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#447219#8718. 保区间最小值一次回归问题275307894aRE 0ms12144kbC++142.2kb2024-06-18 07:06:142024-06-18 07:06:14

Judging History

你现在查看的是最新测评结果

  • [2024-06-18 07:06:14]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:12144kb
  • [2024-06-18 07:06:14]
  • 提交

answer

#include<bits/stdc++.h>
#define Gc() getchar()
#define Me(x,y) memset(x,y,sizeof(x))
#define Mc(x,y) memcpy(x,y,sizeof(x))
#define d(x,y) ((m)*(x-1)+(y))
#define R(n) (rnd()%(n)+1)
#define Pc(x) putchar(x)
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define eb emplace_back
#define all(x) x.begin(),x.end()
using namespace std;using ll=long long;using db=double;using lb=long db;using ui=unsigned;using ull=unsigned long long;using pii=pair<int,int>;
const int N=5e5+5,M=N*30+5,K=1000+5,mod=998244353,Mod=mod-1;const db eps=1e-9;const ll INF=1e18+7;mt19937 rnd(time(0));
#define Tp template<typename T>
#define Ts template<typename T,typename... Ar>
namespace Debug{
	Tp void _debug(char* f,T t){cerr<<f<<'='<<t<<endl;}
	Ts void _debug(char* f,T x,Ar... y){while(*f!=',') cerr<<*f++;cerr<<'='<<x<<",";_debug(f+1,y...);}
	#ifdef LOCAL
	#define gdb(...) _debug((char*)#__VA_ARGS__,__VA_ARGS__)
	#else 
	#define gdb(...) void()
	#endif
}using namespace Debug;
int n,m,fa[N],A[N];
int GF(int x){return fa[x]^x?fa[x]=GF(fa[x]):x;}
struct ques{int l,r,w;}Q[N];
ll dp[N];
int q[N],head,tail;
void Solve(){
	int i,j;scanf("%d%d",&n,&m);
	for(i=1;i<=n;i++) scanf("%d",&A[i]);
	for(i=1;i<=m;i++) scanf("%d%d%d",&Q[i].l,&Q[i].r,&Q[i].w);
	iota(fa+1,fa+n+2,1);
	sort(Q+1,Q+m+1,[](ques x,ques y){return x.w^y.w?x.w<y.w:x.r<y.r;});
	ll ans=0;
	for(int l=1,r;l<=m;l=r+1){
		for(r=l;Q[r].w==Q[l].w&&r<=m;r++);r--;
		vector<int> st;
		for(int i=l;i<=r;i++){
			int x=Q[i].l;
			while((x=GF(x))<=Q[i].r){
				st.push_back(x);
				fa[x]=x+1;
				if(A[x]<Q[i].w) ans+=Q[i].w-A[x],A[x]=Q[i].w;
			}
		}
		sort(st.begin(),st.end());
		st.push_back(n+1);A[n+1]=Q[l].w;
		q[head=tail=0]=0;dp[0]=0;
		int R=l;
		for(int j:st){
			while(R<=r&&Q[R].r<j){
				while(head<=tail&&q[head]<Q[R].l) head++;
				R++;
			}
			dp[j]=INF;
			if(head<=tail) dp[j]=dp[q[head]]+A[j]-Q[l].w;
			while(head<=tail&&dp[j]<dp[q[tail]]) tail--;
			q[++tail]=dp[j];
			// gdb(Q[i].w,j,dp[j]);
		}
		ans=min(ans+dp[n+1],INF);
	}
	printf("%lld\n",ans==INF?-1ll:ans);
}
int main(){
	int t=1;
	scanf("%d",&t);
	while(t--) Solve();
	cerr<<clock()*1.0/CLOCKS_PER_SEC<<'\n';
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 12144kb

input:

1
3 2
2023 40 41
1 1 2022
2 3 39

output:

2

result:

ok 1 number(s): "2"

Test #2:

score: -100
Runtime Error

input:

1000
100 100
1 35141686 84105222 84105220 7273527 178494861 178494861 112519027 77833654 77833656 261586535 278472336 278472336 261586536 416361017 416361017 426649080 323519513 278472337 420127821 420127823 420127823 482516531 434108818 420127821 631535744 615930922 546346921 546346920 546346920 70...

output:


result: