QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#455507#244. Turn Off The LightDecember456100 ✓229ms37732kbC++143.2kb2024-06-26 15:36:092024-06-26 15:36:10

Judging History

你现在查看的是最新测评结果

  • [2024-06-26 15:36:10]
  • 评测
  • 测评结果:100
  • 用时:229ms
  • 内存:37732kb
  • [2024-06-26 15:36:09]
  • 提交

answer

#include <algorithm>
#include <cstdio>

constexpr int MAXN = 1000000 + 2;
constexpr int P = 1000000007;

int pre[MAXN][2], suf[MAXN][2];
int pre_rev[MAXN][2], suf_rev[MAXN][2];
int sum[MAXN];

char s[MAXN];

inline void add(int &x, int y) {
    (x += y) >= P && (x -= P);
}

void solve() {
    int n, L, R, ans = 0;
    scanf("%d%s", &n, s + 1);

    for (L = 1; L <= n && s[L] == '0'; L ++);
    for (R = n; R && s[R] == '0'; R --);

    if (!R) {
        puts("0");
        return;
    }

    if (L == R) {
        for (int i = 1; i <= n; i ++) {
            if (i == L) {
                add(ans, 3 * L);
            } else {
                add(ans, ((abs(L - i) << 1) - 1ll) * i % P);
            }
        }

        printf("%d\n", ans);
        return;
    }

    for (int i = 1; i <= n; i ++) {
        sum[i] = sum[i - 1] + (s[i] ^ '0');
    }

    bool fl, tag;

    for (int i = 0; i < 2; i ++) {
        pre[L][i] = pre_rev[L][i] = 0;
    }
    for (int i = L + 1; i <= n; i ++) {
        fl = s[i] ^ '0' ^ 1;
        for (int j = 0; j < 2; j ++) {
            pre[i][j] = pre[i - 1][j ^ fl] + (j == fl);
            pre_rev[i][j] = pre_rev[i - 1][j];
        }
        pre_rev[i][(sum[i] - sum[L]) & 1] ++;
    }

    for (int i = 0; i < 2; i ++) {
        suf[R][i] = suf_rev[R][i] = 0;
    }
    for (int i = R - 1; i; i --) {
        fl = s[i] ^ '0' ^ 1;
        for (int j = 0; j < 2; j ++) {
            suf[i][j] = suf[i + 1][j ^ fl] + (j == fl);
            suf_rev[i][j] = suf_rev[i + 1][j];
        }
        suf_rev[i][(sum[R - 1] - sum[i - 1]) & 1] ++;
    }

    for (int i = 1; i < L; i ++) {
        tag = (R ^ i ^ sum[R] ^ sum[i] ^ 1) & 1;
        add(ans, i * (suf[i + 1][0] + 3ll * suf[i + 1][1] + tag) % P);
    }
    for (int i = R + 1; i <= n; i ++) {
        tag = (i ^ L ^ sum[i - 1] ^ sum[L]) & 1;
        add(ans, i * (pre[i - 1][0] + 3ll * pre[i - 1][1] + tag) % P);
    }

    if (L + 1 == R) {
        add(ans, (L + R) << 1);
        printf("%d\n", ans);
        return;
    }

    for (int i = L + 1; i < R; i ++) {
        fl = (sum[i - 1] ^ sum[L]) & 1;
        tag = (R ^ i ^ sum[R] ^ sum[i - 1] ^ fl) & 1;
        int cost = i - L + pre_rev[i - 1][0] + suf[i][fl] + tag
                     + 3 * (pre_rev[i - 1][1] + suf[i][fl ^ 1]);

        fl = (sum[R - 1] ^ sum[i]) & 1;
        tag = (i ^ L ^ sum[i] ^ sum[L] ^ fl ^ 1) & 1;
        cost = std::min(cost, R - i + suf_rev[i + 1][0] + tag
             + pre[i][fl] + 3 * (suf_rev[i + 1][1] + pre[i][fl ^ 1]));

        add(ans, (long long){i} * cost % P);
    }

    fl = s[L + 1] & 1;
    tag = (R ^ L ^ sum[R] ^ sum[L + 1] ^ fl) & 1;
    add(ans, L * (2ll + pre_rev[L + 1][0] + suf[L + 2][fl] + tag
               + 3 * (pre_rev[L + 1][1] + suf[L + 2][fl ^ 1])));

    fl = s[R - 1] & 1;
    tag = (R ^ L ^ sum[R - 2] ^ sum[L] ^ fl ^ 1) & 1;
    add(ans, R * (2ll + suf_rev[R - 1][0] + pre[R - 2][fl] + tag
               + 3 * (suf_rev[R - 1][1] + pre[R - 2][fl ^ 1])) % P);

    printf("%d\n", ans);
}

int main() {
    int T;
    scanf("%d", &T);

    while (T --) {
        solve();
    }

    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 229ms
memory: 37732kb

input:

146645
2
00
2
10
2
01
2
11
3
000
3
100
3
010
3
110
3
001
3
101
3
011
3
111
4
0000
4
1000
4
0100
4
1100
4
0010
4
1010
4
0110
4
1110
4
0001
4
1001
4
0101
4
1101
4
0011
4
1011
4
0111
4
1111
5
00000
5
10000
5
01000
5
11000
5
00100
5
10100
5
01100
5
11100
5
00010
5
10010
5
01010
5
11010
5
00110
5
10110
5...

output:

0
5
7
6
0
14
10
12
14
24
12
26
0
34
22
36
18
40
20
38
26
60
40
58
24
62
42
60
0
69
47
66
33
80
50
83
31
90
60
93
34
87
57
80
45
120
90
123
64
117
87
110
42
123
93
120
67
118
88
129
0
123
89
126
63
128
86
125
49
150
108
147
70
153
111
152
51
168
126
165
88
171
129
170
54
165
123
168
85
154
112
159
73...

result:

ok 146645 lines