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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#449040#8526. Polygon IIucup-team3215WA 1ms3628kbC++202.6kb2024-06-20 16:21:342024-06-20 16:21:34

Judging History

你现在查看的是最新测评结果

  • [2024-06-20 16:21:34]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3628kb
  • [2024-06-20 16:21:34]
  • 提交

answer

#include <algorithm>
#include <cstdint>
#include <iostream>
#include <vector>

using namespace std;

constexpr int mod = 1e9 + 7, C = 3, N = 1e3 + 1;

using poly = vector<int>;

auto& mul(auto&& a, auto... b) { return ((a = a * (uint64_t)b % mod), ...); }
auto& add(auto&& a, auto... b) { return ((a -= (a += b) >= mod? mod: 0), ...); }
auto& adp(auto&& a, auto b, auto c) { return (a = (a + (uint64_t)b * c) % mod); }
auto& mad(auto&& a, auto b, auto c) { return (a = (a * (uint64_t)b + c) % mod); }
int inv_(int a) { for (int r = 1, b = mod - 2; ; mul(a, a), b /= 2) if (b % 2) mul(r, a); else if (!b) return r; }
poly dif(poly p, poly q) { if (p.size() < q.size()) p.resize(q.size()); for (int i = 0; i < q.size(); ++i) add(p[i], mod - q[i]); return p; }

int eval(const poly& p, int x) {
  int res = 0;
  for (int i = p.size(); i--; ) mad(res, x, p[i]);
  return res;
}

int inv[N];

poly ade(poly p) {
  for (int i = 0; i < p.size(); ++i) mul(p[i], inv[i + 1]);
  p.insert(p.begin(), 0);
  return p;
}

int main() {
  cin.tie(0)->sync_with_stdio(0);
  for (int i = 1; i < N; ++i) inv[i] = inv_(i);
  int n; cin >> n;
  int c0[C]{}, cnt[C]{};
  for (int i = 0, x; i < n; ++i) cin >> x, ++c0[x], cnt[x - !!x] += !!x;
  for (int i = C; --i; ) cnt[i - 1] += cnt[i];
  vector<poly> cont{{1}, {0}};
  for (int i = 1; i < n; ++i) {
    vector<poly> nx;
    poly pp;
    for (int i = 0; auto& p: cont) p = ade(p), nx.push_back(dif(p, dif(pp, {eval(pp, 1)}))), pp = p;
    nx.push_back({0});
    cont = nx;
  }
  vector<int> e(n);
  for (int i = 0; i < n; ++i) e[i] = add(eval(ade(cont[i]), 1), e[i - !!i]);
  int ans = 0;
  for (int c = C; c--; ) if (c0[c]) {
    vector<int> dens{{1}}, ndens;
    int64_t mins = 1 - (1ll << c), maxs = n - 2 + mins, L = 0;
    for (int i = C; i--; ) maxs += 1ll * cnt[i] << i;
    int cans = 0;
    for (int i = C; i--; ) {
      for (auto& x: dens) ndens.push_back(x), ndens.push_back(0);
      swap(dens = {}, ndens);
      dens.pop_back();
      L *= 2;
      for (int j = cnt[i]; j--; ) {
        int64_t l = -(!j && i < c), r = j || i >= c;
        dens.push_back(0);
        for (int pp = 0; auto& p: dens) ndens.push_back(mul(pp + p, mod / 2 + 1)), pp = p;
        maxs -= r << i, mins -= l << i;
        L += l;
        swap(dens = {}, ndens);
        while (-L > maxs >> i) add(cans, dens[0]), dens.erase(dens.begin()), ++L;
        while ((int)dens.size() + L - 1 > -mins >> i) dens.pop_back();
      }
    }
    while (L <= 0) add(cans, mul(+dens[0], e[-L++])), dens.erase(dens.begin());
    add(ans, mul(cans, c0[c]));
  }
  cout << add(1, mod - ans) << '\n';
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3564kb

input:

3
0 2 0

output:

166666668

result:

ok 1 number(s): "166666668"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3628kb

input:

3
0 0 0

output:

500000004

result:

ok 1 number(s): "500000004"

Test #3:

score: -100
Wrong Answer
time: 0ms
memory: 3628kb

input:

3
5 6 7

output:

1

result:

wrong answer 1st numbers differ - expected: '208333335', found: '1'