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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#438292#8718. 保区间最小值一次回归问题as_lyrWA 465ms23704kbC++142.1kb2024-06-10 15:11:592024-06-10 15:11:59

Judging History

你现在查看的是最新测评结果

  • [2024-06-10 15:11:59]
  • 评测
  • 测评结果:WA
  • 用时:465ms
  • 内存:23704kb
  • [2024-06-10 15:11:59]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N=510000;
const ll INF=1e18;
int n,m;
int a[N];
ll sum[N];
struct node{
	int l,r,x;
}b[N];
int f[N];
int find(int x){
	return f[x]==x?x:f[x]=find(f[x]);
}
int g[N];
inline int as(int x){
	return x<0?-x:x;
}
ll dp[N];
void solve(){
	scanf("%d%d",&n,&m);
	for(int i=1;i<=n;i++)
		scanf("%d",&a[i]);
	for(int i=1;i<=m;i++)
		scanf("%d%d%d",&b[i].l,&b[i].r,&b[i].x);
	sort(b+1,b+m+1,[](const node x,const node y){
		return x.x>y.x;
	});
	for(int i=1;i<=n+1;i++)
		f[i]=i;
	ll ans=0;
	for(int i=1,j;i<=m;i=j+1){
		j=i;
		while(j<m&&b[i].x==b[j+1].x)
			j++;
		vector <int> v;
		for(int k=i;k<=j;k++)
			for(int x=find(b[k].l);x<=b[k].r;x=find(x+1)){
				v.push_back(x);
				f[x]=x+1;
			}
		sort(v.begin(),v.end());
		sort(b+i,b+j+1,[](const node x,const node y){
			return x.r<y.r;
		});
		if(v.empty()){
			puts("-1");
			return ;
		}
		for(int k=i;k<=j;k++)
			if(lower_bound(v.begin(),v.end(),b[k].l)==upper_bound(v.begin(),v.end(),b[k].r)){
				puts("-1");
				return ;
			}
		for(int k=0;k<(int)v.size();k++)
			g[k]=0;
		for(int k=i;k<=j;k++){
			int x=lower_bound(v.begin(),v.end(),b[k].l)-v.begin();
			int y=upper_bound(v.begin(),v.end(),b[k].r)-v.begin()-1;
			g[y]=max(g[y],x);
		}
		for(int k=1;k<(int)v.size();k++)
			g[k]=max(g[k],g[k-1]);
		deque <pair<int,int>> q;
		q.push_back(make_pair(-1,0));
		sum[0]=(a[v[0]]<b[i].x?b[i].x-a[v[0]]:0);
		for(int k=1;k<(int)v.size();k++)
			sum[k]=sum[k-1]+(a[v[k]]<b[i].x?b[i].x-a[v[k]]:0);
		for(int k=0;k<(int)v.size();k++){
			if(q.empty()==0&&q.front().first<g[k]-1)
				q.pop_front();
			dp[k]=q.front().second+sum[k-1]+as(a[v[k]]-b[i].x);
			while(q.empty()==0&&q.back().second>=dp[k]-sum[k])
				q.pop_back();
			q.push_back(make_pair(k,dp[k]-sum[k]));
		}
		ll res=INF;
		for(int k=g[(int)v.size()-1];k<(int)v.size();k++)
			res=min(res,dp[k]+sum[(int)v.size()-1]-sum[k]);
		ans+=res;
	}
	printf("%lld\n",ans);
}
int main(){
	int T;
	scanf("%d",&T);
	while(T--)
		solve();
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 2ms
memory: 14008kb

input:

1
3 2
2023 40 41
1 1 2022
2 3 39

output:

2

result:

ok 1 number(s): "2"

Test #2:

score: -100
Wrong Answer
time: 465ms
memory: 23704kb

input:

1000
100 100
1 35141686 84105222 84105220 7273527 178494861 178494861 112519027 77833654 77833656 261586535 278472336 278472336 261586536 416361017 416361017 426649080 323519513 278472337 420127821 420127823 420127823 482516531 434108818 420127821 631535744 615930922 546346921 546346920 546346920 70...

output:

49
43
43
39
51
47
50
46
46
50
45
57
953
54
52
56
48
61
53
47
50
53
41
56
51
57
49
44
40
45
40
50
56
43
58
44
45
42
37
49
45
51
43
50
915
939
49
51
52
49
46
43
55
50
44
46
51
52
49
46
38
47
45
42
55
41
48
48
40
49
51
46
44
47
46
48
43
47
39
45
45
35
41
47
52
47
49
44
43
46
50
39
47
53
45
41
45
48
47
...

result:

wrong answer 2nd numbers differ - expected: '46', found: '43'