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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#450283#5422. Perfect PalindromearctanoAC ✓19ms3860kbC++141.5kb2024-06-22 07:26:452024-06-22 07:26:45

Judging History

你现在查看的是最新测评结果

  • [2024-06-22 07:26:45]
  • 评测
  • 测评结果:AC
  • 用时:19ms
  • 内存:3860kb
  • [2024-06-22 07:26:45]
  • 提交

answer

#include <algorithm>
#include <bitset>
#include <cassert>
#include <cctype>
#include <cerrno>
#include <cfloat>
#include <chrono>
#include <climits>
#include <cmath>
#include <complex>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <ctime>
#include <deque>
#include <exception>
#include <fstream>
#include <functional>
#include <iomanip>
#include <iostream>
#include <istream>
#include <iterator>
#include <limits>
#include <list>
#include <map>
#include <memory>
#include <new>
#include <numeric>
#include <ostream>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <stack>
#include <stdexcept>
#include <streambuf>
#include <string>
#include <tuple>
#include <typeinfo>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <valarray>
#include <vector>

using namespace std;

#define int long long
typedef long double ld;
typedef pair<int, int> pii;
#define pb push_back
#define all(x) x.begin(), x.end()
#define mp make_pair
#define L first
#define R second
#define endl "\n"

signed main() {
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    int t; cin>>t;
    while(t--){
        string S; cin >> S;
        map<char, int> m;
        for(int i = 0; i < S.length(); i++){
            m[S[i]]++;
        }
        int max = -1;
        for(auto e : m){
            if(e.R > max) max = e.R;
        }
        cout << S.length() - max << endl;
    }
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3568kb

input:

2
abcb
xxx

output:

2
0

result:

ok 2 number(s): "2 0"

Test #2:

score: 0
Accepted
time: 19ms
memory: 3860kb

input:

11107
lfpbavjsm
pdtlkfwn
fmb
hptdswsoul
bhyjhp
pscfliuqn
nej
nxolzbd
z
clzb
zqomviosz
u
ek
vco
oymonrq
rjd
ktsqti
mdcvserv
x
birnpfu
gsgk
ftchwlm
bzqgar
ovj
nsgiegk
dbolme
nvr
rpsc
fprodu
eqtidwto
j
qty
o
jknssmabwl
qjfv
wrd
aa
ejsf
i
npmmhkef
dzvyon
p
zww
dp
ru
qmwm
sc
wnnjyoepxo
hc
opvfepiko
inuxx...

output:

8
7
2
8
4
8
2
6
0
3
7
0
1
2
5
2
4
6
0
6
2
6
5
2
5
5
2
3
5
6
0
2
0
8
3
2
0
3
0
6
5
0
1
1
1
2
1
8
1
7
5
3
4
4
1
8
5
5
8
8
6
3
0
2
3
2
1
5
0
0
9
3
3
4
8
4
0
4
2
6
6
0
8
7
4
3
9
3
4
2
5
8
8
8
6
1
4
4
2
7
2
8
6
4
4
8
7
8
4
9
3
8
0
7
7
2
6
0
0
5
4
0
7
5
4
2
1
6
7
5
2
4
4
7
3
3
2
5
4
8
5
0
3
5
1
2
3
0
4
7
...

result:

ok 11107 numbers