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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#436383#8782. Schoolgirlsucup-team1198#WA 4ms3824kbC++204.1kb2024-06-09 00:23:152024-06-09 00:23:15

Judging History

你现在查看的是最新测评结果

  • [2024-06-14 13:48:47]
  • hack成功,自动添加数据
  • (/hack/679)
  • [2024-06-14 13:05:18]
  • hack成功,自动添加数据
  • (/hack/678)
  • [2024-06-14 12:22:35]
  • hack成功,自动添加数据
  • (/hack/676)
  • [2024-06-09 00:23:15]
  • 评测
  • 测评结果:WA
  • 用时:4ms
  • 内存:3824kb
  • [2024-06-09 00:23:15]
  • 提交

answer

#include <map>
#include <set>
#include <array>
#include <cmath>
#include <deque>
#include <bitset>
#include <random>
#include <string>
#include <vector>
#include <cassert>
#include <complex>
#include <iomanip>
#include <iostream>
#include <algorithm>
#include <unordered_map>
#include <unordered_set>

using namespace std;

const int HMOD = 998244353;

int rnd(int x) {
  return (1ll * x * x) % HMOD;
}

int P;

int reduce(int x) {
  if (x >= P) return x - P;
  return x;
}

int norm(int x) {
  if (x < 0) return x + P;
  return x;
}

int add(int a, int b) {
  return norm(a - P + b); 
}

int sub(int a, int b) {
  return norm(a - b);
}

int mul(int a, int b) {
  return (1ll * a * b) % P;
}

int pw(int x, int n) {
  int res = 1;
  while (n) {
    if (n % 2 == 0) {
      x = mul(x, x);
      n /= 2;
    } else {
      res = mul(res, x);
      --n;
    }
  }
  return res;
}

int XI;

vector<int> operator+(vector<int> a, const vector<int>& b) {
  for (int i = 0; i < (int)a.size(); ++i) {
    a[i] = add(a[i], b[i]);
  }
  return a;
}

vector<int> operator-(vector<int> a, const vector<int>& b) {
  for (int i = 0; i < (int)a.size(); ++i) {
    a[i] = sub(a[i], b[i]);
  }
  return a;
}

vector<int> operator*(vector<int> a, const vector<int>& b) {
  for (int i = 0; i < (int)a.size(); ++i) {
    a[i] = mul(a[i], b[i]);
  }
  return a;
}

vector<int> operator*(vector<int> a, int n) {
  for (int& x : a) {
    x = mul(n, x);
  }
  return a;
}

const int MAXN = 4e4 + 100;
vector<int> coord[MAXN];

const int B = 5757, HMOD2 = 1e9 + 1000 - 7;

int hsh(const vector<int>& a) {
  int res = 0;
  for (int x : a) {
    res = (1ll * res * B + x) % HMOD2;
  }
  return rnd(res);
}


int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);

  int n;
  cin >> n;
  for (int i = (HMOD2 + n - 1) / n * n + 1;; i += n) {
    bool f = true;
    for (int x = 2; x * x <= i && f; ++x) {
      f &= (i % x != 0);
    }
    if (f) {
      P = i;
      break;
    }
  }
  /// cerr << P << endl;
  /// P is a prime, n | (P - 1)
  int p1 = P - 1;
  vector<int> prm;
  for (int i = 2; i * i <= p1; ++i) {
    if (p1 % i == 0) {
      prm.push_back(i);
      while (p1 % i == 0) p1 /= i;
    }
  }
  if (p1 != 1) {
    prm.push_back(p1);
  }
  for (int g = 2;; ++g) {
    bool f = true;
    for (int q : prm) {
      if (pw(g, (P - 1) / q) == 1) {
        f = false;
        break;
      }
    }
    if (f) {
      XI = pw(g, (P - 1) / n); /// nth root of unity
      break;
    }
  }

  vector<int> x(n);
  x[0] = 1;
  for (int i = 1; i < n; ++i) {
    x[i] = mul(x[i - 1], XI);
  }
  coord[0] = vector<int>(n, 1);
  for (int i = 1; i < n; ++i) {
    coord[i] = coord[i - 1] * x;
  }

  int m, k;
  cin >> m >> k;
  for (int i = 0; i < m; ++i) {
    int a, b, c;
    cin >> a >> b >> c;
    --a; --b; --c;
    coord[i + n] = coord[a] + coord[c] - coord[b];
  }

  while (k--) {
    int r;
    cin >> r;
    vector<int> pos(r);
    vector<int> sum(n, 0);
    for (int i = 0; i < r; ++i) {
      cin >> pos[i];
      --pos[i];
      sum = sum + coord[pos[i]];
    }
    vector<int> cur_rot;
    if (n % r == 0) {
      cur_rot = coord[n / r];
    } else if (n % 2 == 1 && (2 * n) % r == 0) {
      cur_rot = vector<int>(n, 0) - coord[(n + 1) / 2];
      int val = 2 * n / r;
      val = (val - 1) / 2;
      cur_rot = cur_rot * coord[val];
    } else {
      cout << "No\n";
      /// cout << "here" << "\n";
      continue;
    }
    int check = 0, rot = 0;
    for (int i = 0; i < r; ++i) {
      vector<int> cur = (coord[pos[i]] * r - sum);
      /**for (int x : cur) {
        cerr << x << " ";
      }
      cerr << endl;
      cerr << "->\n";*/
      check = (check + hsh(cur)) % HMOD;
      cur = cur * cur_rot;
      /**for (int x : cur) {
        cerr << x << " ";
      }
      cerr << "\n---\n";*/
      rot = (rot + hsh(cur)) % HMOD;
    }
    if (check == rot) {
      cout << "Yes\n";
    } else {
      cout << "No\n";
    }
  }

  
  return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3824kb

input:

3 6 8
1 2 3
3 1 4
5 4 3
3 1 2
4 5 3
4 5 2
6 4 7 6 5 1 2
3 1 3 2
3 1 1 8
4 2 5 6 7
3 2 1 4
3 6 5 9
3 4 7 9
4 1 3 2 8

output:

Yes
Yes
Yes
No
No
No
Yes
No

result:

ok 8 token(s): yes count is 4, no count is 4

Test #2:

score: 0
Accepted
time: 1ms
memory: 3624kb

input:

12 0 1
12 12 11 10 9 8 7 6 5 4 3 2 1

output:

Yes

result:

ok YES

Test #3:

score: -100
Wrong Answer
time: 4ms
memory: 3564kb

input:

3 0 6685
5 1 3 1 2 2
3 1 2 3
5 3 1 3 3 1
4 1 1 1 3
3 3 2 1
5 2 3 2 1 3
6 2 2 3 2 3 1
5 3 1 2 3 2
3 3 3 2
5 3 2 2 2 3
5 2 2 3 3 1
6 3 3 1 3 1 3
6 2 3 3 2 2 1
5 2 2 3 2 2
6 2 3 3 2 1 3
6 2 2 2 2 1 3
3 3 1 2
4 3 2 1 1
5 3 1 3 2 3
4 3 1 1 2
4 2 2 2 3
3 1 2 2
4 2 3 3 1
3 2 2 2
4 1 2 2 3
3 3 3 3
4 1 3 1 3...

output:

No
Yes
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
Yes
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
Yes
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
N...

result:

wrong answer expected YES, found NO [107th token]