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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#455047#8820. Exchanging Kubic 2275307894aRE 0ms0kbC++142.0kb2024-06-25 18:26:262024-06-25 18:26:27

Judging History

你现在查看的是最新测评结果

  • [2024-06-25 18:26:27]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:0kb
  • [2024-06-25 18:26:26]
  • 提交

answer

#include<bits/stdc++.h>
#define Gc() getchar()
#define Me(x,y) memset(x,y,sizeof(x))
#define Mc(x,y) memcpy(x,y,sizeof(x))
#define d(x,y) ((m)*(x-1)+(y))
#define R(n) (rnd()%(n)+1)
#define Pc(x) putchar(x)
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define eb emplace_back
#define all(x) x.begin(),x.end()
using namespace std;using ll=long long;using db=double;using lb=long db;using ui=unsigned;using ull=unsigned long long;using pii=pair<int,int>;
const int N=800+5,M=N*4+5,K=1000+5,mod=998244353,Mod=mod-1;const db eps=1e-9;const ll INF=1e18+7;mt19937 rnd(time(0));
#define Tp template<typename T>
#define Ts template<typename T,typename... Ar>
namespace Debug{
	Tp void _debug(char* f,T t){cerr<<f<<'='<<t<<endl;}
	Ts void _debug(char* f,T x,Ar... y){while(*f!=',') cerr<<*f++;cerr<<'='<<x<<",";_debug(f+1,y...);}
	#ifdef LOCAL
	#define gdb(...) _debug((char*)#__VA_ARGS__,__VA_ARGS__)
	#else 
	#define gdb(...) void()
	#endif
}using namespace Debug;
int n,m,vis[N][N],k=1200;
ll dp[N][1205][2],f[N][1205][2];
void add(ll &x,ll y){(x+=y)>=mod&&(x-=mod);}
void Solve(){
	int i,j;scanf("%d",&n);
	for(i=1;i<=n;i++){
		int len,x;scanf("%d",&len);
		while(len--) scanf("%d",&x),vis[i][x]=1;
	}
	for(i=0;i<=k;i++) if(vis[1][i]) dp[i][1][0]=1;
	for(i=2;i<=n;i++){
		for(j=0;j<=k;j++) for(int h=0;h<=k;h++) for(int o:{0,1}) add(dp[j+1][h+1][o],dp[j][h][o]);
		for(j=0;j<=k;j++) if(!vis[i][j]) Me(dp[j],0);
		
		for(j=0;j<=k;j++) for(int h=0;h<=k;h++){
			if(h<i){
				for(int o:{0,1}) add(dp[j][i][o],dp[j][h][o]),dp[j][h][o]=0;
			}
			if(h>n+i-1){
				// if(dp[j][h][0]) gdb(dp[j][h][0],i,h,n-i+1);
				add(dp[j][n+i-1][1],dp[j][h][0]*(h-(n+i-1))%mod);
				for(int o:{0,1}) add(dp[j][n+i-1][o],dp[j][h][o]),dp[j][h][o]=0;
			}
		}
	}
	ll ans=0;
	for(i=0;i<=k;i++) for(j=0;j<=k;j++) ans+=dp[i][j][1];
	printf("%lld\n",(ans%mod+mod)%mod);
}
int main(){
	int t=1;
	// scanf("%d",&t);
	while(t--) Solve();
	cerr<<clock()*1.0/CLOCKS_PER_SEC<<'\n';
}

詳細信息

Test #1:

score: 0
Runtime Error

input:

5
3 1 2 3
1 2
0
4 0 2 3 4
2 2 3

output:


result: