QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#447428#7627. PhonyRong7WA 1ms4044kbC++143.6kb2024-06-18 14:23:192024-06-18 14:23:22

Judging History

你现在查看的是最新测评结果

  • [2024-06-18 14:23:22]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:4044kb
  • [2024-06-18 14:23:19]
  • 提交

answer

// Not afraid to dark.

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;

clock_t start_time, end_time;
#define GET_START start_time = clock ();
#define GET_END end_time = clock (); fprintf (stderr, "TIME COSSEMED : %0.3lf\n", 1.0 * (end_time - start_time) / CLOCKS_PER_SEC);
#define inline __inline__ __attribute__ ((always_inline))

#define int long long

namespace io {
    int read_pos, read_dt; char read_char;
    inline int read (int &p = read_pos){
        p = 0, read_dt = 1; read_char = getchar ();
        while (! isdigit (read_char)){
            if (read_char == '-')
                read_dt = - 1;
            read_char = getchar ();
        }
        while (isdigit (read_char)){
            p = (p << 1) + (p << 3) + read_char - 48;
            read_char = getchar ();
        }
        return p = p * read_dt;
    }
    int write_sta[65], write_top;
    inline void write (int x){
        if (x < 0)
            putchar ('-'), x = - x;
        write_top = 0;
        do
            write_sta[write_top ++] = x % 10, x /= 10;
        while (x);
        while (write_top)
            putchar (write_sta[-- write_top] + 48);
    }
}

const int N = 5e5;
int n, m, k, a[N + 5], rt[N + 5], dv[N + 5], cnt;

namespace Banlanced_Tree{
    int T;
    tree < pair < int , int > , null_type , greater < pair < int , int > > , rb_tree_tag , tree_order_statistics_node_update > tr;
    inline void Clear (){
        T = 0;
        tr.clear ();
    }
    inline void Insert (int x){
        tr.insert (make_pair (x, T ++));
    }
    inline int Kth (int k){
        if (k < 1 || k > T)
            return - 4e18;
        return (*tr.find_by_order (k - 1)).first;
    }
} using namespace Banlanced_Tree;

inline int MOD (int x){
    return (x % k + k) % k;
}
inline int PAR (int x){
    if (x >= 0)
        return x / k;
    else
        return (x - k + 1) / k;
}

signed main (){
    GET_START

    io::read (n), io::read (m), io::read (k);
    for (int i = 1;i <= n;++ i)
        io::read (a[i]);
    sort (a + 1, a + n + 1, [] (const int &x, const int &y){
        return x > y;
    });
    ++ n;
    a[n] = - 4e18;

    for (int i = 1;i <= n;++ i)
        if (i == n || PAR (a[i + 1]) < PAR (a[i])){
            ++ cnt;
            rt[cnt] = i, dv[cnt] = PAR (a[i]);
        }

    int p = 1, rest = 0;
    for (int i = 1;i <= rt[p];++ i)
        Insert (MOD (a[i]));

    int TT = 0;

    while (m --){
        char opt;
        cin >> opt;
        if (opt == 'A'){
            ++ TT;
            int x = io::read ();
            if (TT == 23 || TT == 22)
                printf ("%lld %lld [%lld %lld] (%lld %lld) : %lld %lld<<<\n", x, rest, rt[p], rt[p + 1], dv[p], dv[p + 1], Kth (x - (rt[p] - rest)) + (dv[p] - 1) * k, Kth (x + rest) + dv[p] * k);
            if (x > rt[p])
                io::write (a[x]), puts ("");
            else
            if (x > rt[p] - rest)
                io::write (Kth (x - (rt[p] - rest)) + (dv[p] - 1) * k), puts ("");
            else
                io::write (Kth (x + rest) + dv[p] * k), puts ("");
        } else {
            int t = io::read () + rest;
            while ((dv[p] - dv[p + 1]) * rt[p] <= t){
                t -= (dv[p] - dv[p + 1]) * rt[p];
                for (int i = rt[p] + 1;i <= rt[p + 1];++ i)
                    Insert (MOD (a[i]));
                ++ p;
            }
            dv[p] -= t / rt[p];
            rest = t % rt[p];
        }
    }

    GET_END
    return 0;
}
/*
3 5 5
7 3 9
A 3
C 1
A 2
C 2
A 3
*/

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 4044kb

input:

3 5 5
7 3 9
A 3
C 1
A 2
C 2
A 3

output:

3
4
-1

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 0ms
memory: 3984kb

input:

5 8 8
294 928 293 392 719
A 4
C 200
A 5
C 10
A 2
C 120
A 1
A 3

output:

294
200
191
0
-2

result:

ok 5 lines

Test #3:

score: -100
Wrong Answer
time: 1ms
memory: 3916kb

input:

100 100 233
5101 8001 6561 6329 6305 7745 4321 811 49 1121 3953 8054 8415 9876 6701 4097 6817 6081 495 5521 2389 2042 4721 8119 7441 7840 8001 5756 5561 129 1 5981 4801 7201 8465 7251 6945 5201 5626 3361 5741 3650 7901 2513 8637 3841 5621 9377 101 3661 5105 4241 5137 7501 5561 3581 4901 561 8721 811...

output:

6881
9161
4721
8200
2945
7647
7531
5291
5001
2042
4721
4721
6881
4097
7187
7218
7035
7018
811
6752
2561
1 9 [35 37] (28 27) : -3999999999999993709 6683<<<
6683
33 33 [37 39] (27 26) : 6103 -3999999999999993709<<<
6103
6135
3581
5291
1485
5957
5393
2042
5303
5171
5205
4721
5084
4029
4097
4591
4816
45...

result:

wrong answer 22nd lines differ - expected: '6683', found: '1 9 [35 37] (28 27) : -3999999999999993709 6683<<<'