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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#439788#8770. ComparatorHKOI0#RE 0ms3616kbC++143.2kb2024-06-12 18:02:472024-06-12 18:02:48

Judging History

你现在查看的是最新测评结果

  • [2024-06-12 18:02:48]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:3616kb
  • [2024-06-12 18:02:47]
  • 提交

answer

#include <bits/stdc++.h>
#define all(a) begin(a), end(a)
#define int long long
using namespace std;

int prior(char c){
	if (c == '!') return 4;
	if (c == '=') return 3;
	if (c == '&') return 2;
	if (c == '|') return 1;
	if (c == '^') return 0;
	if (c == '(' || c == ')') return -1;
	return -2;
}

bool is_op(char c){
	return prior(c) > -2;
}

bool calc(char c, bool x, bool y){
	if (c == '=') return x == y;
	if (c == '&') return x & y;
	if (c == '|') return x | y;
	if (c == '^') return x ^ y;
	assert(false); return -1;
}

bool eval(string s, bool x, bool y){
	s = "(" + s + ")";
	vector<bool> val; vector<char> op;
	for (auto c : s) {
		// for (auto x : val) cout << x << ' '; cout << endl;
		// for (auto c : op) cout << c << ' '; cout << endl;
		// cout << "Process " << c << ' ' << is_op(c) << endl;
		if (is_op(c)) {
			if (c == '(') {
				op.push_back('(');
				continue;
			} else if (c == ')') {
				while (!op.empty() && prior(op.back()) > prior(c)) {
					assert(val.size() >= 2);
					bool x = val[val.size() - 2], y = val.back(); val.pop_back();
					val.back() = calc(op.back(), x, y); op.pop_back();
				}
				op.pop_back();
				continue;
			}
			while (!op.empty() && prior(op.back()) > prior(c)) {
				assert(val.size() >= 2);
				bool x = val[val.size() - 2], y = val.back(); val.pop_back();
				val.back() = calc(op.back(), x, y); op.pop_back();
			}
			op.push_back(c);
		} else {
			bool b;
			if (c == 'x' || c == 'y') {
				b = c == 'x' ? x : y;
			} else {
				b = c - '0';
			}
			while (!op.empty() && op.back() == '!') {
				b = !b; op.pop_back();
			}
			val.push_back(b);
		}
	}
	return val[0];
}

struct Comparator{
	int a, b, m, r;

	bool term(int x, int y){
		bool b1 = (x >> a) & 1;
		bool b2 = (y >> b) & 1;
		return (m >> (b1 * 2 + b2)) & 1;
	}
};

int msk[11][11];
bool cmp[1 << 10][1 << 10];
void solve() {
	int n, k; cin >> n >> k;
	vector<Comparator> C;
	for (int i = 0; i < n; i++) {
		int a, b; cin >> a >> b;
		string expr; cin >> expr;
		int m = 0;
		// cout << "*" << '\n';
		for (int i = 0; i < 2; i++) {
			for (int j = 0; j < 2; j++) {
				m += eval(expr, i, j) * (1 << (i * 2 + j));
				// cout << i << ' ' << j << ' ' << eval(expr, i, j) << '\n';
			}
		}
		int r; cin >> r;
		if ((msk[a][b] | m) == msk[a][b]) continue;
		msk[a][b] |= m; C.push_back({a - 1, b - 1, m, r});
	}
	bool lst; cin >> lst;
	
	for (int a = 0; a < (1 << k); a++) {
		for (int b = 0; b < (1 << k); b++) {
			bool done = false;
			for (auto& c : C) {
				if (c.term(a, b)) {
					done = true; cmp[a][b] = c.r;
					break;
				}
			}
			if (!done) cmp[a][b] = lst;
		}
	}

	const int K = 1 << k;
	// for (int i = 0; i < K; i++) {
	// 	for (int j = 0; j < K; j++) {
	// 		cout << cmp[i][j] << ' ';
	// 	}
	// 	cout << '\n';
	// }
	int a1 = 0, a2 = 0, a3 = 0;
	for (int a = 0; a < K; a++) {
		a1 += cmp[a][a];
		for (int b = 0; b < K; b++) {
			if (cmp[a][b] && cmp[b][a]) a2++;
			for (int c = 0; c < K; c++) {
				if (cmp[a][b] && cmp[b][c] && !cmp[a][c])
					a3++;
			}
		}
	}
	cout << a1 << ' ' << a2 << ' ' << a3 << '\n';
}

int32_t main(){
#ifndef LOCAL
	cin.tie(0)->sync_with_stdio(false);
#endif
	int t = 1;
	// cin >> t;
	while (t--) {
		solve();
	}
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3540kb

input:

3 2
1 1 (x=0)&(y=1) 1
1 1 (x=1)&(y=(x^x)) 0
2 2 (x=1)|(y=0) 0
1

output:

0 0 0

result:

ok single line: '0 0 0'

Test #2:

score: 0
Accepted
time: 0ms
memory: 3616kb

input:

4 3
2 1 x=0&(y=1) 1
1 2 !x^!!y 0
2 3 ((x|1)=y)&1&1 1
3 1 !x&!x&!x 0
1

output:

3 25 52

result:

ok single line: '3 25 52'

Test #3:

score: -100
Runtime Error

input:

1413 3
1 3 0 0
3 3 !x 0
2 2 x=0 1
1 2 !y^0 1
2 3 (x^1) 0
3 2 ((!0)) 1
1 1 !!1=(y) 0
2 2 !(1^x)&y 1
3 2 (y)&1|!!1 0
3 1 !x=(y&y=y) 0
2 1 (((!1)^!x)) 1
2 3 !0=(0&y)=1&y 0
1 2 ((((!0)))|!1) 0
3 1 !(y=!1=x|(!x)) 0
1 1 ((((y=!y)))&!0) 0
2 3 ((y=1)^!1^!!1|0) 1
2 3 1|(!x)&!x|1|(x=1) 1
2 3 !0^!!!!y&0=(!1&!0...

output:


result: