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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#456968#7108. Couleurucup-team3282AC ✓2985ms60528kbC++142.8kb2024-06-28 19:12:342024-06-28 19:12:35

Judging History

你现在查看的是最新测评结果

  • [2024-06-28 19:12:35]
  • 评测
  • 测评结果:AC
  • 用时:2985ms
  • 内存:60528kb
  • [2024-06-28 19:12:34]
  • 提交

answer

#include <bits/stdc++.h>
#define int long long
using namespace std;
const int N = 1e5+9;
int root[N], n, a[N];
map<int, int> rev;// rev[a] stands for the rev of range beginning at id [a + 1] 
multiset<int> s;
struct ChairmanTree {
	int sum[N << 5], ch[N << 5][2], tot = 0;
	int newnode() {
		tot++;
		sum[tot] = 0; ch[tot][0] = ch[tot][1] = 0;
		return tot;
	}
	
	void add(int id, int l, int r, int old, int pos) {
		sum[id] = sum[old]; ch[id][0] = ch[old][0]; ch[id][1] = ch[old][1];
		int mid = (l + r) >> 1;
		if (l == r) {sum[id]++; return;}
		if (pos <= mid) add(ch[id][0] = newnode(), l, mid, ch[old][0], pos);
		else add(ch[id][1] = newnode(), mid + 1, r, ch[old][1], pos);
		sum[id] = sum[ch[id][0]] + sum[ch[id][1]];
	}
	
	int query(int id, int l, int r, int cl, int cr) {
		if (cl > cr) return 0;
		if (cl <= l && r <= cr) return sum[id];
		int mid = (l + r) >> 1, res = 0;
		if (cl <= mid) res += query(ch[id][0], l, mid, cl, cr);
		if (mid < cr) res += query(ch[id][1], mid + 1, r, cl, cr);
		return res; 
	}
} T;

void split(int l, int r, int x) {
	int old = rev[l]; s.erase(s.find(old));
	int ax = T.query(root[r - 1], 1, n, 1, a[x] - 1) - T.query(root[x], 1, n, 1, a[x] - 1)
				 + T.query(root[x - 1], 1, n, a[x] + 1, n) - T.query(root[l], 1, n, a[x] + 1, n);
	if (x - l < r - x) {
		int one = 0, two = ax;//one is the rev of left; two is right
		for (int i = l + 1; i < x; i++) {
			one += T.query(root[i - 1], 1, n, a[i] + 1, n) - T.query(root[l], 1, n, a[i] + 1, n);
			two += T.query(root[r - 1], 1, n, 1, a[i] - 1) - T.query(root[x], 1, n, 1, a[i] - 1);
		}
		
		rev[l] = one; rev[x] = old - one - two; s.insert(rev[l]); s.insert(rev[x]);
	}
	
	else {
		int one = 0, two = ax;//one is the rev of right; two is left
		for (int i = x + 1; i < r; i++) {
			one += T.query(root[i - 1], 1, n, a[i] + 1, n) - T.query(root[x], 1, n, a[i] + 1, n);
			two += T.query(root[x - 1], 1, n, a[i] + 1, n) - T.query(root[l], 1, n, a[i] + 1, n);
		}
		
		rev[l] = old - one - two; rev[x] = one; s.insert(rev[l]); s.insert(rev[x]);
	}
}

void solve() {
	T.tot = 0;
	cin >> n;
	for (int i = 1; i <= n; i++) cin >> a[i];
	for (int i = 1; i <= n; i++) T.add(root[i] = T.newnode(), 1, n, root[i - 1], a[i]);
	int ori = 0;
	for (int i = 1; i <= n; i++) ori += T.query(root[i - 1], 1, n, a[i] + 1, n);
	rev.clear(); rev[0] = ori; rev[n + 1] = 0;
	s.clear(); s.insert(ori); s.insert(0);
	int ans = 0;
	for (int i = 1; i <= n; i++) {
		ans = *prev(s.end()); cout << ans;
		if (i == n) cout << "\n";
		else cout << " ";
		int x; cin >> x;
		x ^= ans;
		auto it = prev(rev.lower_bound(x));
		split(it->first, next(it)->first, x);
	}
}

signed main() {
	//freopen("G.in", "r", stdin);
	ios::sync_with_stdio(false); cin.tie(nullptr);
	int T; cin >> T;
	while (T--) solve();
	return 0;
}

这程序好像有点Bug,我给组数据试试?

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 7700kb

input:

3
5
4 3 1 1 1
5 4 5 3 1
10
9 7 1 4 7 8 5 7 4 8
21 8 15 5 9 2 4 5 10 6
15
4 8 8 1 12 1 10 14 7 14 2 9 13 10 3
37 19 23 15 7 2 10 15 2 13 4 5 8 7 10

output:

7 0 0 0 0
20 11 7 2 0 0 0 0 0 0
42 31 21 14 14 4 1 1 1 0 0 0 0 0 0

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 2985ms
memory: 60528kb

input:

11116
10
10 5 10 3 6 4 8 5 9 8
31 27 24 11 12 3 0 2 3 1
10
8 2 7 2 8 10 1 10 9 10
6 5 2 13 2 1 0 1 3 1
10
7 10 7 6 1 3 10 6 7 9
21 18 10 1 6 5 4 8 9 10
10
2 10 4 8 8 5 7 2 6 7
20 10 9 1 15 0 4 2 9 7
10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
10
1 2 3 4 5 6 7 8 9 10
6 3 5 2 7 10 9 1 4 8
10
1 10 1 3...

output:

21 18 16 12 10 6 4 1 1 0
12 12 10 10 4 4 4 2 1 0
20 16 9 5 3 3 3 0 0 0
22 14 8 8 5 5 2 1 1 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
19 12 7 4 4 2 2 1 0 0
20 18 8 3 1 1 0 0 0 0
45 21 21 10 3 3 3 0 0 0
17 11 8 2 1 1 1 0 0 0
13 4 1 0 0 0 0 0 0 0
29 27 22 15 9 7 4 3 1 0
26 16 9 2 1 1 1 1 1 0
0 0 0 0 0 ...

result:

ok 11116 lines

Extra Test:

score: 0
Extra Test Passed