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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#439283#8768. Arrested DevelopmentPetroTarnavskyi#RE 0ms0kbC++202.6kb2024-06-11 19:05:492024-06-11 19:05:51

Judging History

你现在查看的是最新测评结果

  • [2024-06-11 19:05:51]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:0kb
  • [2024-06-11 19:05:49]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)
#define SZ(a) int(a.size())
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair
#define F first
#define S second

typedef long long LL;
typedef vector<int> VI;
typedef pair<int, int> PII;
typedef double db;

const int N = 200'447;
const int K = 10;
VI f[N];
string s[N];
int res[N];
int idxA[N];
int idxB[N];
int val[K][K][2][2];

void upd(int& a, int b)
{
	a = min(a, b);
}

bool g(bool x, bool y, char c)
{
	if (c == '=')
		return x == y;
	if (c == '&')
		return x && y;
	if (c == '|')
		return x || y;
	return x ^ y;
}

bool eval(int i, int l, int r, bool x, bool y)
{
	//cerr << s[i] << ' ' << l << ' ' << r << '\n';
	bool nt = false;
	VI v;
	string op = "";
	FOR (j, l, r)
	{
		if (s[i][j] == '!')
			nt ^= 1;
		else if (s[i][j] == '(')
		{
			v.PB(eval(i, j + 1, f[i][j], x, y) ^ nt);
			nt = 0;
			j = f[i][j];
		}
		else if (s[i][j] == 'x')
		{
			v.PB(x ^ nt);
			nt = 0;
		}
		else if (s[i][j] == 'y')
		{
			v.PB(y ^ nt);
			nt = 0;
		}
		else if (s[i][j] == '0' || s[i][j] == '1')
		{
			v.PB(s[i][j] - '0');
		}
		else
		{
			//cerr << s[i][j] << '\n';
			assert(s[i][j] == '=' || s[i][j] == '&' || s[i][j] == '|' || s[i][j] == '^');
			op += s[i][j];
		}
	}
	string all = "=&|^";
	FOR (t, 0, 4)
	{
		int last = v[0];
		VI v2;
		string op2 = "";
		FOR (j, 0, SZ(op))
		{
			if (op[j] == all[t])
			{
				last = g(last, v[j + 1], op[j]);
			}
			else
			{
				v2.PB(last);
				op2 += op[j];
				last = v[j + 1];
			}
		}
		v2.PB(last);
		v = v2;
		op = op2;
	}
	//cerr << SZ(v) << ' ' << SZ(op) << '\n';
	assert(SZ(v) == 1);
	return v[0];
} 

int main()
{
	ios::sync_with_stdio(0);
	cin.tie(0);
	
	int n, k;
	cin >> n >> k;
	FOR (i, 0, k) FOR (j, 0, k) FOR (vi, 0, 2) FOR (vj, 0, 2) val[i][j][vi][vj] = n;
	FOR (i, 0, n)
	{
		cin >> idxA[i] >> idxB[i];
		idxA[i]--;
		idxB[i]--;
		cin >> s[i];
		f[i].resize(SZ(s[i]));
		VI st;
		FOR (j, 0, SZ(s[i]))
		{
			if (s[i][j] == '(')
				st.PB(j);
			else if (s[i][j] == ')')
			{
				f[i][st.back()] = j;
				st.pop_back();
			}
		}
		FOR (vi, 0, 2)
		{
			FOR (vj, 0, 2)
			{
				if (eval(i, 0, SZ(s[i]), vi, vj))
					upd(val[idxA[i]][idxB[i]][vi][vj], i);
			}
		}
		cin >> res[i];
	}
	cin >> res[n];
	
	//FOR (i, 0, k) FOR (j, 0, k) FOR (vi, 0, 2) FOR (vj, 0, 2) 
	//	cerr << i << ' ' << j << ' ' << vi << ' ' << vj << ' ' << val[i][j][vi][vj] << '\n';
	
	
	return 0;
}

Details

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Test #1:

score: 0
Runtime Error

input:

4
100 1
1 90
1 20
1 20

output:


result: