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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#449789#8717. 骰子Andyqian7RE 2ms9760kbC++142.0kb2024-06-21 17:14:112024-06-21 17:14:11

Judging History

你现在查看的是最新测评结果

  • [2024-06-21 17:14:11]
  • 评测
  • 测评结果:RE
  • 用时:2ms
  • 内存:9760kb
  • [2024-06-21 17:14:11]
  • 提交

answer

#include <bits/stdc++.h>
#define int long long
const int mod = 1e9 + 7;
using namespace std;
int n, m, q, b[300], p[2000][300], zero[300], pre[2000][300], ipre[2000][300], pre2[2000][300];
int fp(int x, int k)
{
    if (!k)
        return 1;
    if (k & 1)
        return fp(x, k - 1) * x % mod;
    int tmp = fp(x, k >> 1);
    return tmp * tmp % mod;
}
int inv(int x)
{
    return fp(x, mod - 2);
}
void mul(int *a, int *b, int *c)
{
    for (int i = 0; i <= m; i++)
    {
        c[i] = 0;
        for (int j = 0; j <= i; j++)
        {
            c[i] += b[j] * a[i - j];
            c[i] %= mod;
        }
    }
}
void inv(int *a, int *b)
{
    b[0] = inv(a[0]);
    for (int i = 1; i <= m; i++)
    {
        b[i] = 0;
        for (int j = 0; j < i; j++)
        {
            b[i] += a[i - j] * b[j];
            b[i] %= mod;
        }
        b[i] = (mod - b[i]) * b[0] % mod;
    }
}
signed main()
{
    cin >> n >> m >> q;
    for (int i = 0; i <= m; i++)
    {
        cin >> b[m - i];
    }
    for (int i = 1; i <= n; i++)
    {
        bool sign = false;
        for (int j = 0; j <= m; j++)
        {
            int tmp;
            cin >> tmp;
            tmp %= mod;
            if (tmp)
                sign = true;
            if (sign)
            {
                p[i][j - zero[i]] = tmp;
            }
            else
            {
                zero[i]++;
            }
        }
        zero[i] += zero[i - 1];
    }
    ipre[0][0] = pre[0][0] = 1;
    for (int i = 1; i <= n; i++)
    {
        mul(pre[i - 1], p[i], pre[i]);
        inv(pre[i], ipre[i]);
        mul(pre[i], b, pre2[i]);
    }
    while (q--)
    {
        int l, r;
        cin >> l >> r;
        int ans = 0;
        for (int i = 0; i <= m - zero[r] + zero[l - 1]; i++)
        {
            ans += pre2[r][i] * ipre[l - 1][m - zero[r] + zero[l - 1] - i];
            ans %= mod;
        }
        cout << ans << endl;
    }
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 9760kb

input:

3 3 3
4 3 2 1
0 1 0 1000000007
0 500000004 0 500000004
0 0 500000004 500000004
1 1
1 2
1 3

output:

3
1
0

result:

ok 3 number(s): "3 1 0"

Test #2:

score: 0
Accepted
time: 2ms
memory: 9728kb

input:

3 3 6
4 3 2 1
1000000007 0 1 0
1000000007 1 0 0
1000000007 0 1 0
1 1
1 2
1 3
2 2
2 3
3 3

output:

2
1
0
3
1
2

result:

ok 6 numbers

Test #3:

score: 0
Accepted
time: 0ms
memory: 7736kb

input:

1 1 1
604063100 57375033
742299910 257700098
1 1

output:

148903503

result:

ok 1 number(s): "148903503"

Test #4:

score: -100
Runtime Error

input:

1500 200 600000
253665324 876103781 804024983 929290295 908790466 176299158 528078340 696679927 416465140 509641654 705083449 361711737 250659645 735832780 35321360 383752049 203979021 178832532 785212637 514502839 169840231 65809146 504755349 516829442 382478309 901925498 142312128 782336477 741339...

output:


result: