C++14 | 738b | 2024-06-29 10:17:20 | 2024-06-29 10:17:23 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 2e6 + 5, mod = 998244353;
int f[N], g[21];
int main()
{
int n, i, j, l, ans;
scanf("%d", &n);
f[0] = 1;
for(i = 0; i <= 20; i++)
for(j = (1 << i); j <= n; j++)
f[j] = (f[j] + f[j - (1 << i)]) % mod;
for(i = 1; i <= 20; i++)
{
g[i] = f[(1 << i) - 1];
for(j = 1; j < i; j++)
g[i] = (g[i] + (ll)(mod - g[j]) * f[(1 << (i - j)) - 1]) % mod;
}
for(i = 1; i <= n; i++)
{
l = ans = 0;
while(i >> (l + 1))
l++;
for(j = l; j >= 0; j--)
{
if(!((i >> j) & 1))
break;
ans = (ans + (ll)g[l - j + 1] * f[i & ((1 << j) - 1)]) % mod;
}
printf("%d ", ans);
}
printf("\n");
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3716kb
input:
10
output:
1 1 2 1 1 3 6 1 1 2
result:
ok 10 numbers
Test #2:
score: 0
Accepted
time: 0ms
memory: 3732kb
input:
70
output:
1 1 2 1 1 3 6 1 1 2 2 5 5 11 26 1 1 2 2 4 4 6 6 11 11 16 16 27 27 53 166 1 1 2 2 4 4 6 6 10 10 14 14 20 20 26 26 37 37 48 48 64 64 80 80 107 107 134 134 187 187 353 1626 1 1 2 2 4 4 6
result:
ok 70 numbers
Test #3:
score: 0
Accepted
time: 86ms
memory: 7724kb
input:
1000000
output:
1 1 2 1 1 3 6 1 1 2 2 5 5 11 26 1 1 2 2 4 4 6 6 11 11 16 16 27 27 53 166 1 1 2 2 4 4 6 6 10 10 14 14 20 20 26 26 37 37 48 48 64 64 80 80 107 107 134 134 187 187 353 1626 1 1 2 2 4 4 6 6 10 10 14 14 20 20 26 26 36 36 46 46 60 60 74 74 94 94 114 114 140 140 166 166 203 203 240 240 288 288 336 336 400 ...
result:
ok 1000000 numbers
Extra Test:
score: 0
Extra Test Passed