#include<iostream>
#include<algorithm>
using namespace std;
#define int long long
const int N = 2e5 + 5, p = 1e9 + 7;
pair<int, int> nums[N], heap[N];
int ans, arr[N], Logarr[N], dLog[N];
bool smaller(pair<int, int> a, pair<int, int> b)
{
double x = log2(nums[a.first].first) + nums[a.first].second;
double y = log2(nums[b.first].first) + nums[b.first].second;
if (x < y) return true; else return false;
}
void heapInsert(int idx)
{
while (idx != 0 && smaller(heap[idx], heap[idx / 2]))
{
pair<int, int> tmp = heap[idx]; heap[idx] = heap[idx / 2];
heap[idx / 2] = tmp; idx = idx / 2;
}
}
void heapify(int idx, int size)
{
int l = 2 * idx;
while (l <= size)
{
int mini = l + 1 <= size && smaller
(heap[l + 1], heap[l]) ? l + 1 : l;
if (smaller(heap[idx], heap[mini])) break;
pair<int, int> tmp = heap[mini]; heap[mini] = heap[idx];
heap[idx] = tmp; idx = mini; l = 2 * idx;
}
}
int power(int a, int b)
{
int tmp = 2, ans = 1;
while (b > 0)
{
if (b % 2) ans = (ans * tmp) % p;
tmp = (tmp * tmp) % p; b /= 2;
}
return (a * ans) % p;
}
signed main()
{
int n, k; cin >> n >> k;
for (int i = 1; i <= n; i++)
{
cin >> nums[i].first;
nums[i].second = 0;
heap[i] = { i, nums[i].first };
heapInsert(i);
}
for (int i = 0; i < k; i++)
{
//时间复杂度O(k*logn),k比较大时无法在时限内得到结果
heap[1].second = (heap[1].second * 2) % p;
nums[heap[1].first].second++; heapify(1, n);
}
for (int i = 1; i <= n; i++)
{
ans += heap[i].second; ans %= p;
}
cout << ans;
return 0;
}