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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#456831#244. Turn Off The LightClHg2100 ✓303ms32576kbC++142.1kb2024-06-28 14:59:472024-06-28 14:59:48

Judging History

你现在查看的是最新测评结果

  • [2024-06-28 14:59:48]
  • 评测
  • 测评结果:100
  • 用时:303ms
  • 内存:32576kb
  • [2024-06-28 14:59:47]
  • 提交

answer

#include <bits/stdc++.h>

#define FOR(i, l, r) for (int i = l; i <= (r); ++i)
#define ROF(i, l, r) for (int i = r; i >= (l); --i)
#define rep(n) FOR (_, 1, n)
#define each(i, x) for (auto& i : x)

using namespace std;

using ll = long long;
using db = long double;
using str = string;

#define mp make_pair
#define f first
#define s second

#define ttt template <typename T
ttt > using V = vector<T>;
ttt, size_t n > using A = array<T, n>;

#define sz(x) int((x).size())
#define bg begin
#define all(x) bg(x), end(x)
#define rsz resize
#define pb push_back
#define eb emplace_back

#define il inline
ttt > il bool ckmin(T& x, const T& y) { return y < x ? x = y, true : false; }
ttt > il bool ckmax(T& x, const T& y) { return x < y ? x = y, true : false; }

constexpr int N = 1e6 + 5, mod = 1e9 + 7;
int n;
str s;
A<int, N> a, b, g;
A<A<int, 2>, N> f;
A<A<int, N>, 2> ans;

void proc() {
  cin >> n >> s;
  if (s == str(n, '0')) return void(cout << "0\n");
  FOR (stage, 0, 1) {
    FOR (i, 1, n) a[i] = s[i - 1] - '0';
    int l = n, r = 1;
    ROF (i, 1, n)
      if (a[i]) l = i;
    FOR (i, 1, n)
      if (a[i]) r = i;
    if (l == r) {
      ll h = 0;
      FOR (i, 1, n) h = (h + (ll)i * (i == l ? 3 : 2 * abs(i - l) - 1)) % mod;
      return void(cout << h << "\n");
    }
    f[r - 1] = {1, 2};
    ROF (i, 1, r - 2) {
      f[i][0] = 1 + f[i + 1][a[i + 1] ^ 1];
      f[i][1] = 3 + f[i + 1][a[i + 1]];
    }
    g[l] = 0, b[l] = a[l] ^ 1;
    FOR (i, l + 1, r - 1) {
      if (b[i - 1] == 0)
        b[i] = a[i], g[i] = g[i - 1] + 1;
      else
        b[i] = a[i] ^ 1, g[i] = g[i - 1] + 3;
    }
    FOR (i, 1, l) ans[stage][i] = f[i][a[i]];
    FOR (i, l + 1, r - 1)
      ans[stage][i] = i - l + g[i - 1] +
                      (b[i - 1] == 0 ? 1 + f[i][a[i] ^ 1] : 3 + f[i][a[i]]);
    fill(bg(ans[stage]) + r, bg(ans[stage]) + n + 1, 1e9);
    reverse(all(s));
  }
  ll h = 0;
  FOR (i, 1, n) h = (h + (ll)i * min(ans[0][i], ans[1][n - i + 1])) % mod;
  cout << h << "\n";
}
int main() {
  cin.tie(nullptr)->sync_with_stdio(false), cin.exceptions(cin.failbit);
  int t;
  cin >> t;
  rep (t) proc();
}

详细

Test #1:

score: 100
Accepted
time: 303ms
memory: 32576kb

input:

146645
2
00
2
10
2
01
2
11
3
000
3
100
3
010
3
110
3
001
3
101
3
011
3
111
4
0000
4
1000
4
0100
4
1100
4
0010
4
1010
4
0110
4
1110
4
0001
4
1001
4
0101
4
1101
4
0011
4
1011
4
0111
4
1111
5
00000
5
10000
5
01000
5
11000
5
00100
5
10100
5
01100
5
11100
5
00010
5
10010
5
01010
5
11010
5
00110
5
10110
5...

output:

0
5
7
6
0
14
10
12
14
24
12
26
0
34
22
36
18
40
20
38
26
60
40
58
24
62
42
60
0
69
47
66
33
80
50
83
31
90
60
93
34
87
57
80
45
120
90
123
64
117
87
110
42
123
93
120
67
118
88
129
0
123
89
126
63
128
86
125
49
150
108
147
70
153
111
152
51
168
126
165
88
171
129
170
54
165
123
168
85
154
112
159
73...

result:

ok 146645 lines