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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#436195#8782. SchoolgirlsForever_Young#WA 56ms18540kbC++174.0kb2024-06-08 23:36:362024-06-08 23:36:36

Judging History

你现在查看的是最新测评结果

  • [2024-06-14 13:48:47]
  • hack成功,自动添加数据
  • (/hack/679)
  • [2024-06-14 13:05:18]
  • hack成功,自动添加数据
  • (/hack/678)
  • [2024-06-14 12:22:35]
  • hack成功,自动添加数据
  • (/hack/676)
  • [2024-06-08 23:36:36]
  • 评测
  • 测评结果:WA
  • 用时:56ms
  • 内存:18540kb
  • [2024-06-08 23:36:36]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
#define pb push_back
#define all(x) ((x).begin()), ((x).end())
typedef long long LL;
inline LL fastpo(LL x, LL n, LL mod) {
    LL res(1);
    while(n) {
        if(n & 1) {
            res = res * (LL)x % mod;
        }
        x = x * (LL) x % mod;
        n /= 2;
    }
    return res;
}
const int inf = 1e9 + 7;
const int L = 9999999;
const int N = 10000111;
bool f[N];
int np = 0;
int p[N / 10];
const int M = 53333;
int a[M], b[M], c[M], h[M];
bool answer[M];
vector<int> q[M];
int powmod (int a, int b, int p) {
    int res = 1;
    while (b)
        if (b & 1)
            res = int (res * 1ll * a % p),  --b;
        else
            a = int (a * 1ll * a % p),  b >>= 1;
    return res;
}

int findpr (int p) {
    vector<int> fact;
    int phi = p-1,  n = phi;
    for (int i=2; i*i<=n; ++i)
        if (n % i == 0) {
            fact.push_back (i);
            while (n % i == 0)
                n /= i;
        }
    if (n > 1)
        fact.push_back (n);

    for (int res=2; res<=p; ++res) {
        bool ok = true;
        for (size_t i=0; i<fact.size() && ok; ++i)
            ok &= powmod (res, phi / fact[i], p) != 1;
        if (ok)  return res;
    }
    return -1;
}
int main() {
    fill(f + 2, f + L + 1, true);
    p[0] = inf;
    for(int i = 2; i <= L; i++) {
        if(f[i]) {
             p[++np] = i;
        }
        for(int j = 1; j <= np && p[j] * i <= L && i % p[j - 1]; j++) {
            f[i * p[j]] = 0;
        }
    }
    int n, m, k;
    scanf("%d%d%d", &n, &m, &k);
    for(int i = 1; i <= m; i++) {
        scanf("%d%d%d", &a[i], &b[i], &c[i]);
    }
    for(int i = 1; i <= k; i++) {
        int r;
        scanf("%d", &r);
        for(int j = 0; j < r; j++) {
            int x;
            scanf("%d", &x);
            q[i].pb(x);
        }
        answer[i] = true;
    }
    int mod = -1;
    
    int cc = 0;
    for(int i = 1; i * n + 1 <= L; i++) {
        if(i * n + 1 >= 10000 && f[i * n + 1]) {
            mod = i * n + 1;
        } else {
            continue;
        }
        cc++;
        if(cc == 11) {
            break;
        }
        int pr = findpr(mod);
        // printf("%d %d\n", pr, mod);
        for(int i = 1; i <= 1; i++) {
            
            int pp = fastpo(pr, i, mod);
            int g = fastpo(pp, (mod - 1) / n, mod);
            // printf("g = %d %d\n", g, fastpo(g, n, mod));
            for(int i = 1; i <= n; i++) {
                h[i] = i == 1 ? 1 : (LL)h[i - 1] * g % mod;
            }
            for(int j = 1; j <= m; j++) {
                h[n + j] = ((LL)h[c[j]] + h[a[j]] - h[b[j]] + mod) % mod;
            }
            // for(int i = 1; i <= n + m; i++) {
            //     printf("%d ", h[i]);
            // }
            // printf("\n");
            for(int j = 1; j <= k; j++) {
                int r = q[j].size();
                set<int> st;
                int sum = 0;
                vector<int> xs;
                // printf("j = %d\n", j);
                for(int id : q[j]) {
                    int x = h[id];
                    xs.pb(x);
                    sum = (sum + x) % mod;
                    // if(j == 3) {
                    //     printf("%d %d %d\n", id, x, int((LL)x * g % mod));
                    // }
                }
                sum = (LL)sum * fastpo(r, mod - 2, mod) % mod;
                for(int x : xs) {
                    st.insert((x - sum + mod) % mod);
                }
                bool flag = true;
                for(int x : xs) {
                    int y = (LL)(x - sum + mod) * g % mod;
                    if(st.count(y) == 0) {
                        flag = false;
                        break;
                    }
                }
                if(!flag) {
                    answer[j] = false;
                }
            }
        }
    }

    
    for(int i = 1; i <= k; i++) {
        printf("%s\n", answer[i] ? "Yes" : "No");
    }
}

Details

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Test #1:

score: 100
Accepted
time: 42ms
memory: 17824kb

input:

3 6 8
1 2 3
3 1 4
5 4 3
3 1 2
4 5 3
4 5 2
6 4 7 6 5 1 2
3 1 3 2
3 1 1 8
4 2 5 6 7
3 2 1 4
3 6 5 9
3 4 7 9
4 1 3 2 8

output:

Yes
Yes
Yes
No
No
No
Yes
No

result:

ok 8 token(s): yes count is 4, no count is 4

Test #2:

score: 0
Accepted
time: 34ms
memory: 18492kb

input:

12 0 1
12 12 11 10 9 8 7 6 5 4 3 2 1

output:

Yes

result:

ok YES

Test #3:

score: -100
Wrong Answer
time: 56ms
memory: 18540kb

input:

3 0 6685
5 1 3 1 2 2
3 1 2 3
5 3 1 3 3 1
4 1 1 1 3
3 3 2 1
5 2 3 2 1 3
6 2 2 3 2 3 1
5 3 1 2 3 2
3 3 3 2
5 3 2 2 2 3
5 2 2 3 3 1
6 3 3 1 3 1 3
6 2 3 3 2 2 1
5 2 2 3 2 2
6 2 3 3 2 1 3
6 2 2 2 2 1 3
3 3 1 2
4 3 2 1 1
5 3 1 3 2 3
4 3 1 1 2
4 2 2 2 3
3 1 2 2
4 2 3 3 1
3 2 2 2
4 1 2 2 3
3 3 3 3
4 1 3 1 3...

output:

No
Yes
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
Yes
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
Yes
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
N...

result:

wrong answer expected NO, found YES [108th token]